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Practice Binomial Theorem - Algebra - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Binomial Theorem. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| COMEDK 2025 AFTERNOON SHIFT | 2025 | 1 | View paper |
| COMEDK 2025 Morning Shift | 2025 | 1 | View paper |
| COMEDK 2024 AFTERNOON SHIFT | 2024 | 1 | View paper |
| COMEDK 2024 EVENING SHIFT | 2024 | 1 | View paper |
| COMEDK 2024 MORNING SHIFT | 2024 | 1 | View paper |
| COMEDK 2023 Morning Shift | 2023 | 6 | View paper |
| COMEDK 2022 | 2022 | 5 | View paper |
| COMEDK 2021 | 2021 | 6 | View paper |
| COMEDK 2020 | 2020 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
The ninth term of the expansion \({\left( {3x - {1 \over {2x}}} \right)^8}\) is
Using mathematical induction, the numbers \({a_n}\)'s are defined by \({a_0} = 1,{a_{n + 1}} = 3{n^2} + n + {a_n},(n \ge 0)\). Then, \({a_n}\) is equal to
The coefficient of \(x^{10}\) in the expansion of \(1+(1+x)+...+(1+x)^{20}\) is
If \(49^n+16n+P\) is divisible by 64 for all \(n\in N\), then the least negative integral value of P is
Number of terms in the binomial expansion of \((x+a)^{53}+(x-a)^{53}\) is
Middle term in the expansion of \({\left( {{x^2} + {1 \over {{x^2}}} + 2} \right)^n}\) is
\({2^{3n}} - 7n - 1\) is divisible by
The total number of terms in the expansion of \({(x + y)^{100}} + {(x - y)^{100}}\) is
If \(U_{n+1}=3 U_n-2 U_{n-1}\) and \(U_0=2, U_1=3\), then \(U_n\) is equal to
The coefficient of \({x^{20}}\) in the expansion of \({(1 + 3x + 3{x^2} + {x^3})^{20}}\) is
If \(4^n+15n+P\) is divisible by 9 for all \(n\in N\), then the least negative integral value of P is
In the expansion of \({(1 - 3x + 3{x^2} - {x^3})^{2n}}\), the middle term is
If the sum of the coefficients of the first three terms in the expansion of \(\left(x-\frac{a}{x^2}\right)^{12}, x \neq 0\) is 559. Find the value of '\(a\)' if '\(a\)' belongs to positive integers
In the expansion \(\left(\frac{1}{x}+x \sin x\right)^{10}, \quad\) the co - efficient of \(6^{\text {th }}\) term is equal to \(7 \frac{7}{8}\), then the principal value of \(x\) is
The coefficient of the third term in the expansion of \(\left(x^2-\frac{1}{4}\right)^n\), when expanded in the descending power of \(x\) is 31, then \(n\) is
If \(49^n+16^n+k\) is divisible by 64 for \(n \in N\), then the least negative integral value of \(k\) is
The coefficient of \(x^{29}\) in the expansion of \(\left(1-3 x+3 x^2-x^3\right)^{15}\) is
In the expansion of \(\left(1+3 x+3 x^2+x^3\right)^{2 n}\), the term which has greatest binomial coefficient, is
$$2^{3 n}-7 n-1 \text { is divisible by }$$
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