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NCERT Exemplar · Class 9 · Science

Chapter 3: Atoms and Molecules

Practice each question, then open the answer or worked solution.

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13 questions
Q31Written answer

Raunak took 5 moles of carbon atoms in a container and Krish also took 5 moles of sodium atoms in another container of same weight.

(a) Whose container is heavier?

(b) Whose container has more number of atoms?

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Worked solution

a) Mass of sodium atoms carried by Krish = (5 ×23) g = 115 g

The atomic weight of Na = 23

While the mass of carbon atom carried by Raunak = (5 ×12) g = 60g

b) Both container has an equal number of atoms

Q32Written answer

Fill in the missing data in the Table 3.1

Species property H2O CO2 Na atom MgCl2
No of Moles 2 – – 0.5
No of particles – 3.011×1023 – 0
Mass 36g – 115g 0
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Worked solution
Species property H2O CO2 Na atom MgCl2
No of Moles 2 0.5 5 0.5
No of particles 12.044×1023 3.011×1023 3.011×1023 3.011×1023
Mass 36g 22g 115g 47.5g
Q33Written answer

The visible universe is estimated to contain 1022 stars. How many moles are present in the visible universe?

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Worked solution

Number of moles of stars = 1022 / 6.023 × 1023

Number of moles of stars = 0.0166

Q34Written answer

What is the SI prefix for each of the following multiples and submultiples of a unit?

(a) 103

(b) 10–1

(c) 10–2

(d) 10–6

(e) 10–9

(f) 10–12

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Worked solution

a) 103 = 1000= kilo

(b) 10–1 =1/10= 0.1= deci

(c) 10–2 =1/100 = 0.01= centi

(d) 10–6 = 0.000 001= micro

(e) 10–9 =0.000 000 001 = nano

(f) 10–12 =0.000 000 000 001 = pico

Q35Written answer

Express each of the following in kilograms

(a) 5.84×10-3 mg

(b) 58.34 g

(c) 0.584g

(d) 5.873×10-21g

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Worked solution

(a) 5.84 × 10–3 mg = 5.84 ×10–9 kg

(b) 58.34 g =5.834 ×10–2 kg

(c) 0.584g =5.84 ×10–4 kg

(d) 5.873×10-21g=5.873 ×10–24 kg

Q36Written answer

Compute the difference in masses of 103 moles each of magnesium atoms and magnesium ions. (Mass of an electron = 9.1×10–31 kg)

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Worked solution

Mg2+ ion and Mg atom differ by two electrons.

103 moles of Mg2+ and Mg atoms would differ by

103 × 2 moles of electrons

Mass of 2 ×103 moles of electrons = 2×103 × 6.023 ×1023 × 9.1 ×10–31 kg

2×6.022 × 9.1×10–5kg

109.6004 ×10–5 kg

1.096 × 10–3kg

Q37Written answer

Which has more number of atoms? 100g of N2 or 100 g of NH3

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Worked solution

No. of moles of atoms = weight / atomic weight.

For N2

100 gms of N2 = 100/2 x 14 moles = 100/28 moles

Number of molecules = 100 / 28 x 6.022 x 10²³

Molar mass of N2 = 2 x molar mass of monoatomic  N

Molar mass of N2 = 2 x 14.0067 = 28 moles.

Number of molecules = 100/28 x 6.022 x 10²³

No. of atoms = 2 x 100/28 x 6.022 x 10²³ = 43.01 x 10²³

For NH3

100 gm of NH3 = 100/17 moles

Number of molecules = 100/17 x 6.022 x 10²³ molecules

No. of atoms in NH3 = (1 + 3) = 4 x 100/17 x 6.022 x 10²³ =

141.69 x 10²³ atoms.

Therefore, NH3 has more atoms than N2.

Q38Written answer

Compute the number of ions present in 5.85 g of sodium chloride.

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Worked solution

58.5 g NaCl contains 6.023 x 1023 molecules

therefore 58.5 g NaCl contains 12.046 x 1023 ions.

Hence, 5.85 g NaCl contains 5.85 x 12.046 x 1023/ 58.5

= 1.2046 x 1023 ions

Q39Written answer

A gold sample of gold and the rest copper. How many atoms of gold are present in one gram of this sample of gold ?

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Worked solution

one gram of gold sample will contain 90/100 = 0.9g of gold

number of moles of gold = mass of gold / atomic mass of gold

= 0.9/19.7 = 0.0046

one mole of gold contains NA atoms = 6.022 × 1023

Therefore, 0.0046 mole of gold will contain = 0.0046 × 6.022

= 2.77 × 1021

Q40Written answer

What are ionic and molecular compounds? Give examples.

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Worked solution

While forming some compounds, atoms gain or lose electrons, and form electrically charged particles called ions. Compounds that are formed by the attraction of cations and anions are called as ionic compounds.

Ex : 2Na + Cl2 → 2Na+ Cl- → 2NaCl (sodium chloride- common salt.)

Sodium is a group 1 metal, thus forms a +1 charged cation. Chlorine is a non-metal, and has the ability to form a -1 charged anion.

Compounds formed due to bonding of uncharged ions are called as molecular compounds and the bonding between them is called covalent bonding. Molecular compounds are formed by sharing of electrons between the two atoms and the elements are held together by covalent bonds.

Ex: 2C + O2 → 2CO ( Carbon monoxide)