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NCERT Exemplar · Class 12 · Physics

Chapter 5: Magnetism and Matter

Practice each question, then open the answer or worked solution.

Questions

25 questions
Q5.1Written answer

A toroid of n turns, mean radius R and cross-sectional radius a carries current I. It is placed on a horizontal table taken as an x-y plane. Its magnetic moment m

a) is non-zero and points in the z-direction by symmetry

b) points along the axis of the toroid
Exemplar Solutions Class 12 Physics Chapter 5 - 1

c) is zero, otherwise, there would be a field falling as 1/r3 at large distances outside the toroid

d) is pointing radially outwards

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Worked solution

c) is zero, otherwise, there would be a field falling as 1/r3 at large distances outside the toroid

Q5.2Written answer

The magnetic field of the earth can be modelled by that of a point dipole placed at the centre of the earth. The dipole axis makes an angle of 11.3o with the axis of the earth. At Mumbai, declination is nearly zero. Then,

a) the declination varies between 11.3o W to 11.3o E

b) the least declination is 0o

c) the plane defined by the dipole axis and the earth axis passes through Greenwich

d) declination average over the earth must always be negative

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Worked solution

a) the declination varies between 11.3o W to 11.3o E

Q5.3Written answer

In a permanent magnet at room temperature

a) magnetic moment of each molecule is zero

b) the individual molecules have a non-zero magnetic moment which is all perfectly aligned

c) domains are partially aligned

d) domains are all perfectly aligned

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Worked solution

d) domains are all perfectly aligned

Q5.4Written answer

Consider the two idealized systems: i) a parallel plate capacitor with large plates and small separation and ii) a long solenoid of length L >> R, the radius of the cross-section. In i) E is ideally treated as a constant between plates and zero outside. In ii) the magnetic field is constant inside the solenoid and zero outside. These idealised assumptions, however, contradict fundamental laws as below:

a) case (i) contradicts Gauss’s law for electrostatic fields

b) case (ii) contradicts Gauss’s law for magnetic fields

c) case (i) agrees with
Exemplar Solutions Class 12 Physics Chapter 5 - 2

d) case (ii) contradicts
Exemplar Solutions Class 12 Physics Chapter 5 - 3

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Worked solution

b) case (ii) contradicts Gauss’s law for magnetic fields

Q5.5Written answer

A paramagnetic sample shows a net magnetisation of 8 Am-1 when placed in an external magnetic field of 0.6T at a temperature of 4K. When the same sample is placed in an external magnetic field of 0.2T at a temperature of 16K, the magnetisation will be

a) 32/3 Am-1

b) 2/3 Am-1

c) 6 Am-1

d) 2.4 Am-1

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Worked solution

b) 2/3 Am-1

Multiple Choice Questions II
Q5.6Written answer

S is the surface of a lump of magnetic material

a) lines of B are necessarily continuous across S

b) some lines of B must be discontinuous across S

c) lines of H are necessarily continuous across S

d) lines of H cannot all be continuous across S

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Worked solution

a) lines of B are necessarily continuous across S

d) lines of H cannot all be continuous across S

Q5.7Written answer

The primary origin(s) of magnetism lies in

a) atomic currents

b) Pauli exclusion principle

c) polar nature of molecules

d) intrinsic spin of electron

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Worked solution

a) atomic currents

d) intrinsic spin of electron

Q5.8Written answer

A long solenoid has 1000 turns per meter and carries a current of 1 A. It has a soft iron core of μr = 1000. The core is heated beyond the Curie temperature Tc

a) the H field in the solenoid is unchanged, but the B field decreases drastically

b) the H and B fields in the solenoid are nearly unchanged

c) the magnetisation in the core reverses the direction

d) the magnetisation in the core diminishes by a factor of about 108

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Worked solution

a) the H field in the solenoid is unchanged, but the B field decreases drastically

d) the magnetisation in the core diminishes by a factor of about 108

Q5.9Written answer

Essential difference between electrostatic shielding by a conducting shell and magnetostatic shielding is due to

a) electrostatic field lines can end on charges, and conductors have free charges

b) lines of B can also end, but conductors cannot end them

c) lines of B cannot end on any material, and perfect shielding is not possible

d) shells of high permeability materials can be used to divert lines of B from the interior region

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Worked solution

a) electrostatic field lines can end on charges, and conductors have free charges

c) lines of B cannot end on any material, and perfect shielding is not possible

d) shells of high permeability materials can be used to divert lines of B from the interior region

Q5.10Written answer

Let the magnetic field on the earth be modelled by that of a point magnetic dipole at the centre of the earth. The angle of dip at a point on the geographical equator

a) is always zero

b) can be zero at specific points

c) can be positive or negative

d) is bounded

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Worked solution

b) can be zero at specific points

c) can be positive or negative

d) is bounded

Very Short Answers