ap × bq = (ab)pq
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Ans: False.
RHS = (ab)pq
Using law of exponents, am × an = am+n
Therefore, (ab)pq = (a)pq x (b)pq
L H S ≠ R H S
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ap × bq = (ab)pq
Ans: False.
RHS = (ab)pq
Using law of exponents, am × an = am+n
Therefore, (ab)pq = (a)pq x (b)pq
L H S ≠ R H S
$\dfrac{{{x^m}}}{{{y^m}}} = {\left( {\dfrac{y}{x}} \right)^{ - m}}$
Ans: True
${\text{RHS = }}{\left( {\dfrac{y}{x}} \right)^{ - m}} = {\left( {\dfrac{x}{y}} \right)^m} = \dfrac{{{x^m}}}{{{y^m}}} = {\text{LHS}}$
${a^m} = \dfrac{1}{{{a^{ - m}}}}$
Ans: True
Using law of exponents, ${x^{ - m}} = \dfrac{1}{{{x^m}}}$
${a^m} = \dfrac{1}{{{a^{ - m}}}}$
The exponential form for (–2)4 × ${\left( {\dfrac{5}{2}} \right)^4}$ is 54.
Ans: True
${\left( { - 2} \right)^4} \times {\left( {\dfrac{5}{2}} \right)^4} = {\left( 2 \right)^4} \times {\left( {\dfrac{5}{2}} \right)^4}$
= ${2^4} \times \dfrac{{{5^4}}}{{{2^4}}} = {5^4}$
The standard form for 0.000037 is 3.7 × 10–5.
Ans: True
For standard form, 0.000037 = 0.37 x 10-4= 3.7 x 10-5
The standard form for 203000 is 2.03 × 105
Ans: True
For standard form, 203000 = 203 x 10 x 10 x 10 = 203 x 103
= 2.03 x 102 x 103= 2.03 x 105
The usual form for 2 × 10–2 is not equal to 0.02.
Ans: False
As, $2 \times {10^{ - 2}} = 2 \times \dfrac{1}{{{{10}^2}}} = 2 \times \dfrac{1}{{100}} = 0.02$
The value of 5–2 is equal to 25.
Ans: False
As, ${5^{ - 2}} = \dfrac{1}{{{5^2}}} = \dfrac{1}{{25}} \ne 25$
Large numbers can be expressed in the standard form by using positive exponents.
Ans: True
e.g. 2350000 = 235 x 10 x 10 x 10 x 10 = 235 x 104
= 2.35 x 104 x 102 =2.35 x 106
am × bm = (ab)m
Ans: True
LHS = am × bm = (a × b)m = (ab)m