Chemical Bonding And Molecular Structure - Inorganic Chemistry - Chemistry Previous Year Questions

Observe the following list of molecules. Number of polar and non-polar molecules are respectively

$\mathrm{NH}_3, \mathrm{BF}_3, \mathrm{NF}_3, \mathrm{H}_2 \mathrm{~S}_2, \mathrm{CO}_2, \mathrm{CH}_4, \mathrm{CHCl}_3, \mathrm{H}_2 \mathrm{O}$

The molecule ' $X$ ' has see-saw shape with central atom in $s p^3 d$ hybridisation. What is ' $X$ '?

Identify the pair of molecules in which the hybridisation of the central atom is $s p^2$ with bent geometry.

Consider the following statements

I. In the conversion of $\mathrm{O}_2$ to $\mathrm{O}_2^{2+}$ bond order decreases.

II. In the conversion of $\mathrm{O}_2$ to $\mathrm{O}_2^{2+}$ magnetic property is not changed.

III. In the conversion of $\mathrm{O}_2$ to $\mathrm{O}_2^{2+}$ bond length decreases.

IV. $\mathrm{O}_2^{2-}$ and $\mathrm{B}_2$ have same bond order.

Identify the correct statements

If the sum of bond orders of $\mathrm{O}_2^{-}$and $\mathrm{O}_2^{2-}$ is $x$, then bond order of $\mathrm{O}_2^{2+}$ will be

Identify the molecule / ion in which the ratio of $\sigma$ to $\pi$-bonds is $3: 2$

Observe the following statements

Statement-I Hybridisation is not same in both $\mathrm{SF}_6$ and $\mathrm{BrF}_5$.

Statement-II $\mathrm{BrF}_5$ is square pyramidal while $\mathrm{SF}_6$ is octahedral in shape.

The correct answer is

The sum of bond order of $\mathrm{O}_2^{+}, \mathrm{O}_2^{-}, \mathrm{O}_2$ and $\mathrm{O}_2^{2+}$ is equal to

The atomic numbers of the elements $X, Y, Z$ are $a, a+1, a+2$ respectively. $Z$ is an alkali metal. The nature of bonding in the compound formed by $X$ and $Z$ is

The sets of molecules in which central atom has no lone pair of electrons are

I. $\mathrm{SnCl}_2, \mathrm{NH}_3, \mathrm{SF}_4$

II. $\mathrm{HgCl}_2, \mathrm{SO}_3, \mathrm{SF}_6$

III. $\mathrm{BeCl}_2 \mathrm{BF}_3, \mathrm{PCl}_5$

IV. $\mathrm{ClF}_3, \mathrm{BrF}_5, \mathrm{XeF}_6$