Can you find a rational number whose multiplicative inverse is –1?
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Solution:-
No, we cannot find a rational number whose multiplicative inverse is –1.
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Can you find a rational number whose multiplicative inverse is –1?
Solution:-
No, we cannot find a rational number whose multiplicative inverse is –1.
Find five rational numbers between 0 and 1.
Solution:-
The five rational numbers between 0 and 1 are, 1/6, 2/6, 3/6, 4/6, 5/6.
Find two rational numbers whose absolute value is 1/5.
Solution:-
1/5 and -1/5 are the rational number whose absolute value is 1/5.
From a rope 40 metres long, pieces of equal size are cut. If the length of one piece is 10/3 metre, find the number of such pieces.
Solution:-
From the question it is given that,
The length of rope = 40 m
The length of one piece of rope = 10/3
Let us assume the total number of pieces be y.
So,
(10/3) y = 40
y = (40 × 3)/10
y = 120/10
y = 12 pieces
∴The number of pieces cut from the rope are 12.
5½ metres long rope is cut into 12 equal pieces. What is the length of each piece?
Solution:-
From the question it is given that,
The length of rope = 5½ m = 11/2 m
The total number of pieces = 12
Let us assume the length of one piece of rope be y.
So,
12y = 11/2 m
y = (11/2) × (1/12)
y = 11/24
∴The length of one piece of rope 11/24.
Write the following rational numbers in the descending order.
(8/7), (-9/8), (-3/2), 0, (2/5)
Solution:-
The LCM of the denominators 7, 8, 2 and 5 is 280
∴ 8/7 = [(8×40)/ (7×40)] = (320/280)
(-9/8) = [(-9×35)/ (8×35)] = (-315/280)
(-3/2) = [(-3×140)/ (2×140)] = (-420/280)
(2/5) = [(2×56)/ (56×56)] = (112/280)
Now, 320 > 112 > 0 > -315 > -420
Hence, ⇒ 8/7 > 2/5 > 0 > -9/8 > -3/2
Descending order 8/7, 2/5, 0, -9/8, -3/2
Find (i) 0 ÷ (2/3)
Solution:-
0 ÷ (2/3) = 0 × (3/2)
= 0/2
= 0
On a winter day the temperature at a place in Himachal Pradesh was –16°C. Convert it in degree Fahrenheit (oF) by using the formula.
(C/5) = (F – 32)/9
Solution:-
Given, a winter day the temperature at a place in Himachal Pradesh was –16°C.
Formula, (C/5) = (F – 32)/9
Where, C = -16o
Then,
(-16o/5) = (F – 32)/9
(-16o/5) × 9 = F -32
(-144/5) = F – 32
F = 32 – (144/5)
F = (160 – 144)/5
F = 16/5
F = 3.2 oF
Find the sum of additive inverse and multiplicative inverse of 7.
Solution:-
Additive inverse of 7 = – 7
Multiplicative inverse of 7 = 1/7
Then,
Sum of additive inverse and multiplicative inverse of 7 = -7 + (1/7)
= (-49 + 1)/7
= – 48/7
Find the product of additive inverse and multiplicative inverse of 1/3.
Solution:-
Additive inverse of -1/3 = 1/3
Multiplicative inverse of -1/3 = -3/1
Then,
The product of additive inverse and multiplicative inverse of 1/3 = 1/3 × (-3)
= -1