Your cart is empty.
Practice each question, then open the answer or worked solution.
The ratio of 8 books to 20 books is
(A) 2 : 5 (B) 5 : 2 (C) 4 : 5 (D) 5 : 4
Solution:-
(A) 2 : 5
The comparison of two numbers or quantities by division is known as the ratio. Symbol ‘:’ is used to denote ratio.
The ratio of 8 books to 20 books = 8/20
Divide both the numerator and denominator by 4.
= 2/5
Therefore, the ratio of 8 books to 20 books = 2 : 5
The ratio of the number of sides of a square to the number of edges of a cube is
(A) 1 : 2 (B) 3 : 2 (C) 4 : 1 (D) 1 : 3
Solution:-
(D) 1 : 3
We know that number of sides in a square = 4, and the number of edges in a cube = 12
So, the ratio of sides to edges = 4/12
Divide both the numerator and denominator by 4.
= 1/3
Therefore, the ratio of sides to edges = 1 : 3
A picture is 60cm wide and 1.8m long. The ratio of its width to its perimeter in the lowest form is
(A) 1 : 2 (B) 1 : 3 (C) 1 : 4 (D) 1 : 8
Solution:-
(D) 1 : 8
From the question, it is given that,
Width of a picture = 60 cm
Length of a picture = 1.8 m
We know that 1 m = 100 cm
So, 1.8 m = 180 cm
Perimeter of rectangle = 2 (length + breadth)
= 2 (180 + 60)
= 2 (240)
= 480
Therefore, The ratio of its width to its perimeter in lowest form = 60/480
Divide both the numerator and denominator by 20.
= 3/24
Again, divide both the numerator and denominator by 3.
= 1/8
= 1 : 8
Neelam’s annual income is Rs. 288000. Her annual savings amount to Rs. 36000. The ratio of her savings to her expenditure is
(A) 1 : 8 (B) 1 : 7 (C) 1 : 6 (D) 1 : 5
Solution:-
(B) 1 : 7
From the question, it is given that,
Neelam’s annual income is ₹ 288000
Her annual savings amount to ₹ 36000
So, Neelam’s expenditure = 288000 – 36000
= ₹ 252000
Then, the ratio of her savings to her expenditure = 36000/252000
= 36/252
Divide both the numerator and denominator by 12.
= 3/21
Again, divide both the numerator and denominator by 3.
= 1/7
Therefore, the ratio of her savings to her expenditure = 1 : 7
Mathematics textbook for Class VI has 320 pages. The chapter ‘symmetry’ runs from page 261 to page 272. The ratio of the number of pages of this chapter to the total number of pages of the book is
(A) 11 : 320 (B) 3 : 40 (C) 3 : 80 (D) 272 : 320
Solution:-
(C) 3 : 80
From the question, it is given that,
Total number of pages in the Mathematics textbook for Class VI = 320 pages
The chapter ‘symmetry’ runs from page 261 to page 272
Number of pages containing symmetry chapter = 12
So, the ratio of the number of pages of symmetry chapter to the total number of pages of the book is,
= 12/320
Divide both the numerator and denominator by 2.
= 6/160
Again, divide both the numerator and denominator by 2.
= 3/80
Therefore, the ratio of the number of pages of this chapter to the total number of pages of the book is 3: 80.
In a box, the ratio of red marbles to blue marbles is 7:4. Which of the following could be the total number of marbles in the box?
(A) 18 (B) 19 (C) 21 (D) 22
Solution:-
(D) 22
From the question, it is given that the ratio of red marbles to blue marbles is 7:4.
Now, let us assume the common factor of 7 and 4 be x.
So, the total number of marbles in the box = 7x + 4x = 11x
Hence, the number of marbles in the box is a multiple of 11.
Therefore, 11 × 2 = 22
On a shelf, books with green covers and those with brown covers are in the ratio 2:3. If there are 18 books with green covers, then the number of books with brown covers is
(A) 12 (B) 24 (C) 27 (D) 36
Solution:-
(C) 27
From the question, it is given that,
On a shelf, books with green covers and those with brown covers are in the ratio 2:3
There are 18 books with green cover
So, let us assume the common factor of 2 and 3 be x.
Then, 2x = 18
x = 18/2
Divide both the numerator and denominator by 2.
x = 9
Therefore, the number of books with brown covers is = 3x = 3 × 9
= 27
The greatest ratio among the ratios 2 : 3, 5 : 8, 75 : 121 and 40 : 25 is
(A) 2 : 3 (B) 5 : 8 (C) 75 : 121 (D) 40 : 25
Solution:-
(D) 40 : 25
Consider the given ratios, 2 : 3, 5 : 8, 75 : 121 and 40 : 25.
The simplified form of 2: 3 = 2/3 = 0.67
The simplified form of 5 : 8 = 5/8 = 0.625
Simplified form of 75: 121 = 75/121 = 0.61
The simplified form of 40: 25 = 40/25 = 1.6
Therefore, the greatest ratio among the given ratios is 40 : 25
There are ‘b’ boys and ‘g’ girls in a class. The ratio of the number of boys to the total number of students in the class is:
(A) b/(b + g) (B) g/(b + g) (C) b/g (D) (b + g)/b
Solution:-
(A) b/(b + g)
From the question,
Number of boys in the class = b
Number of girls in the class = g
Total number of students in the class = b + g
Therefore, the ratio of the number of boys to the total number of students in the class
= b/(b + g)
If a bus travels 160 km in 4 hours and a train travels 320km in 5 hours at uniform speeds, then the ratio of the distances travelled by them in one hour is
(A) 1 : 2 (B) 4 : 5 (C) 5 : 8 (D) 8 : 5
Solution:-
(C) 5 : 8
From the question, it is given that,
The bus travels 160 km in 4 hours
The train travels 320 km in 5 hours
So, distance travelled by bus in an hour = 160/4 = 40 km/h
Distance travelled by train in an hour = 320/5 = 64 km/h
Then the ratio of the distances travelled by them in one hour is = 40/64
Divide both the numerator and denominator by 8.
= 5/8
Therefore, the ratio of the distances travelled by them in one hour is 5: 8.
In questions 11 to 15, find the missing number in the box [ ] in each of the proportions: