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NCERT Exemplar · Class 7 · Maths

Chapter 2: Fractions and Decimals

Practice each question, then open the answer or worked solution.

Questions

61 questions
Q11Written answer

(5/7) ÷ 6 is equal to:

(a) 30/7 (b) 5/42 (c) 30/42 (d) 6/7

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Worked solution

Solution:-

(b) 5/42

= 5/7 ÷ 6/1

= (5/7)/ (6/1)

= (5/7) × (1/6)

= 5/42

Q12Written answer


NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 7÷ 9/2 is equal to:

(a) 31/6 (b) 1/27 (c)
NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 8 (d) 31/27

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Worked solution

Solution:-

(d) 31/27

First, we have to convert the mixed fraction into an improper fraction
NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 9= 31/6

Then,

= 31/6 ÷ 9/2

= (31/6)/ (9/2)

= (31/6) × (2/9)

= (31/3) × (1/9)

= 31/27

Q13Written answer

Which of the following represents 1/3 of 1/6?

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Worked solution

Solution:-

(a) (1/3) + (1/6) (b) (1/3) – (1/6)

(c) (1/3) × (1/6) (d) (1/3) ÷ (1/6)

Solution:-

(c) (1/3) × (1/6)

Q14Written answer

3/7 of 2/5 is equal to

(a) 5/12 (b) 5/35 (c) 1/35 (d) 6/35

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Worked solution

Solution:-

(d) 6/35

3/7 of 2/5 is equal to = (3/7) × (2/5)

= 6/35

Q15Written answer

One packet of biscuits requires 2½ cups of flour and NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 10 cups of sugar. The estimated total quantity of both ingredients used in 10 such packets of biscuits will be

(a) less than 30 cups

(b) between 30 cups and 40 cups

(c) between 40 cups and 50 cups

(d) above 50 cups

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Worked solution

Solution:-

(c) between 40 cups and 50 cups

From the question, it is given that,

One packet of biscuits requires 2½ cups of flour = 5/2

One packet of biscuits requires NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 11 cups of sugar. = 5/3

Total ingredients for one packet of biscuits = (5/2) + (5/3)

= (15 + 10)/6

= 25/6

Then, the total quantity of both ingredients used in 10 such packets of biscuits = 10 × (25/6)

= 5 × (25/3)

= 125/3

=
NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 12

Q16Written answer

The product of 7 and 6¾ is

(a) 42¼ (b) 47¼ (c) 42¾ (d) 47¾

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Worked solution

Solution:-

(b) 47¼

First, we have to convert the mixed fraction into improper fraction 6¾ = 27/4

= 7 × (27/4)

= 189/4

= 47¼

Q17Written answer

On dividing 7 by 2/5, the result is

(a) 14/2 (b) 35/4 (c) 14/5 (d) 35/2

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Worked solution

Solution:-

(d) 35/2

= 7/ (2/5)

= 7 × (5/2)

= 35/2

Q18Written answer

NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 13÷ 5 is equal to

(a) 8/15 (b) 40/3 (c) 40/5 (d) 8/3

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Worked solution

Solution:-

(a) 8/15

First, we have to convert the mixed fraction into an improper fraction
NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 14= 8/3

Then,

= (8/3) ÷ 5

= (8/3)/(5/1)

= (8/3) × (1/5)

= 8/15

Q19Written answer

4/5 of 5 kg apples were used on Monday. The next day 1/3 of what was left was used. Weight (in kg) of apples left now is

(a) 2/7 (b) 1/14 (c) 2/3 (d) 4/21

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Worked solution

Solution:-

(c) 2/3

From the question, it is given that,

4/5 of 5 kg apples were used on Monday = (4/5) × 5

= 20/5

= 4 kg

Then,

The next day 1/3 of what was left was used = (1/3) × 1

= 1/3 kg

So, the Weight (in kg) of apples left now is = 1 – (1/3)

= (3 – 1)/3

= 2/3 kg of apples

Q20Written answer

The picture

NCERT Exemplar Class 7 Maths Solutions Chapter 2 Image 15

Interprets

(a) ¼ ÷ 3 (b) 3 × ¼ (c) ¾ × 3 (d) 3 ÷ ¼

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Worked solution

Solution:-

(b) 3 × ¼

From the given picture, ¼ + ¼ + ¼ = ¾

In Questions 21 to 44, fill in the blanks to make the statements true.