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Practice each question, then open the answer or worked solution.
15 kg is _______ % of 50 kg.
Solution:-
15 kg is 30 % of 50 kg.
Let us assume the percentage be P.
So, P% of 50 kg =15 kg
(P/100) × 50 = 15
P = (15 × 100)/50
P = 1500/50
P = 150/5
P = 30
Weight of Nikhil increased from 60 kg to 66 kg. Then, the increase in weight is _______ %.
Solution:-
Weight of Nikhil increased from 60 kg to 66 kg. Then, the increase in weight is 10 %.
From the question it is given that, Weight of Nikhil increased from 60 kg to 66 kg.
So, weight increase = 66 – 60
= 6 kg
Then, percentage increase = (Weight increase/Initial weight) × 100%
= (6/60) × 100
= 600/60
= 60/6
= 10%
In a class of 50 students, 8 % were absent on one day. The number of students present on that day was ________.
Solution:-
In a class of 50 students, 8 % were absent on one day. The number of students present on that day was 46.
From the question it is given that, number of students in the class = 50
Percentage of students who were absent on one day = 8%
Then, percentage of students who were present on one day = 100% – 8%
= 92%
So, 92% of 50
= (92/100) × 50
= 4600/100
= 46 students
Savitri obtained 440 marks out of 500 in an examination. She secured _______ % marks in the examination.
Solution:-
Savitri obtained 440 marks out of 500 in an examination. She secured 88% marks in the examination.
From the question it is give that, Savitri obtained 440 marks out of 500 in an examination,
Then, percentage of marks obtained by Savitri = (440/500) × 100
= 0.88 × 100
= 88%
Out of a total deposit of ₹ 1500 in her bank account, Abida withdrew 40% of the deposit. Now the balance in her account is ______.
Solution:-
Out of a total deposit of ₹ 1500 in her bank account, Abida withdrew 40% of the deposit. Now the balance in her account is ₹ 900.
From the question,
Total deposit in Abida’s account = ₹ 1500
Percentage of amount Abida withdrew = 40%
Then, amount withdrew = 40% of ₹ 1500
= (40/100) × 1500
= 60000/100
= ₹ 600
Then, remaining amount in the account = ₹ 1500 – ₹ 600
= ₹ 900
________ is 50% more than 60.
Solution:-
90 is 50% more than 60.
Let us assume the number be Q.
From the question, Q is 50% more than 60
So, Q = 60 + (50/100) × 60
= 60 + (3000/100)
= 60 + 30
= 90
John sells a bat for ₹ 75 and suffers a loss of ₹ 8. The cost price of the bat is________.
Solution:-
John sells a bat for ₹ 75 and suffers a loss of ₹ 8. The cost price of the bat is ₹ 83.
From the question it is given that, the selling price of bat ₹ 75
Loss = ₹ 8
We know that, Cost Price (CP) = SP + loss
= ₹ 75 + ₹ 8
= ₹ 83
If the price of sugar is decreased by 20%, then the new price of 3kg sugar, originally costing ₹ 120 will be
Solution:-
If the price of sugar is decreased by 20%, then the new price of 3kg sugar originally costing ₹ 120 will be ₹ 96
From the question it is given that, price of 3kg sugar originally costing ₹ 120
The price of the sugar is decreased by 20%
Then, the new price of sugar = 120 – 20% of original price
= 120 – (20/100) × 120
= 120 – (2400/100)
= 120 – 24
= ₹ 96
Mohini bought a cow for ₹ 9000 and sold it at a loss of ₹ 900. The selling price of the cow is ________.
Solution:-
Mohini bought a cow for ₹ 9000 and sold it at a loss of ₹ 900. The selling price of the cow is ₹ 8100
From the question it is given that,
Cost price of cow (CP) = ₹ 9000
Loss = ₹ 900
We know that, Selling price (SP) = CP – loss
= 9000 – 900
= ₹ 8100
Devangi buys a chair for ₹ 700 and sells it for ₹ 750. She earns a profit of ________ % in the transaction.
Solution:-
Devangi buys a chair for ₹ 700 and sells it for ₹ 750. She earns a profit of
% in the transaction.
From the question it is given that, cost price of chair = ₹ 700
As we know that, Profit = SP – CP
= 750 – 700
= ₹ 50
Then, Profit percentage = (profit/CP) × 100%
= (50/700) × 100
=
%