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NCERT Exemplar · Class 7 · Maths

Chapter 1: Integers

Practice each question, then open the answer or worked solution.

Questions

83 questions
Q51Written answer

[12 × ( – 7)] × 5 = ___ × [(– 7) × ___ ]

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Worked solution

12, 5:

Q52Written answer

23 × ( – 99) = ___ × ( – 100 + ___ ) = 23 × ___ + 23 × ___

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Worked solution

23, 1, -100, 1:

23 × ( – 99) = 23 × ( – 100 + 1 ) = 23 × (-100) + 23 × 1 (Distributive property of integers)

Q53Written answer

___ × ( – 1) = – 35

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Worked solution

35:

35 × ( – 1) = – 35

Q54Written answer

____ × ( – 1) = 47

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Worked solution

-47:

-47 × ( – 1) = 47 (product of even number of negative integers is a positive integer)

Q55Written answer

88 × ___ = – 88

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Worked solution

-1:

88 × -1 = – 88

Q56Written answer

___ × (–93) = 93

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Worked solution

-1:

-1 × (–93) = 93

Q57Written answer

( – 40) × __ = 80

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-2:

( – 40) × (-2) = 80

Q58Written answer

___ × (–23) = – 920

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Worked solution

40:

40 × (–23) = – 920

Q59Written answer

When we divide a negative integer by a positive integer, we divide them as whole numbers and put a ______ sign before quotient.

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Worked solution

negative

Q60Written answer

When –16 is divided by _________ the quotient is 4.

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Worked solution

-4:

Let -16 be divided by x and the quotient is 4

So, -16/x = 4

x = -4