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NCERT Exemplar · Class 8 · Maths

Chapter 3: Squares and Square Roots & Cubes and Cube Roots

Practice each question, then open the answer or worked solution.

Questions

142 questions
Q21Written answer

A perfect square number having n digits where n is even will have square root with

(a) n + 1 digit (b) n/2 digit (c) n/3 digit (d) (n + 1)/2 digit

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Worked solution

Solution:-

(b) n/2 digit

Q22Written answer

If m is the cube root of n, then n is

(a) m3 (b) √m (c) m/3 (d) 3√m

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Worked solution

Solution:-

(a) m3

Given in the question,

3√n = m

n = m3

Q23Written answer

The value of √(248 + √(52 + √144)) is

(a) 14 (b) 12 (c) 16 (d) 13

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Worked solution

Solution:-

(c) 16

√(248 + √(52 + √144))

= √(248 + √(52 + 12))

= √(248 + √(64))

= √(248 + 8)

= √(256)

= 16

Q24Written answer

Given that √4096 = 64, the value of √4096 + √40.96 is

(a) 74 (b) 60.4 (c) 64.4 (d) 70.4

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Worked solution

Solution:-

(d) 70.4

√4096 + √40.96

= 64 + 6.4

= 70.4

In questions 25 to 48, fill in the blanks to make the statements true.

Q25Written answer

There are _________ perfect squares between 1 and 100.

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Worked solution

Solution:-

There are 8 perfect squares between 1 and 100.

2 × 2 = 4

3 × 3 = 9

4 × 4 = 16

5 × 5 = 25

6 × 6 = 36

7 × 7 = 49

8 × 8 = 64

9 × 9 = 81

Q26Written answer

There are _________ perfect cubes between 1 and 1000.

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Worked solution

Solution:-

There are 8 perfect cubes between 1 and 1000.

2 × 2 × 2 = 8

3 × 3 × 3 = 27

4 × 4 × 4 = 64

5 × 5 × 5 = 125

6 × 6 × 6 = 216

7 × 7 × 7 = 343

8 × 8 × 8 = 512

9 × 9 × 9 = 729

Q27Written answer

The units digit in the square of 1294 is _________.

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Worked solution

Solution:-

The units digit in the square of 1294 is 6.

We know that, 4 or 6 at the units place ends in 6.

Q28Written answer

The square of 500 will have _________ zeroes.

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Worked solution

Solution:-

The square of 500 will have 4 zeroes.

5002 = 500 × 500 = 25000

Q29Written answer

There are _________ natural numbers between n2 and (n + 1)2.

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Worked solution

Solution:-

There are 2n natural numbers between n2 and (n + 1)2.

Q30Written answer

The square root of 24025 will have _________ digits.

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Worked solution

Solution:-

The square root of 24025 will have 3 digits.

The number given in the question has 5 digits,

i.e. n = 5

Then,

= (n + 1)/2

= (5 + 1)/2

= 6/2

= 3