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NCERT Exemplar · Class 8 · Maths

Chapter 13: Playing with Numbers

Practice each question, then open the answer or worked solution.

Questions

45 questions
Q11Written answer

If the sum of digits of a number is divisible by three, then the number is always divisible by

(a) 2 (b) 3 (c) 6 (d) 9

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Worked solution

Solution: The correct answer is option (b) 3

Explanation:

Option (b) – 3 is the correct answer because the divisibility test of 3 says that if the sum of the digits of a number is divisible by 3, then the number is always divisible by 3.

Q12Written answer

If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is

(a) an odd multiple of 3 (b) odd multiple of 6

(c) even multiple of 3 (d) even multiple of 9

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Worked solution

Solution: The correct answer is option (a) an odd multiple of 3

Explanation:

Given that, the sum of the digits xyz is given as x+y+z is 6, where z is an odd integer.

The divisibility test of 3, the number xyz is divisible by z. Since the last digit is an odd digit, then xyz is an odd multiple of 3.

Q13Written answer

If 5 A + B 3 = 65, then the value of A and B is

(a) A = 2, B = 3 (b) A = 3, B = 2

(c) A = 2, B = 1 (d) A = 1, B = 2

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Worked solution

Solution: The correct answer is option (c) A = 2, B = 1

Explanation:

NCERT Exemplar Class 8 Maths Solutions for Chapter 13 - 1

In the 1’s column A +3 = 5

When A is added with 3, it gives 5

Since A is a digit, it should be between 0 and 9

When you substitute A = 2, you will get 2+3 = 5

Similarly, repeat the process for 10’s column

Then we will get B= 1

Therefore A= 2, and B = 1

Q14Written answer

If A 3 + 8 B = 150, then the value of A + B is

(a) 13 (b) 12 (c) 17 (d) 15

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Worked solution

Solution: The correct answer is option (a) 13

Explanation:

From the question,

NCERT Exemplar Class 8 Maths Solutions for Chapter 13 - 2

In 1’s place, we have to add 3+B = 0

Since B is a digit, the value of B should be between 0 and 9

When you substitute the value of B = 7, then you will get

3+7 = 10

So here, the unit digit is 0.

Now carry 1 to the 10’ s place,

Repeat the same process for 10’s place, you will get the value of A

So, A = 6

Therefore, A+B = 6+7 = 13

Q15Written answer

If 5 A × A = 399, then the value of A is

(a) 3 (b) 6 (c) 7 (d) 9

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Worked solution

Solution: The correct answer is option (c) 7

Explanation:

In the 1’s place, the product of A and A gives 9

Here, A is a number whose multiplication gives the two digit number having 9 in its 1’s place.

So, the product of 7 and 7 gives 49, where 1’s place is 9.

Q16Written answer

If 6 A × B = A 8 B, then the value of A – B is

(a) –2 (b) 2 (c) –3 (d) 3

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Worked solution

Solution: The correct answer is option (a) -2

Explanation:

Given that, 6 A × B = A 8 B

So, AB = B

Therefore A = 1

Now substitute A = 1 in the given equation

6B = A8

6B = 18

B = 18/6 = 3

Now, A – B = 1 -3 = -2

Q17Written answer

Which of the following numbers is divisible by 99

(a) 913462 (b) 114345 (c) 135792 (d) 3572406

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Worked solution

Solution: The correct answer is option (b) 114345

Explanation:

If a number is divisible is 99, it should be divisible by both 9 and 11.

From the given option, option (b) 114345 is divisible by both 9 and 11.

All other numbers are either divisible by 9 or 11, but not both 9 and 11.

In questions 18 to 33, fill in the blanks to make the statements true.

Q18Written answer

3134673 is divisible by 3 and ______.

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Worked solution

Solution: 9

Explanation:

Adding all the digits in the given number, we get 27, which is divisible by 3 and 9.

Q19Written answer

20×3 is a multiple of 3 if the digit x is ______ or ______ or ______.

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Worked solution

Solution: 1 or 4 or 7

Explanation:

It is known that, when a number is a multiple of 3, if the sum of digits in the number is a multiple of 3

By equating the closet multiple of 3, such as 6, 9, and 12, we get the digit

Either the digit x should be 1 or 4 or 7.

Q20Written answer

3×5 is divisible by 9 if the digit x is __________.

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Worked solution

Solution: 1

Explanation:

It is known that, if a number is a multiple of 9, then the sum of the digits of a number is divisible by 9.

From, the given equation, we can write it as:

3+x+5 = x + 8

It means that x+8 is divisible by 8, if x+8 is equal to 9,

Then the value of x is 1.