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NCERT Exemplar · Class 8 · Maths

Chapter 2: Data Handling

Practice each question, then open the answer or worked solution.

Some questions are missing from the current source. Exercise · Page 42: questions 88 missing from source

Exercise · Page 42

Textbook page 42 · 115 questions
Q112Written answer

Sonia picks up a card from the given cards.

NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 40

Calculate the probability of getting

(a) an odd number

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Worked solution

Solution:-

Total number of odd numbers in given cards = 5

Total number of cards = 10

Probability of getting an odd number = Total number of odd numbers/ total number of

cards

= 5/10

= ½

(b) a Y card

Solution:-

Total number of y cards = 3

Total number of cards = 10

Probability of getting a Y card = Total number of Y cards/ total number of cards

= 3/10

 

(c) a G card

Total number of G cards = 2

Total number of cards = 10

Probability of getting a Y card = Total number of Y cards/ total number of cards

= 2/10

= 1/5

(d) B card bearing number > 7

Total number B card bearing number > 7= 0

Total number of cards = 10

Probability of getting a Y card = Total number B card bearing number > 7/ total number

of cards

= 0/10

= 0

Q113Written answer

Identify which symbol should appear in each sector in 113, 114.

NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 41

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Worked solution

Solution:-

From the given figure,

Total number of symbol = 800 + 700 + 550 + 450 = 2500

Then,

(i) = (32/100) × 2500

NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 42

Q114Written answer

NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 43

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Worked solution

Solution:-

From the given figure,

Total number of ice-creams = 192 + 228 + 180 = 600

Then,

(i) = (38/100) × 600

= 228

∴
NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 44yellow colour ice cream should appear in sector having 38%.

(ii) = (32/100) × 600

= 192

∴
NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 45red colour ice cream should appear in sector having 32%.

(iii) = (30/100) × 600

= 180

∴
NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 46pink colour ice cream should appear in sector having 30%.

Q115Written answer

A financial counsellor gave a client this pie chart describing how to budget his income. If the client brings home Rs. 50,000 each month, how much should he spend in each category?

NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 47

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Worked solution

Solution:-

From the question it is given that,

Total money spent on 7 categories = Rs. 50,000

Then,

(1) Money spent on Housing = (30/100) × 50,000

= Rs. 15,000

(2) Money spent on Food (including eating out) = (20/100) × 50,000

= Rs. 10,000

(3) Money spent on Car Loan and Maintenance = (25/100) × 50,000

= Rs. 12,500

(4) Money spent on Utilities = (10/100) × 50,000

= Rs. 5,000

(5) Money spent on Phone = (5/100) × 50,000

= Rs. 2,500

(6) Money spent on Clothing = (5/100) × 50,000

= Rs. 2,500

(7) Money spent on Entertainment = (5/100) × 50,000

= Rs. 2,500

Q116Written answer

Following is a pie chart showing the amount spent in rupees (in thousands) by a company on various modes of advertising for a product.

NCERT Exemplars Class 8 Maths Solutions Chapter 2 Image 48

Now answer the following questions.

1. Which type of media advertising is the greatest amount of the total?

2. Which type of media advertising is the least amount of the total?

3. What per cent of the total advertising amount is spent on direct mail campaigns?

4. What per cent of the advertising amount is spent on newspaper and magazine advertisements?

5. What media types do you think are included in miscellaneous?

Why aren’t those media types given their own category?

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Worked solution

Solution:-

From the given figure,

The type of media advertising is the greatest amount of the total is Newspaper.

Solution:-

From the given figure,

The type of media advertising is the least amount of the total is Radio.

Solution:-

From the given figure,

Total amount spent by a company on various modes of advertising for a product,

= 40 + 42 + 23 + 7 + 11 + 39 + 14 + 15 + 9

= Rs. 200

Then,

Per cent of the total advertising amount is spent on direct mail campaigns

= (39/200) × 100

= 19.5%

Solution:-

From the given figure,

Total amount spent by a company on various modes of advertising for a product,

= 40 + 42 + 23 + 7 + 11 + 39 + 14 + 15 + 9

= Rs. 200

Then,

Per cent of the total advertising amount is spent on newspaper and magazine

= ((42 + 23)/200) × 100

= (65/200) × 100

= 32.5%

Solution:-

Internet and web media are included in miscellaneous.