In the equation 2x = 4 – x, transposing –x to LHS, we get x = 4.
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Solution:-
False.
Given, 2x = 4 – x
Transposing –x to LHS it becomes x
2x + x = 4
3x = 4
X = 3/4
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In the equation 2x = 4 – x, transposing –x to LHS, we get x = 4.
Solution:-
False.
Given, 2x = 4 – x
Transposing –x to LHS it becomes x
2x + x = 4
3x = 4
X = 3/4
If (15/8) – 7x = 9, then -7x = 9 + (15/8)
Solution:-
False.
Given, (15/8) – 7x = 9
Transposing 15/8 to RHS it becomes – (15/8)
– 7x = 9 – (15/8)
If (x/3) + 1 = (7/15), then x/3 = 6/15
Solution:-
False.
Given, (x/3) + 1 = (7/15)
Transposing 1 to RHS it becomes – 1
(x/3) = (7/15) – 1
(x/3) = (7 – 15)/15
(x/3) = -8/15
If 6x = 18, then 18x = 54
Solution:-
True.
Given, 6x = 18
Multiplying both LHS and RHS by 3, we get
6x × 3 = 18 × 3
18x = 54
If x/11 = 15, then x = 11/15
Solution:-
False.
Given, x/11 = 15
Multiplying both LHS and RHS by 11, we get
(x/11) × 11 = 15 × 11
X = 165
If x is an even number, then the next even number is 2(x + 1).
Solution:-
False.
If x is an even number, then the next even number is (x + 2)
If the sum of two consecutive numbers is 93 and one of them is x, then the other number is 93 – x.
Solution:-
False.
From the question,
The sum of two consecutive numbers is 93
Two consecutive number are = x and 93 – x
Then, sum of two consecutive numbers = x + (93 – x) = 93
X + 93 – x = 93
Transposing 93 to RHS it becomes – 93
x – x = 93 -93
0 = 0
Two numbers differ by 40, when each number is increased by 8, the bigger becomes thrice the lesser number. If one number is x, then the other number is (40 – x).
Solution:-
False.
From the question it is given that,
One number = x
Other number = 40 –x
Let us assume (40 – x) > x
So, 40 – x + 8 = 3 (x + 8)
48 – x = 3x + 24
– x – 3x = 24 -48
– 4x = -24
X = -24 × (-1/4)
X = 6
∴One number is x = 6
Other number is = 40 – x
= 40 – 6
= 34
Difference between numbers = 34 – 6 = 28
Solve the following:
((3x – 8)/2x) = 1
Solution:-
We have,
((3x – 8)/2x) = 1
By cross multiplication, we get
(3x – 8) = 2x
Transposing -8 to RHS it becomes 8 and 2x to LHS it becomes – 2x
3x – 2x = 8
x = 8
(5x/(2x – 1)) = 2
Solution:-
We have,
(5x/(2x – 1)) = 2
By cross multiplication, we get
5x = 2 × (2x – 1)
5x = 4x – 2
Transposing 4x to LHS, it becomes – 4x
5x – 4x = -2
x = -2