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NCERT Exemplar · Class 9 · Maths

Chapter 4: Linear Equations in Two Variables

Practice each question, then open the answer or worked solution.

Exercise 4.1

Textbook page 34 · 9 questions
Q1Written answer

The linear equation 2x – 5y = 7 has

A. A unique solution
B. Two solutions
C. Infinitely many solutions
D. No solution

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Worked solution

C. Infinitely many solutions

Explanation:

Expressing y in terms of x in the equation 2x – 5y = 7, we get,

2x – 5y = 7

– 5y = 7 – 2x

y = ( 7 – 2x)/– 5

Hence, we can conclude that the value of y will be different for different values of x.

Hence, option C is the correct answer.

Q2Written answer

The equation 2x + 5y = 7 has a unique solution, if x, y are:

A. Natural numbers

B. Positive real numbers

C. Real numbers

D. Rational numbers

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Worked solution

A. Natural numbers

Explanation:

Consider, 2x + 5y = 7

x 1
y 1

A. (1, 1) is a solution of 2x + 5y = 7

B. If positive real numbers are chosen, 2x + 5y = 7 will have many solutions.

C. If real numbers are chosen, 2x + 5y = 7 will have infinite solutions.

D. If rational numbers are chosen, 2x + 5y = 7 will have many solutions.

Hence, option A is the correct answer.

Q3Written answer

If (2, 0) is a solution of the linear equation 2x + 3y = k, then the value of k is
A. 4
B. 6
C. 5
D. 2

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Worked solution

A. 4

Explanation:

We know that,

(2, 0) = (x, y)

Substituting values of x and y in the above equation, we get

2×2 + 3×0 = k

k = 4

Hence, option A is the correct answer.

Q4Written answer

Any solution of the linear equation 2x + 0y + 9 = 0 in two variables is of the form

A. (-9/2 , m)
B. (n, -9/2)
C. (0, -9/2)
D. ( – 9, 0)

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Worked solution

A. (-9/2 , m) 

Explanation:

Solving the above equation we get,

2x = -9

x = -9/2

As the coefficient of y is 0, therefore, y can take any value and will not affect our answer.

A. x = -9/2

y = any value

B. x = n

C. x = 0

D. x = -9

Hence, option A is the correct answer.

Q5Written answer

The graph of the linear equation 2x + 3y = 6 cuts the y – axis at the point

A. (2, 0)
B. (0, 3)
C. (3, 0)
D. (0, 2)

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Worked solution

D. (0, 2)

Let 2x + 3y = 6 cut the y-axis at P. therefore at P x-coordinate = 0.

Substituting x = 0, we get

2(0) + 3y = 6

3y = 6

y = 2

Hence the coordinates are (0, 2).

A. (2, 0) is wrong because it has x = 2

B. (0, 3) is wrong because it has y = 3

C. (3, 0) is wrong because it has x = 3

D. (0, 2) is right because it has x = 0 and y = 2 which is equal to the coordinates (0,2)

Hence, option D is the correct answer.

Q6Written answer

The equation x = 7, in two variables, can be written as

A. 1. x + 1. y = 7
B. 1. x + 0. y = 7
C. 0. x + 1. y = 7
D. 0. x + 0. y = 7

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Worked solution

B. 1. x + 0. y = 7

A. Simplifying the equation we get x + y = 7

B. Simplifying the equation we get x + 0y = 7 which is equal to x = 7

C. Simplifying the equation we get y = 7

D. simplifying the equation we get 0x + 0y = 7 which is not possible.

Hence, option (B) is the correct answer.

Q7Written answer

Any point on the x-axis is of the form

A. (x, y)
B. (0, y)
C. (x, 0)
D. (x, x)

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Worked solution

C. (x, 0)

Any point on the x-axis has its ordinate 0.

So, any point on the x-axis if of the form (x, 0).

Hence, option (C) is the correct answer.

Q8Written answer

Any point on the line y = x is of the form

A. (a, a)
B. (0, a)
C. (a, 0)
D. (a, – a)

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Worked solution

A. (a, a)

Any point on the line y = x will have x and y coordinate same.

So, any point on the line y = x is of the form (a, a).

Hence, option (A) is the correct answer.

Q9Written answer

The equation of x – axis is of the form

A. x = 0
B. y = 0
C. x + y = 0
D. x = y

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Worked solution

B. y = 0

The equation of x-axis is y = 0, since, x-axis is a parallel to itself at a distance 0 from it.

Hence, option (B) is the correct answer.