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NCERT Exemplar · Class 12 · Chemistry

Chapter 13: Amines

Practice each question, then open the answer or worked solution.

Multiple Choice Questions (Type-II)

10 questions
Q28Written answer

Which of the following cannot be prepared by Sandmeyer’s reaction?

(A) Chlorobenzene 

(B) Bromobenzene

(C) Iodobenzene 

(D) Fluorobenzene

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Worked solution

Ans: (C and D) 

Chlorobenzene and bromobenzene are prepared by the sandmeyer’s reaction. 

While fluorobenzene and iodobenzene are prepared by simple heating of diazonium salt with aqueous KI Solution.


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Q29Written answer

Reduction of nitrobenzene by which of the following reagents give aniline?

(A) $\mathrm{Sn} / \mathrm{HCl}$

(B) $\mathrm{Fe} / \mathrm{HCl}$

(C) $\mathrm{H}_{2}-\mathrm{Pd}$

(D) $\mathrm{Sn} / \mathrm{NH}_{4} \mathrm{OH}$

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Worked solution

Ans: (A, B & C) 

Nitro compounds are reduced to amines by passing hydrogen gas through an acidic medium containing finely divided nickel, palladium, or platinum, as well as by reduction with metals in an acidic medium.


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Q30Written answer

Which of the following species are involved in the carbylamine test?

(A) R-NC

(B) $\mathrm{CHCl}_{3}$

(C) $\mathrm{COCl}_{2}$

(D) $\mathrm{NaNO}_{2}+\mathrm{HCl}$

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Worked solution

Ans: (A and B)

When aliphatic and aromatic primary amines are heated with chloroform and ethanolic potassium hydroxide, they form isocyanides or carbylamines, which have a foul odor. This reaction does not occur in secondary or tertiary amines.


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Q31Written answer

The reagents that can be used to convert benzene diazonium chloride to benzene are

(A) $\mathrm{SnCl}_{2} / \mathrm{HCl}$

(B) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$

(C) $\mathrm{H}_{3} \mathrm{PO}_{2}$

(D) $\mathrm{LiAlH}_{4}$

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Worked solution

Ans: (B and C) 

Certain mild reducing agents like hypophosphorous acid (phosphinic acid) or ethanol reduce diazonium salts to arenes and themselves get oxidised to phosphorous acid and ethanol, respectively.


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Q32Written answer

The Product of the following reaction is.


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(A)


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(B)


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(C)


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(D)


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Worked solution

Ans: (A and B)  

$\mathrm{NHCOCH}_{3}$ is an ortho- para directing group so ortho-para products are formed. 


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Q33Written answer

Arenium ion involved in the bromination of aniline is.

(A)


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(B)


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(C)


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(D)


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Worked solution

Ans: (A, B & C)  

As the $\mathrm{NH}_{2}$ group is Ortho para directing group, so $\mathrm{Br}^{+}$attacks only at the o and p positions thus the products formed corresponds to the option A, B and C.


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Q34Written answer

Which of the following amines can be prepared by Gabriel synthesis?

(A) Isobutyl amine 

(B) 2-Phenylethylamine

(C) N-Methylbenzylamine 

(D) Aniline

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Worked solution

Ans: (A and B) 

Gabriel synthesis is a method for producing primary amines. When phthalimide is treated with ethanolic potassium hydroxide, it forms a potassium salt of phthalimide, which when heated with an alkyl halide and then alkaline hydrolyzed yields the corresponding primary amine.


Q35Written answer

Which of the following reactions are correct?

(A)


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(B)


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(C)


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(D)


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Worked solution

Ans: (A and C) 

(a) Primary alkyl halides react with ammonia to give primary amines. Correct reaction.

(B) Elimination process doesn’t occur with aq. KOH, hydrolysis process takes place. (B) is incorrect. 

(c) Dehydrohalogenation I.e. elimination of HCl occurs which produces alkene as the product takes place with alc. KOH . (c) is correct.

(d) In this reaction, aliphatic primary amines, on treatment with nitrous acid, produce primary alcohol as a product.

Therefore (D) is incorrect. 


Q36Written answer

Under which of the following reaction conditions, aniline gives p-nitro derivative as the major product?

(A) Acetyl chloride/pyridine followed by reaction with conc. $\mathrm{H}_{2} \mathrm{SO}_{4}+$ conc. $\mathrm{HNO}_{3}$

(B) Acetic anhydride/pyridine followed by conc. $\mathrm{H}_{2} \mathrm{SO}_{4}+$ conc. $\mathrm{HNO}_{3}$

(C) Dil. $\mathrm{HCl}$ followed by reaction with conc. $\mathrm{H}_{2} \mathrm{SO}_{4}+$ conc. $\mathrm{HNO}_{3}$

(D) Reaction with conc. $\mathrm{H}_{2} \mathrm{SO}_{4}+$ conc. $\mathrm{HNO}_{3}$

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Worked solution

Ans: (A and B)  

In addition to the nitro derivatives, direct nitration of aniline produces tarry oxidation products. Furthermore, aniline is protonated in the strongly acidic medium to form the anilinium ion, which is meta directing. As a result, in addition to the ortho and para derivatives, a significant amount of meta derivative is formed.

However, by protecting the $-\mathrm{NH}_{2}$ group with an acetylation reaction with acetic anhydride, the nitration reaction can be controlled and the p-nitro derivative obtained as the main product.


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Q37Written answer

Which of the following reactions belong to electrophilic aromatic substitution?

(A) Bromination of acetanilide

(B) Coupling reaction of aryldiazonium salts

(C) Diazotization of aniline

(D) Acylation of aniline

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Worked solution

Ans: (A and B)  

Benzene diazonium chloride reacts with phenol to form p-hydroxy azobenzene by coupling the phenol molecule at its para position with the diazonium salt. This is referred to as a coupling reaction. This is an illustration of an electrophilic substitution reaction. 


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At room temperature, aniline reacts with bromine water to form a white precipitate of 2,4,6-tribromoaniline.

By acetylation with acetic anhydride to protect the $-\mathrm{NH}_{2}$ group, then carrying out the desired substitution followed by hydrolysis of the substituted amide to the substituted amine.


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