Q41Written answer
(– 23) × (42) = (– 42) × _____
Show solutionHide solution
Worked solution
23:
(– 23) × (42) = (– 42) × 23 = 966
NCERT Exemplar · Class 7 · Maths
Chapter 1: Integers
Practice each question, then open the answer or worked solution.
Questions
83 questionsQ42Written answer
While multiplying a positive integer and a negative integer, we multiply them as ________ numbers and put a ________ sign before the product.
Show solutionHide solution
Worked solution
whole, negative
Q43Written answer
If we multiply ________ number of negative integers, then the resulting integer is positive.
Show solutionHide solution
Worked solution
even
Q44Written answer
If we multiply six negative integers and six positive integers, then the resulting integer is _______
Show solutionHide solution
Worked solution
positive integer
When even number of negative integers are multiplied the resulting integer is positive and when six positive integers are multiplied the resulting integer is also a positive.
Q45Written answer
If we multiply five positive integers and one negative integer, then the resulting integer is _______.
Show solutionHide solution
Worked solution
negative
When odd number of negative integers are multiplied the resulting integer is negative. Also, when a negative and positive integer are multiplied the resulting integer is negative.
Q46Written answer
_______ is the multiplicative identity for integers.
Show solutionHide solution
Worked solution
1
1 is the multiplicative identity for integers.
i.e. 1 x a = a
Q47Written answer
We get additive inverse of an integer a when we multiply it by _________.
Show solutionHide solution
Worked solution
-1:
a x (-1) = -a = additive inverse of (a)
Q48Written answer
( – 25) × ( – 2) =
Show solutionHide solution
Worked solution
50:
( – 25) × ( – 2) = 25 x 2 = 50
Q49Written answer
(– 5) × ( – 6) × ( – 7) =
Show solutionHide solution
Worked solution
-210:
(– 5) × ( – 6) × ( – 7) = – (5 × 6 × 7) = -210
Q50Written answer
3 × ( – 1) × ( – 15) =
Show solutionHide solution
Worked solution
45:
3 × ( – 1 ) × ( – 15) = (-3) x (-15) = 45