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Practice Inverse Trigonometric Functions - Trigonometry - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Inverse Trigonometric Functions. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| COMEDK 2026 Afternoon Shift | 2026 | 2 | View paper |
| COMEDK 2026 Morning Shift | 2026 | 2 | View paper |
| COMEDK 2025 AFTERNOON SHIFT | 2025 | 2 | View paper |
| COMEDK 2025 EVENING SHIFT | 2025 | 2 | View paper |
| COMEDK 2025 Morning Shift | 2025 | 2 | View paper |
| COMEDK 2024 AFTERNOON SHIFT | 2024 | 3 | View paper |
| COMEDK 2024 EVENING SHIFT | 2024 | 3 | View paper |
| COMEDK 2024 MORNING SHIFT | 2024 | 2 | View paper |
| COMEDK 2023 EVENING SHIFT | 2023 | 2 | View paper |
| COMEDK 2020 | 2020 | 3 | View paper |
Practice every matching question in batches of 20, with every available option.
The solution of \({\tan ^{ - 1}}x + 2{\cot ^{ - 1}}x = {{2\pi } \over 3}\) is
If \({\sec ^{ - 1}}\left( {{{1 + x} \over {1 - y}}} \right) = a\), then \({{dy} \over {dx}}\) is
The value of \(\sin \left[ {2{{\cos }^{ - 1}}{{\sqrt 5 } \over 3}} \right]\) is
$$\text { Let } f(x)=\cos ^{-1}(3 x-1) \text {, then domain of } f(x) \text { is equal to }$$
$$\text { The value of } \sin ^{-1}\left[\cos \left(39 \frac{\pi}{5}\right)\right] \text { is }$$
Evaluate :
$$\operatorname{cosec}^{-1}\left(-\frac{2 \sqrt{3}}{3}\right)+\tan ^{-1}\left(-\frac{\sqrt{3}}{3}\right)+\sec ^{-1} 2+\cos ^{-1}\left(-\frac{1}{2}\right)-\sin ^{-1}\left(\frac{\sqrt{2}}{2}\right)$$
$$\text { If } \alpha=\tan ^{-1}\left(\tan \frac{5 \pi}{4}\right) \text { and } \beta=\tan ^{-1}\left(-\tan \frac{2 \pi}{3}\right) \text { then }$$
$$\text { If } y=\sin ^{-1}(\sqrt{\sin x}) \text {, then } \frac{d y}{d x} \text { equals }$$
$$\text { Evaluate: } \cot ^{-1}\left(-\frac{3}{\sqrt{3}}\right)-\sec ^{-1}\left(-\frac{2}{\sqrt{2}}\right)-\operatorname{cosec}^{-1}(-1)-\tan ^{-1}(1)$$
$$\text { The function } f(x)=\tan ^{-1}(\sin x+\cos x) \text { is an increasing function in }$$
$$\text { Evaluate: } \cos ^{-1}\left(\cos \frac{35 \pi}{18}\right)-\sin ^{-1}\left(\sin \frac{35 \pi}{18}\right)$$
\(\text { The value of } \sin ^{-1}\left[\cot \left(\frac{1}{2} \tan ^{-1} \frac{1}{\sqrt{3}}+\cos ^{-1} \frac{\sqrt{12}}{4}+\sin ^{-1} \frac{1}{\sqrt{2}}\right)\right]\) is
Evaluate : \(\cos ^{-1}\left[\cos \left(-680^{\circ}\right)\right]+\sin ^{-1}\left[\sin \left(-600^{\circ}\right)\right]-\cos ^{-1}\left(\sin 270^{\circ}\right)\)
Which of the following is the simplest form of the expression $\boldsymbol{\operatorname { t a n }}^{-\mathbf{1}}\left(\frac{\sqrt{\mathbf{1 + x ^ { \mathbf { 2 } }}}-\mathbf{1}}{\boldsymbol{x}}\right)$ where $x \neq 0$
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