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NCERT Exemplar · Class 7 · Maths

Chapter 2: Fractions and Decimals

Practice each question, then open the answer or worked solution.

Questions

61 questions
Q1Written answer

(2/5) × NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 1 is equal to:

(a) 26/25 (b) 52/25 (c) 2/5 (d) 6

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Worked solution

Solution:-

(b) 52/25

First, we have to convert the mixed fraction into an improper fraction

NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 2
= 26/5

Then, (2/5) × (26/5)

= 52/25

Q2Written answer

3¾ ÷ ¾ is equal to:

(a) 3 (b) 4 c) 5 (d) 45/16

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Worked solution

Solution:-

c) 5

First, we have to convert the mixed fraction into improper fraction 3¾ = 15/4

Then, 15/4 ÷ ¾

= (15/4)/ (¾)

= (15/4) × (4/3)

= (15 × 4)/ (4 ×3)

= (5 × 1)/ (1 ×1)

= 5

Q3Written answer

A ribbon of length 5¼ m is cut into small pieces, each of length ¾m. The number of pieces will be:

(a) 5 (b) 6 (c) 7 (d) 8

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Worked solution

Solution:-

(c) 7

First, we have to convert the mixed fraction into improper fraction 5¼ = 21/4

Then, 21/4 ÷ ¾

= (21/4)/ (¾)

= (21/4) × (4/3)

= (21 × 4)/ (4 × 3)

= (7 × 1)/ (1 × 1)

= 7

Q4Written answer

The ascending arrangement of (2/3), (6/7), (13/21) is:

(a) 6/7, 2/3, 13/21 (b) 13/21, 2/3, 6/7

(c) 6/7, 13/21, 2/3 (d) 2/3, 6/7, 13/21

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Worked solution

Solution:-

(b) 13/21, 2/3, 6/7

LCM of 21, 3, 7 = 21

Now, let us change each of the given fractions into an equivalent fraction having 21 as the denominator.

Clearly,

(13/21) < (14/21) < (18/21)

Hence,

(13/21) < (2/3) < (6/7)

Hence, the given fractions in ascending order are (13/21), (2/3), (6/7)

Q5Written answer

Reciprocal of the fraction 2/3 is:

(a) 2 (b) 3 (c) 2/3 (d) 3/2

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Worked solution

Solution:-

(d) 3/2

The reciprocal of a non-zero fraction is obtained by interchanging its numerator and denominator.

Q6Written answer

The product of 11/13 and 4 is:

NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 3

NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 4

8. Pictorial representation of 3 × 2/3 is:

NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 5

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Worked solution

Solution:-

NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 6

In the above figure, three circles are divided into 3 equal parts.

Out of 3 equal parts 2 equal parts are hatched.

Q7Multiple choice

The product of \[{\mathbf{3}}\] and ${\mathbf{4}}\dfrac{{\mathbf{2}}}{{\mathbf{5}}}$ is.:

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Correct option: C
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Worked solution

Ans: Option (c) is correct.

First, we have to convert the mixed fraction into improper fraction $4\dfrac{2}{5} = \dfrac{{22}}{5}$

$ \Rightarrow 3 \times 4\dfrac{2}{5} = 3 \times \dfrac{{22}}{5}=\dfrac{{66}}{5}$

$= 13\dfrac{1}{5}$


Q8Multiple choice

Pictorial representation of ${\mathbf{3}} \times \dfrac{{\mathbf{2}}}{{\mathbf{3}}}$ is:


seo images

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Correct option: B
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Worked solution

Ans: Option (b) is correct.

$3 \times \dfrac{2}{3} = \dfrac{2}{3} + \dfrac{2}{3} + \dfrac{2}{3}$

Therefore, pictorial representation is


seo images
Q9Written answer

1/5 ÷ 4/5 equal to:

(a) 4/5 (b) 1/5 (c) 5/4 (d) ¼

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Worked solution

Solution:-

(d) ¼

= 1/5 ÷ 4/5

= (1/5)/ (4/5)

= (1/5) × (5/4)

= 5/20 … [divide both numerator and denominator by 5]

= ¼

Q10Written answer

The product of 0.03 × 0.9 is:

(a) 2.7 (b) 0.27 (c) 0.027 (d) 0.0027

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Worked solution

Solution:-

(c) 0.027

0.03 × 0.9 can be written as = (3/100) × (9/10)

= 27/1000

On dividing a decimal by 1000, the decimal point is shifted to the left by three places.

= 0.027