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NCERT Exemplar · Class 11 · Physics

Chapter 8: Gravitation

Practice each question, then open the answer or worked solution.

Questions

38 questions
Q8.21Written answer

How is the gravitational force between two point masses affected when they are dipped in the water keeping the separation between them the same?

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Worked solution

The gravitational force is unaffected by the medium, and it remains the same between the point masses irrespective of their surrounding. Therefore, when the two-point masses are dipped in water, the gravitational force between them remains the same.

Q8.22Written answer

Is it possible for a body to have inertia but no weight?

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Worked solution

Yes, it is possible for a body to have inertia, but no weight, as inertia is associated with the mass of the body. A satellite revolving around the earth is an example of a body with inertia and has no weight.

Exemplar Solutions Physics Class 11 Chapter 8 - 4

Q8.23Written answer

We can shield a charge from electric fields by putting it side a hollow conductor. Can we shield a body from the gravitational influence of nearby matter by putting it inside a hollow sphere or by some other means?

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Worked solution

No, it is possible to shield a body from the gravitational influence of nearby matter by putting it inside a hollow sphere as gravitation is independent of the medium.

Q8.24Written answer

An astronaut inside a small spaceship orbiting around the earth cannot detect gravity. If the space station orbiting around the earth has a large size, can he hope to detect gravity?

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Worked solution

When the size of the space station orbiting around the earth is large, the astronaut will experience variation and this is because of acceleration due to gravity.

Q8.25Written answer

The gravitational force between a hollow spherical shell and a point mass is F. Show the nature of F vs r graph where r is the distance of the point from the centre of the hollow spherical shell of uniform density.

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Worked solution

R is the radius of the spherical shell and r is the distance between m and M. M is the mass of the hollow spherical shell and m is the mass of the point. We know that,

F = GMm/r2

When the F = 0, F = GM/r2 for r ≥ R

Exemplar Solutions Physics Class 11 Chapter 8 - 5

Below is the graph which shows the variation of F versus r such that when force is maximum, r tends to infinity.

Exemplar Solutions Physics Class 11 Chapter 8 - 6

Q8.26Written answer

Out of aphelion and perihelion, where is the speed of the earth more and why?

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Worked solution

According to Kepler’s second law, a real velocity is constant and is given as:

rp × vp = rA × vA

rA/rp = vp/vA

rA > rp and vp > vA

Exemplar Solutions Physics Class 11 Chapter 8 - 7

Q8.27Written answer

What is the angle between the equatorial plane and the orbital plane of

a) polar satellite?

b) geostationary satellite?

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Worked solution

a) The angle between the equatorial plane and the orbital plane of the polar satellite is 90o

b) The angle between the equatorial plane and the orbital plane of a geostationary satellite is 0o

Exemplar Solutions Physics Class 11 Chapter 8 - 8

Short Answer
Q8.28Written answer

Mean solar day is the time interval between two successive noon when the sun passes through the zenith point. The sidereal day is the time interval between two successive transits of a distant star through the zenith point. Drawing the appropriate diagram showing earth’s spin and orbital motion, show that the mean solar day is four minutes longer than the sidereal day. In other words, distant stars would rise 4 minutes early every successive day.

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Worked solution

E and E’ is the polar axis of the earth and its movement.

P’ is the translational motion

In every 24 hours, the orbit of the earth is approximately advanced by 1o

Therefore, time taken for transverse is = (24/360o) (1o) = 239.3 sec = 4 minutes.

Exemplar Solutions Physics Class 11 Chapter 8 - 9

Q8.29Written answer

Two identical heavy spheres are separated by a distance 10 times their radius. Will an object placed at the midpoint of the line joining their centres be in a stable equilibrium or unstable equilibrium? Give a reason for your answer.

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Worked solution

M is the mass of the spheres and R is the radius of the spheres.

P is the midpoint of A and B.

The magnitude of the force is given as:

F1 = F2 = GMm/(5R)2

The equilibrium will be unstable as the resultant force acting on the object moves towards sphere A.

Exemplar Solutions Physics Class 11 Chapter 8 - 10

Q8.30Written answer

Show the nature of the following graph for a satellite orbiting the earth.

a) KE vs orbital radius R

b) PE vs orbital radius R

c) TE vs orbital radius R

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Worked solution

Exemplar Solutions Physics Class 11 Chapter 8 - 11

a) K = 1/2mv2 = (1/2 m)(GM/R)

b) PE of satellite is U = -GMm/R = -2K

Exemplar Solutions Physics Class 11 Chapter 8 - 12

c) Total energy of the satellite = -GMm/2R