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NCERT Exemplar · Class 12 · Physics

Chapter 4: Moving Charges and Magnetism

Practice each question, then open the answer or worked solution.

Questions

29 questions
Q4.21Written answer

A multirange voltmeter can be constructed by using a galvanometer circuit, as shown in the figure. We want to construct a voltmeter that can measure 2V, 20V, and 200V using a galvanometer of resistance 10Ω and that produces maximum deflection for a current of 1 mA. Find R1, R2, and R3 that have to be used.

Exemplar Solutions Class 12 Physics Chapter 4 - 12

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Worked solution

iG(G+R1) = 2 for 2V range

iG(G+R1+R2) = 20 for 20V range

iG(G+R1+R2+R3) = 200 for 200V range

Solving the above, we get

R1 = 1990 Ω

R2 = 18kΩ

R3 = 180 kΩ

Q4.22Written answer

A long straight wire carrying a current of 25 A rests on a table, as shown in the figure. Another wire PQ of length 1 m, mass 2.5 g carries the same current but in the opposite direction. The wire PQ is free to slide up and down. To what height will PQ rise?

Exemplar Solutions Class 12 Physics Chapter 4 - 13

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Worked solution

Exemplar Solutions Class 12 Physics Chapter 4 - 14

The magnetic field produced by a long straight current-carrying wire is given as

B = μ0I/2πh

Magnetic force on the small conductor is F = BIl sin θ = BIl

F = mg = μ0I2l/2πh

h = 0.51 cm

Long Answers
Q4.23Written answer

A 100-turn rectangular coil ABCD is hung from one arm of a balance. A mass of 500 g is added to the other arm to balance the weight of the coil. A current 4.9 A passes through the coil, and a constant magnetic field of 0.2 T acting inward is switched on such that only arm CD of length 1 cm lies in the field. How much additional mass ‘m’ must be added to regain the balance?

Exemplar Solutions Class 12 Physics Chapter 4 - 15

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Worked solution

When t = 0, the external magnetic field is off.

Mgl = Wcoil l

0.5 gl = Wcoil l

Wcoil = 0.5 9.8 N

Let m be the mass which is added to regain the balance

When the magnetic field is switched is on,

Mgl + mgl = (ILC)l

m = 1 g

Q4.24Written answer

A rectangular conducting loop consists of two wires on two opposite sides of length l joined together by rods of length d. The wires are each of the same material but with cross-sections differing by a factor of 2. The thicker wire has a resistance R, and the rods are of low resistance, which in turn are connected to a constant voltage source Vo. The loop is placed in uniform a magnetic field B at 45o to its plane. Find τ, the torque exerted by the magnetic field on the loop about an axis through the centres of rods.

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Worked solution

Exemplar Solutions Class 12 Physics Chapter 4 - 16

Force and torque on the first wire are given as

F1 = i1l B sin 90o = V0/2R lB

τ1= d/2√2

F1 = V0ldB/2√2 R

τ = 1/4√2 V0AB/R

Q4.25Written answer

An electron and a positron are released from (0, 0, 0) and (0, 0, 1.5R), respectively, in a uniform magnetic field
each with an equal momentum of magnitude p = eBR. Under what conditions on the direction of momentum will the orbits be non-intersecting circles?

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Worked solution

Exemplar Solutions Class 12 Physics Chapter 4 - 17

When the centres are greater than 2R, then the circular orbits of the electron and positron shall not overlap.

Let d be the distance between Cp and Ce

Then d2 = 4R2 + 9/4R2 – 6R2 cosθ

As d is greater than 2R,

9/4 > 6 cos θ or cos θ < 3/8

Q4.26Written answer

A uniform conducting wire of length 12a and resistance R is wound up as a current-carrying coil in the shape of i) an equilateral triangle of side a, ii) a square of sides a, and iii) a regular hexagon of sides a. The coil is connected to a voltage source V0. Find the magnetic moment of the coils in each case.

