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NCERT Exemplar · Class 12 · Physics

Chapter 11: Dual Nature of Radiation and Matter

Practice each question, then open the answer or worked solution.

Questions

29 questions
Q11.1Written answer

A particle is dropped from a height H. The de Broglie wavelength of the particle as a function of height is proportional to

(a) H

(b) H ½

(c) H0

(d) H–1/2

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Worked solution

The correct answer is d) H–1/2

Q11.2Multiple choice

The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly

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Correct option: B
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Worked solution

The correct answer is b) 1.2 × 10–3 nm

Q11.3Written answer

Consider a beam of electrons (each electron with energy E0) incident on a metal surface kept in an evacuated chamber. Then

(a) no electrons will be emitted as only photons can emit electrons

(b) electrons can be emitted but all with an energy, E0

(c) electrons can be emitted with any energy, with a maximum of E0 – φ (φ is the work function)

(d) electrons can be emitted with any energy, with a maximum of E0

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Worked solution

The correct answer is d) electrons can be emitted with any energy, with a maximum of E0

Q11.4Written answer

Consider Fig. 11.7 in the NCERT textbook of physics for Class XII. Suppose the voltage applied to A is increased. The diffracted beam will have the maximum at a value of θ that

(a) will be larger than the earlier value

(b) will be the same as the earlier value

(c) will be less than the earlier value

(d) will depend on the target

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Worked solution

The correct answer is c) will be less than the earlier value

Q11.5Written answer

A proton, a neutron, an electron and an α-particle have the same energy. Then their de Broglie wavelengths compare as

(a) λp = λn > λe > λα

(b) λα < λp = λn < λe

(c) λe < λp = λn > λα

(d) λe = λp = λn = λα

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Worked solution

The correct answer is b) λα < λp = λn < λe

Q11.6Written answer

An electron is moving with an initial velocity Exemplar Solutions Physics Class 12 Chapter 11 - 1 and is in a magnetic field Exemplar Solutions Physics Class 12 Chapter 11 - 2 Then it’s de Broglie wavelength

(a) remains constant

(b) increases with time

(c) decreases with time

(d) increases and decreases periodically

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Worked solution

The correct answer is a) remains constant

Q11.7Written answer

An electron (mass m ) with an initial velocity Exemplar Solutions Physics Class 12 Chapter 11 - 3 is in an electric field Exemplar Solutions Physics Class 12 Chapter 11 - 4 It’s de Broglie wavelength at time t is given by

a)

Exemplar Solutions Physics Class 12 Chapter 11 - 5

b)

Exemplar Solutions Physics Class 12 Chapter 11 - 6

c) λ0

d) λ0t

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Worked solution

The correct answer is a)Exemplar Solutions Physics Class 12 Chapter 11 - 7

Q11.8Written answer

An electron (mass m) with an initial velocity Exemplar Solutions Physics Class 12 Chapter 11 - 8 is in an electric field Exemplar Solutions Physics Class 12 Chapter 11 - 9 . If λ0 = h/mv0, it’s de Broglie wavelength at time t is given by

a) λ0

b)

Exemplar Solutions Physics Class 12 Chapter 11 - 10

c)

Exemplar Solutions Physics Class 12 Chapter 11 - 11

d)

Exemplar Solutions Physics Class 12 Chapter 11 - 12

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Worked solution

The correct answer is c)Exemplar Solutions Physics Class 12 Chapter 11 - 13

Multiple Choice Questions II
Q11.9Written answer

Relativistic corrections become necessary when the expression for the kinetic energy 1/2 mv2 , becomes comparable with mc2, where m is the mass of the particle. At what de Broglie wavelength will relativistic corrections become important for an electron?

(a) λ =10nm

(b) λ =10–1nm

(c) λ =10–4nm

(d) λ =10–6nm

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Worked solution

The correct answers are

c) λ =10–4nm

d) λ =10–6nm

Q11.10Written answer

Two particles A1 and A2 of masses m1, m2 (m1 > m2) have the same de Broglie wavelength. Then

(a) their momenta are the same

(b) their energies are the same

(c) energy of A1 is less than the energy of A2

(d) energy of A1 is more than the energy of A2

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Worked solution

The correct answers are

a) their momenta are the same

c) energy of A1 is less than the energy of A2