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Practice each question, then open the answer or worked solution.
Sonal bought a bed sheet for ₹ 400 and sold it for ₹ 440. Her ________% is ________.
Solution:-
Sonal bought a bed sheet for ₹ 400 and sold it for ₹ 440. Her Profit% is 10.
From the question, it is given that, cost price of bed = ₹ 400
Selling price of bed = ₹ 440
SP is more than CP so, Profit = SP – CP
= 440 – 400
= ₹ 40
We know that, Profit percentage = (Profit/CP) × 100
= (40/400) × 100
= 10%
Nasim bought a pen for ₹ 60 and sold it for ₹ 54. His ________% is ________.
Solution:-
Nasim bought a pen for ₹ 60 and sold it for ₹ 54. His loss% is 10.
From the question, it is given that, cost price of pen = ₹ 60
Selling price of pen = ₹ 54
CP is more than SP so, Loss = CP – SP
= 60 – 54
= ₹ 6
We know that, loss percentage = (loss/CP) × 100
= (6/60) × 100
= 10%
Aahuti purchased a house for ₹ 50,59,700 and spent ₹ 40300 on its repairs. To make a profit of 5%, she should sell the house for ₹ ________.
Solution:-
Aahuti purchased a house for ₹ 50,59,700 and spent ₹ 40300 on its repairs. To make a profit of 5%, she should sell the house for ₹ 5355000.
From the question it is give that,
Cost price of house purchased by Aahuti = ₹ 50,59,700
Amount spent to repair the house = ₹ 40,300
Then, total cost price of house = ₹ 50,59,700 + 40,300
= ₹ 5100000
Profit % = (profit/CP) × 100
5 = ((SP – CP)/CP) × 100
5 = ((SP – 5100000)/5100000) × 100
(5 × 5100000)/100 = SP – 5100000
SP = ₹ 5355000
If 20 lemons are bought for ₹ 10 and sold at 5 for three rupees, then ________ in the transaction is ________%.
Solution:-
If 20 lemons are bought for ₹ 10 and sold at 5 for three rupees, then profit in the transaction is 20%.
From the question, it is given that, cost price of 20 lemons = ₹ 10
Selling price of 5 lemons = ₹ 3
So, selling price of 1 lemon = ₹ 3/5
Then, selling price of 20 lemons = ₹ (3/5) × 20
= 12
SP is more than CP so, Profit = SP – CP
= 12 – 10
= ₹ 2
We know that, Profit percentage = (Profit/CP) × 100
= (2/10) × 100
= 20%
Narain bought 120 oranges at ₹ 4 each. He sold 60 % of the oranges at ₹ 5 each and the remaining at ₹ 3.50 each. His ________ is ________%.
Solution:-
Narain bought 120 oranges at ₹ 4 each. He sold 60 % of the oranges at ₹ 5 each and the remaining at ₹ 3.50 each. His profit is 10%.
From the question, it is given that, cost price of one orange = ₹ 4
cost price of 120 oranges = ₹ 4 × 120 = ₹ 480
So, selling price of 60% of oranges = ₹ 5 per each
60% of 120 oranges = (60/100) × 120
= 7200/100
= 72 oranges
Selling price of 72 oranges = 72 × 5 = ₹ 360
SP of remaining oranges = (120 – 72) × 3.50
= 48 × 3.50
= ₹ 168
Therefore total selling price of 120 oranges = ₹ 360 + ₹ 168
= ₹ 528
SP is more than CP so, Profit = SP – CP
= 528 – 480
= ₹ 48
We know that, Profit percentage = (Profit/CP) × 100
= (48/480) × 100
= 10%
A fruit seller purchased 20 kg of apples at ₹ 50 per kg. Out of these, 5% of the apples were found to be rotten. If he sells the remaining apples at ₹ 60 per kg, then his _________is _________%.
Solution:-
A fruit seller purchased 20 kg of apples at ₹ 50 per kg. Out of these, 5% of the apples were found to be rotten. If he sells the remaining apples at ₹ 60 per kg, then his profit is 14 %.
From the question it is given that, A fruit seller purchased 20 kg of apples at ₹ 50 per kg
In that 20 kg of apples 5% were rotten, so good apples = 20 – 5% of 20kg
= 20 – (5/100) × 20
= 20 – (100/100)
= 20 – 1
= 19 kg
So, 19 kg apples were sold at ₹ 60 per kg
Then, total Selling price of apples = 19 × 60
= ₹ 1140
Given cost price of 20 kg of apples = 20 × 50
= ₹ 1000
SP is more than CP so, Profit = SP – CP
= 1140 – 1000
= ₹ 140
We know that, Profit percentage = (Profit/CP) × 100
= (140/1000) × 100
= 14%
Interest on ₹ 3000 at 10% per annum for a period of 3 years is ________.
Solution:-
Interest on ₹ 3000 at 10% per annum for a period of 3 years is ₹ 900.
From the question it is given that,
Principal= ₹ 3000
Time = 3 years
Rate = 10%
Then, we know the formula of Simple interest I = (P × R × T)/100
I= (3000 × (10) × 3)/100
I = ₹ 900
Amount obtained by depositing ₹ 20,000 at 8 % per annum for six months is ________.
Solution:-
Amount obtained by depositing ₹ 20,000 at 8 % per annum for six months is ₹ 20800
From the question it is given that,
Principal= ₹ 20000
Time = 6 months = 6/12 = ½
Rate = 8%
Then, we know the formula of Simple interest I = (P × R × T)/100
I= (20000 × 8 × ½ ) /100
I = ₹ 800
Amount received = Principal + Interest
= 20000 + 800
= ₹ 20800
Interest on ₹ 12500 at 18% per annum for a period of 2 years and 4 months is ________.
Solution:-
Interest on ₹ 12500 at 18% per annum for a period of 2 years and 4 months is ₹ 5250.
From the question it is given that,
Principal= ₹ 12500
Time = 2 years 4 months = (2 + (4/12))
= (2 + (1/3))
= 7/3 year
Rate = 18%
Then, we know the formula of Simple interest I = (P × R × T)/100
I= (12500 × 18 × (7/3)) /100
I = ₹ 5250
25 ml is _________ percent of 5 litres.
Solution:-
25 ml is 0.5 percent of 5 litres
Let us assume 25 ml be Q % of 5 liters.
So, 25 ml = Q % of 5l
25 = (Q/100) × 5 × 1000
Q = (25 × 100)/(5 × 1000)
Q = 0.5%