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Practice each question, then open the answer or worked solution.
Write the coordinates of each of the points P, Q, R, S, T and O from Fig. 3.5.
The coordinates of the points P, Q, R, S, T and O are as follows:
P = (1, 1)
Q = (-3, 0)
R = (-2, -3)
S = (2, 1)
T = (4, -2)
O = (0, 0)
Plot the following points and write the name of the figure obtained by joining them in order:
P(– 3, 2), Q (– 7, – 3), R (6, – 3), S (2, 2)
The figure obtained is a Trapezium.
Plot the points (x, y) given by the following table:
Plot the following points and check whether they are collinear or not:
(i) (1, 3), (– 1, – 1), (– 2, – 3)
(ii) (1, 1), (2, – 3), (– 1, – 2)
(iii) (0, 0), (2, 2), (5, 5)
(i)
The points (1, 3), (– 1, – 1), (– 2, – 3) lie in a straight line,
Hence, the points are collinear.
(ii)
The points (1, 1), (2, – 3), (– 1, – 2) lie in a straight line,
Hence, the points are not collinear.
(iii)
The points (0, 0), (2, 2), (5, 5) lie in a straight line,
Hence, the points are collinear.
Without plotting the points, indicate the quadrant in which they will lie, if
(i) ordinate is 5 and abscissa is – 3
(ii) abscissa is – 5 and ordinate is – 3
(iii) abscissa is – 5 and ordinate is 3
(iv) ordinate is 5 and abscissa is 3
(i) The point is (-3,5).
Hence, the point lies in the II quadrant.
(ii) The point is (-5,-3).
Hence, the point lies in the III quadrant.
(iii) The point is (-5,3).
Hence, the point lies in the II quadrant.
(iv) The point is (3,5).
Hence, the point lies in the I quadrant.
In Fig. 3.6, LM is a line parallel to the y-axis at a distance of 3 units.
(i) What are the coordinates of the points P, R and Q?
(ii) What is the difference between the abscissa of points L and M?
(i) The coordinates are:
P = (3,2)
R = (3,0)
Q = (3,-1)
(ii) Since, all the points on the line have the same abscissa = 3.
The difference in abscissa of L and M = 0.