Q11Written answer
In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.
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Worked solution
The initial count of bacteria is given as 5,06,000
Bacteria at the end of 2 hours = 506000(1 + 2.5/100)2
= 506000(1 + 1/40)2
= 506000(41/40)2
= 531616.25
Therefore, the count of bacteria at the end of 2 hours will be 5,31,616 (approx.).