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Worked solution

a) An equilateral triangle with sides a

No. of loops = 4

Area of the triangle A = √3/4 a2

Magnetic moment, m = Ia2√3

Exemplar Solutions Class 12 Physics Chapter 4 - 18

b) For a square with sides a

Area, A = a2

No.of loops = 3

Magnetic moment, m = 3Ia2

Exemplar Solutions Class 12 Physics Chapter 4 - 19

c) For a regular hexagon with sides a

Area, A = 6√3/4 a2

No.of loops = 2

Magnetic moment, m = 3√3a2I

Exemplar Solutions Class 12 Physics Chapter 4 - 20

Q4.27Written answer

Consider a circular current-carrying loop of radius R in the x-y plane with the centre at the origin. Consider the line integral
Exemplar Solutions Class 12 Physics Chapter 4 - 21 taken along the z-axis.

a) show that
Exemplar Solutions Class 12 Physics Chapter 4 - 22 monotonically increases with L

b) use an appropriate Amperian loop to that
Exemplar Solutions Class 12 Physics Chapter 4 - 23 where I is the current in the wire

c) verify directly the above result

d) suppose we replace the circular coil with a square coil of sides R carrying the same current I. What can you say about
Exemplar Solutions Class 12 Physics Chapter 4 - 24

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Exemplar Solutions Class 12 Physics Chapter 4 - 25

a) Magnetic field due to a circular current-carrying loop is given as

Exemplar Solutions Class 12 Physics Chapter 4 - 26

It is a monotonically increasing function of L

b) The Amperian loop is given as

Exemplar Solutions Class 12 Physics Chapter 4 - 27

c) The magnetic field at the axis of the circular coil is given as μ0I

d) When a circular coil is replaced with a square coil, it is given as

Exemplar Solutions Class 12 Physics Chapter 4 - 28

Q4.28Written answer

A multirange current meter can be constructed by using a galvanometer circuit shown in the figure. We want a current meter that can measure 10 mA, 100 mA, and 1 A using a galvanometer of resistance 10Ω and that produces maximum deflection for a current of 1 mA. Find S1, S2, and S3 that have to be used.

Exemplar Solutions Class 12 Physics Chapter 4 - 29

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Exemplar Solutions Class 12 Physics Chapter 4 - 30

I1 is measured as = 10 mA = IGG = (I1 – IG)(S1 + S2 + S3)

I2 is measured as = 100 mA = IG(G+S1)=(I2-IG)(S2-S3)

I3 is measured as = 1 A = IG(G+S1+S2)=(I3-IG)(S3)

S1 = 1 Ω

S2 = 0.1 Ω

S3 = 0.01 Ω

Q4.29Written answer

Five long wires A, B, C, D, and E, each carrying I are arranged to form the edges of a pentagonal prism, as shown in the figure. Each carries current out of the plane of the paper.

a) what will be magnetic induction at a point on the axis O> Axis is at a distance R from each wire

b) what will be the field if the current in one of the wires is switched off

c) what if the current in one of the wires A is reversed

Exemplar Solutions Class 12 Physics Chapter 4 - 31

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Worked solution

a)

Exemplar Solutions Class 12 Physics Chapter 4 - 32

The magnetic induction at a point on the axis will be 0, which is represented by R as A, B, C, D, and E is perpendicular to the plane of paper at the given locations.

b)

Exemplar Solutions Class 12 Physics Chapter 4 - 33

When the current in one of the wires is switched off, the field μ0/2π i/R will be perpendicular to AO towards left.

c)

Exemplar Solutions Class 12 Physics Chapter 4 - 34

If the current is reversed, then the total magnetic field induction at O is μ0/4πR 2I/R

Moving charges and magnetism helps establish a relationship between magnetism and electricity. These moving charges are responsible for the effect of magnetism; however, a charged particle without acceleration can produce an electrical and magnetic field.

Some of the concepts that are introduced in this chapter are listed below:

  1. Ampere’s Circuital Law
  2. The Solenoid and the Toroid
  3. Moving Coil Galvanometer
  4. Magnetic Force
  5. Magnetic Field