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NCERT Exemplar · Class 8 · Maths

Chapter 4: Linear Equations in One Variable

Practice each question, then open the answer or worked solution.

Questions

61 questions
Q41Written answer

In the equation 2x = 4 – x, transposing –x to LHS, we get x = 4.

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Worked solution

Solution:-

False.

Given, 2x = 4 – x

Transposing –x to LHS it becomes x

2x + x = 4

3x = 4

X = 3/4

Q42Written answer

If (15/8) – 7x = 9, then -7x = 9 + (15/8)

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Worked solution

Solution:-

False.

Given, (15/8) – 7x = 9

Transposing 15/8 to RHS it becomes – (15/8)

– 7x = 9 – (15/8)

Q43Written answer

If (x/3) + 1 = (7/15), then x/3 = 6/15

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Worked solution

Solution:-

False.

Given, (x/3) + 1 = (7/15)

Transposing 1 to RHS it becomes – 1

(x/3) = (7/15) – 1

(x/3) = (7 – 15)/15

(x/3) = -8/15

Q44Written answer

If 6x = 18, then 18x = 54

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Worked solution

Solution:-

True.

Given, 6x = 18

Multiplying both LHS and RHS by 3, we get

6x × 3 = 18 × 3

18x = 54

Q45Written answer

If x/11 = 15, then x = 11/15

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Worked solution

Solution:-

False.

Given, x/11 = 15

Multiplying both LHS and RHS by 11, we get

(x/11) × 11 = 15 × 11

X = 165

Q46Written answer

If x is an even number, then the next even number is 2(x + 1).

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Worked solution

Solution:-

False.

If x is an even number, then the next even number is (x + 2)

Q47Written answer

If the sum of two consecutive numbers is 93 and one of them is x, then the other number is 93 – x.

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Worked solution

Solution:-

False.

From the question,

The sum of two consecutive numbers is 93

Two consecutive number are = x and 93 – x

Then, sum of two consecutive numbers = x + (93 – x) = 93

X + 93 – x = 93

Transposing 93 to RHS it becomes – 93

x – x = 93 -93

0 = 0

Q48Written answer

Two numbers differ by 40, when each number is increased by 8, the bigger becomes thrice the lesser number. If one number is x, then the other number is (40 – x).

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Worked solution

Solution:-

False.

From the question it is given that,

One number = x

Other number = 40 –x

Let us assume (40 – x) > x

So, 40 – x + 8 = 3 (x + 8)

48 – x = 3x + 24

– x – 3x = 24 -48

– 4x = -24

X = -24 × (-1/4)

X = 6

∴One number is x = 6

Other number is = 40 – x

= 40 – 6

= 34

Difference between numbers = 34 – 6 = 28

Solve the following:

Q49Written answer

((3x – 8)/2x) = 1

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Worked solution

Solution:-

We have,

((3x – 8)/2x) = 1

By cross multiplication, we get

(3x – 8) = 2x

Transposing -8 to RHS it becomes 8 and 2x to LHS it becomes – 2x

3x – 2x = 8

x = 8

Q50Written answer

(5x/(2x – 1)) = 2

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Worked solution

Solution:-

We have,

(5x/(2x – 1)) = 2

By cross multiplication, we get

5x = 2 × (2x – 1)

5x = 4x – 2

Transposing 4x to LHS, it becomes – 4x

5x – 4x = -2

x = -2