Chapter 4: Simple Equations

Solution:-

Consider the given integers, x – 5 = – 5.

Transpose – 5 to RHS then it becomes 5.

x = – 5 + 5

x = 0

In natural numbers, x – 5 = – 5 has no solution.

Solution:-

Consider the given integers, x + 8 = 12 – 4.

x + 8 = 8

Transpose 8 to RHS then it becomes – 8.

x = 8 – 8

x = 0

In natural numbers, x + 8 = 12 – 4 has one solution.

Solution:-

Let us assume the number be x,

Given, If 5 is added to three times a number = 3x + 5

7 is subtracted from four times the same number = 4x – 7

If 5 is added to three times a number, it becomes the same as 7 is subtracted from four times the same number. This fact can be represented as 3x + 5= 4x – 7.

Solution:-

Consider the given equation, x + 7 = 10.

Transpose 7 to RHS then it becomes -7.

x = 10 – 7

x = 3

Solution:-

Consider the given equation, 3x = 12

x = 12/3

x = 4

Then,

= x – 0

= 4 – 0

= 4

Solution:-

Consider the given equation, 2x = 2

x = 2/2

x = 1

Then,

= x – 1

= 1 – 1

= 0

Solution:-

Consider the given eqaution, x/2 = 6

x = 6 × 2

x = 12

Then,

= x –

= 12 – (- 3)

= 12 + 3

= 15

x – (-3) = 15; when x/2 = 6

Solution:-

Consider the given equation, x + 15 = 19

Transpose 15 to RHS then it becomes -15.

x = 19 – 15

x = 4

Solution:-

Finding the value of a variable in a linear equation that satisfies the equation is called a root of the equation.

Solution:-

Any term of an equation may be transposed from one side of the equation to the other side of the equation by changing the sign of the term.