3/5 = [ ]/20
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Solution:-
Let us assume the missing number be y.
Then, (3/5) = (y/20)
By cross multiplication, we get,
(3 × 20)/5 = y
y = 60/5
Divide both the numerator and denominator by 5.
y = 12
Therefore, 3/5 = [12]/20
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3/5 = [ ]/20
Solution:-
Let us assume the missing number be y.
Then, (3/5) = (y/20)
By cross multiplication, we get,
(3 × 20)/5 = y
y = 60/5
Divide both the numerator and denominator by 5.
y = 12
Therefore, 3/5 = [12]/20
[ ]/18 = 2/9
Solution:-
Let us assume the missing number is y.
Then, y/18 = 2/9
By cross multiplication, we get,
y = (2 × 18)/9
y = 36/9
Divide both the numerator and denominator by 9.
y = 4
Therefore, [4]/18 = 2/9
8/[ ] = 3.2/4
Solution:-
Let us assume the missing number is y.
Then, 8/y = 3.2/4
By cross multiplication, we get,
y = (8 × 4)/3.2
y = 32/3.2
y = 320/32
Divide both the numerator and denominator by 32.
y = 10
Therefore, 8/[10] = 3.2/4
[ ]/45 = 16/40 = 24/[ ]
Solution:-
Consider the first two ratios [ ]/45 = 16/40
Let us assume the missing number by P
Then, P/45 = 16/40
By cross multiplication, we get,
P = (16 × 45)/40
P = 720/40
P = 72/4
Divide both the numerator and denominator by 4.
P = 18
Therefore, [18]/45 = 16/40
Now, consider the last two ratios, 16/40 = 24/[ ]
Let us assume the missing number be Q,
Then, 16/40 = 24/Q
By cross multiplication, we get,
Q = (24 × 40)/16
Q = 960/16
Divide both the numerator and denominator by 16.
Q = 60
Therefore, 16/40 = 24/[60]
16/36 = [ ]/63 = 36/[ ] = [ ]/117
Solution:-
Consider the first two ratios 16/36 = [ ]/63
Let us assume the missing number is P
Then, 16/36 = P/63
By cross multiplication, we get,
P = (16 × 63)/36
P = 1008/36
Divide both the numerator and denominator by 36.
P = 28
Therefore, 16/36 = [28]/63
Now, consider the middle two ratios, 28/63 = 36/[ ]
Let us assume the missing number is Q,
Then, 28/63 = 36/Q
By cross multiplication, we get,
Q = (36 × 63)/28
Q = 2268/28
Divide both the numerator and denominator by 28.
Q = 81
Therefore, 28/63 = 36/[81]
Consider the last two ratios 36/81 = [ ]/117
Let us assume the missing number is R
Then, 36/81 = R/117
By cross multiplication, we get,
P = (36 × 117)/81
P = 4212/81
Divide both the numerator and denominator by 81.
P = 52
Therefore, 36/81 = [52]/117
So, 16/36 = [28]/63 = 36/[81] = [52]/117
In questions 16 to 34, state whether the given statements are true (T) or false (F).
3/8 = 15/40
Solution:-
True.
Consider the two fractions, 3/8 = 15/40
15/40 is further simplified by dividing both the numerator and denominator by 5, and we get,
= 3/8
Therefore, 3/8 = 3/8
4 : 7 = 20 : 35
Solution:-
True.
Consider the two ratios, 4: 7 = 20: 35
= 4/7 = 20/35
20/35 is further simplified by dividing both the numerator and denominator by 5 we get,
= 4/7
Therefore, 4/7 = 4/7
0.2 : 5 = 2 : 0.5
Solution:-
False.
Consider the two ratios, 0.2: 5 = 2: 0.5
0.2/5 = 2/0.5
0.04 ≠ 4
3 : 33 = 33 : 333
Solution:-
False.
Consider the two ratios 3: 33 = 33: 333
3/33 = 33/333
0.0909 ≠ 0.0990
15m : 40m = 35m : 65m
Solution:-
False.
Consider the two ratios 15m : 40m = 35m : 65m
15/40 = 35/65
15/40 is further simplified by dividing both the numerator and denominator by 5 we get,
= 3/8
35/65 is further simplified by dividing both the numerator and denominator by 5 we get,
= 7/13
Hence, 3/8 ≠ 7/13
Therefore, 15/40 ≠ 35/65