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Exam Details

TG EAPCET 2025 ONLINE 2ND MAY EVENING SHIFT

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Questions 160
Duration 180 mins
Package TG EAPCET- Previous Year Papers

Paper pattern & analysis

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Showing all 160 questions in this paper.

Subject distribution

Mathematics
80 Qs
Physics
40 Qs
Chemistry
40 Qs

Topic distribution

Algebra
31 Qs
Calculus
21 Qs
Mechanics
19 Qs
Coordinate Geometry
18 Qs
Inorganic Chemistry
15 Qs
Organic Chemistry
14 Qs
Physical Chemistry
11 Qs
Electromagnetism
10 Qs
Trigonometry
10 Qs
Modern Physics
8 Qs
Optics
3 Qs

Subtopic distribution

Circle
6 Qs
Hydrocarbons
5 Qs
Probability
5 Qs
Vector Algebra
5 Qs
Application Of Derivatives
5 Qs
Indefinite Integration
5 Qs
Straight Lines And Pair Of Straight Lines
5 Qs
Heat And Thermodynamics
4 Qs
Atoms And Nuclei
4 Qs
P Block Elements
4 Qs
Complex Numbers
4 Qs
Matrices And Determinants
4 Qs

Difficulty distribution

Not classified 120 75%
Medium 22 13.8%
Easy 15 9.4%
Hard 3 1.9%

Question type distribution

MCQ 160 100%

Syllabus

Full Syllabus

Practise paper questions

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1
PYP
TG EAPCET 2025 ONLINE 2ND MAY EVENING SHIFT

The locus of the centre of the circle touching the $X$-axis and passing through the point $(-1,1)$ is

2
PYP
TG EAPCET 2025 ONLINE 2ND MAY EVENING SHIFT

Two bodies are projected from the same point with the same initial velocity ' $u$ ' making angles ' $\theta^{\prime}$ and $\left(90^{\circ}-\theta\right)$ with the horizontal in opposite directions. The horizontal distance between their positions when the bodies are at their maximum heights is

3
PYP
TG EAPCET 2025 ONLINE 2ND MAY EVENING SHIFT

The ratio of times taken by a freely falling body to travel first 5 m , second 5 m , third 5 m distances is

4
PYP
TG EAPCET 2025 ONLINE 2ND MAY EVENING SHIFT
If $L$ and $C$ are inductance and capacitance respectively, then the dimensional formula of $(\mathrm{LC})^{-\frac{1}{2}}$ is
5
PYP
TG EAPCET 2025 ONLINE 2ND MAY EVENING SHIFT
A body projected vertically up with an initial speed of $10 \mathrm{~ms}^{-1}$ reaches the point of projection after sometime with a speed of $8 \mathrm{~ms}^{-1}$. The maximum height reached by the body is (Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

Showing 5 of 160 questions