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NCERT Exemplar · Class 7 · Maths

Chapter 5: Lines and Angles

Practice each question, then open the answer or worked solution.

Questions

56 questions
Q21Written answer

If two supplementary angles are in the ratio 1: 2, then the bigger angle is

(a) 120o (b) 125o (c) 110o (d) 90o

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Worked solution

Solution:-

(a) 120o

We know that, when the sum of the measures of two angles is 180o, then the angles are called supplementary angles.

Let us assume two angles be 1x and 2x.

1x + 2x = 180o

3x = 180o

x = 180o/3

x = 60o

Then the bigger angle is 2x = 2 × 60o = 120o

Q22Written answer

In Fig. 5.19, ∠ROS is a right angle and ∠POR and ∠QOS are in the ratio 1: 5. Then, ∠QOS measures

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 12

(a) 150o (b) 75o (c) 45o (d) 60o

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Solution:-

(b) 75o

The sum of all angles about a straight line given in the figure is equal to 180o.

Given, ∠ROS is a right angle = 90o

Let us assume ∠POR = x and ∠QOS = 5x.

Then, ∠POR + ∠ROS + ∠QOS = 180o

x + 90o + 5x = 180o

6x = 180o – 90o

6x = 90o

x = 90o/6

x = 15o

So, ∠QOS measures = 5x = 5 × 15o = 75o

Q23Written answer

Statements a and b are as given below:

a: If two lines intersect, then the vertically opposite angles are equal.

b: If a transversal intersects two other lines, then the sum of two interior angles on the same side of the transversal is 180o.

Then

(a) Both a and b are true (b) a is true and b is false

(c) a is false and b is true (d) both a and b are false

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Solution:-

(b) a is true and b is false

Q24Written answer

For Fig. 5.20, statements p and q are given below:

p: a and b are forming a linear pair.

q: a and b are forming a pair of adjacent angles.

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 13

Then,

(a) both p and q are true

(b) p is true and q is false

(c) p is false and q is true

(d) both p and q are false

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Solution:-

(a) both p and q are true

Q25Written answer

In Fig. 5.21, ∠AOC and ∠ BOC form a pair of

(a) vertically opposite angles

(b) complementary angles

(c) alternate interior angles

(d) supplementary angles

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 14

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Solution:-

(d) supplementary angles

Q26Written answer

In Fig. 5.22, the value of a is

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 15

(a) 20o (b) 15o

(c) 5o (d) 10o

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Solution:-

(d) 10o

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 16

∠AOF = ∠COD = 90o [because vertically opposite angles]

Sum of all angles about a straight line given in the figure are equal to 180o.

Then, ∠BOC + ∠COD + ∠DOE = 180o

40o + 90o + 5a = 180o

130o + 5a = 180o

5a = 180o – 130o

5a = 50o

a = 50/5

a = 10o

Q27Written answer

In Fig. 5.23, if QP || SR, the value of a is

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 17

(a) 40o (b) 30o (c) 90o (d) 80o

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Solution:-

(c) 90o

To find out the value of ‘a’, draw a line XY, to cut at ‘a’.

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 18

So, XY || SR

∠XTS = ∠TSR = 30o … [because interior alternate angles]

∠PQT = ∠QTX = 60o … [because interior alternate angles]

Then, a = ∠XTS + ∠QTX

= 30o + 60o

= 90o

Q28Written answer

In which of the following figures, a and b are forming a pair of adjacent angles?

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 19

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Solution:-

In figure (d) a and b form a pair of adjacent angles.

Q29Written answer

In a pair of adjacent angles, (i) vertex is always common, (ii) one arm is always common, and (iii) uncommon arms are always opposite rays

Then

(a) All (i), (ii) and (iii) are true

(b) (iii) is false

(c) (i) is false but (ii) and (iii) are true

(d) (ii) is false

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Solution:-

(b) (iii) is false

Two angles are called adjacent angles, if they have a common vertex and a common arm but no common interior points.

Q30Written answer

In Fig. 5.25, lines PQ and ST intersect at O. If ∠POR = 90° and x : y = 3 : 2, then z is equal to

(a) 126o (b) 144o (c) 136o (d) 154o

NCERT Exemplar Class 7 Maths Solutions Chapter 5 Image 20

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Solution:-

(b) 144o

The sum of all angles about a straight line given in the figure is equal to 180o.

PQ is a straight line.

Then, ∠POR + ∠ROT + ∠TOQ = 180o

Given, x : y = 3 : 2

Let us assume x = 3a, y = 2a

90o + 3a + 2a = 180o

90o + 5a = 180o

5a = 180o – 90o

5a = 90o

a = 90/5

a = 18o

So, x = 3a = 3 × 18 = 54o

y = 2a = 2 × 18 = 36o

From the figure SOT is a straight line,

Then, z+ y = 180o

z + 36o = 180o

z = 180o – 36o

z = 144o