Which of the following expressions are Polynomials? Justify your answer.
(i) $ 8 $
(ii) $ \sqrt 3 {x^2} - 2x $
(iii) $ 1 - \sqrt {5x} $
(iv) $ \dfrac{1}{{5{x^{ - 2}}}} + 5x + 7 $
(v) $ \dfrac{{\left( {x - 2} \right)\left( {x - 4} \right)}}{x} $
(vi) $ \dfrac{1}{{x + 1}} $
(vii) $ \dfrac{1}{7}{a^3} - \dfrac{2}{{\sqrt 3 }}{a^2} + 4a - 7 $
(viii) $ \dfrac{1}{{2x}} $
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Ans: Here we have given an expression $ 8 $ in which the degree of variable is zero. Therefore, it is a constant Polynomial.
Ans: $ \sqrt 3 {x^2} - 2x $
Here, in each term the power of x is a whole number. Therefore, this expression is a Polynomial.
Ans: $ 1 - \sqrt {5x} $
We can also write it as $ 1 - \sqrt 5 {x^{\dfrac{1}{2}}} $ . Here the degree of variable is not a whole number. Therefore, this expression is not a Polynomial.
Ans: $ \dfrac{1}{{5{x^{ - 2}}}} + 5x + 7 $
We can also write it as $ \dfrac{{1{x^2}}}{5} + 5x + 7 $ . Here in this expression each variable term has the power of x in a whole number. Therefore, this expression is a Polynomial.
Ans: $ \dfrac{{\left( {x - 2} \right)\left( {x - 4} \right)}}{x} $
We can also write it as
$ \dfrac{{{x^2} - 6x + 8}}{x} = x - 6 + \dfrac{8}{x} = x - 6 + 8{x^{ - 1}} $
Here, the exponent of variable x in the third term $ 8{x^{ - 1}} $ is – 1, and this is not a whole number.
Therefore, this algebraic expression is not a Polynomial.
Ans: $ \dfrac{1}{{x + 1}} $
We can also reduce it to $ {\left( {x + 1} \right)^{ - 1}} $ , which cannot be reduced to an expression in which the exponent of the variable x had only whole numbers in each of its terms. Therefore, this algebraic expression is not a Polynomial.
Ans: $ \dfrac{1}{7}{a^3} - \dfrac{2}{{\sqrt 3 }}{a^2} + 4a - 7 $
In this expression, the exponent of a in each term is a whole number, so this expression is a Polynomial.
Ans: $ \dfrac{1}{{2x}} $
We can also write it as $ \dfrac{1}{2}{x^{ - 1}} $ . Here, the exponent of the variable x is $ - 1 $ , which is not a whole number so, this algebraic expression is not a Polynomial.