A triangle can be constructed by taking its sides as:
(a) ${\mathbf{1}}{\mathbf{.8cm,2}}{\mathbf{.6cm,4}}{\mathbf{.4cm}}$
(b) ${\mathbf{2cm,3cm,4cm}}$
(c) ${\mathbf{2}}{\mathbf{.4cm,2}}{\mathbf{.4cm,6}}{\mathbf{.4cm}}$
(d) ${\mathbf{3}}{\mathbf{.2cm,2}}{\mathbf{.3cm,5}}{\mathbf{.5cm}}$
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Ans: Option (b) is the correct answer.
A triangle is possible, when the sum of two sides is greater than the third side. Use the hit and trial method and check the all options:
For option (a),
$1.8{\text{cm}} + 2.6{\text{cm}} = 4.4{\text{cm}}$, which is equal to third side
For option (b),
$2{\text{cm}} + 3{\text{cm}} = 5{\text{cm}}$, which is greater than third side
For option (c),
$2.4{\text{cm}} + 2.4{\text{cm}} = 4.8{\text{cm}}$, which is less than third side
For option (d),
$3.2{\text{cm}} + 2.3{\text{cm}} = 5.5{\text{cm}}$, which is equal to the third side.
Thus, only option (b) satisfies the condition. Therefore, option (b) is right.






