My Cart
Your Cart 0

    Your cart is empty.

  • Total (Amount) ₹0.00
NCERT · Class 6 · Maths

Chapter 3: Playing with Numbers

Practice each question, then open the answer or worked solution.

Exercise 3.6

Textbook page 63 · 3 questions
Q1Written answer

Find the HCF of the following numbers :

(a) 18, 48

(b) 30, 42

(c) 18, 60

(d) 27, 63

(e) 36, 84

(f) 34, 102

(g) 70, 105, 175

(h) 91, 112, 49

(i) 18, 54, 81

(j) 12, 45, 75

Show solutionHide solution
Worked solution

(a) 18, 48

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 1

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 2

18 = 2 × 3 × 3

48 = 2 × 2 × 2 × 2 × 3

HCF = 2 × 3 = 6

Therefore the HCF of 18, 48 is 6

(b) 30, 42

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 3

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 4

30 = 2 × 3 × 5

42 = 2 × 3 × 7

HCF = 2 × 3 = 6

Therefore the HCF of 30, 42 is 6

(c) 18, 60

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 5

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 6

18 = 2 × 3 × 3

60 = 2 × 2 × 3 × 5

HCF = 2 × 3 = 6

Therefore the HCF of 18, 60 is 6

(d) 27, 63

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 7

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 8

27 = 3 × 3 × 3

63 = 3 × 3 × 7

HCF = 3 × 3 = 9

Therefore the HCF of 27, 63 is 9

(e) 36, 84

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 9

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 10

36 = 2 × 2 × 3 × 3

84 = 2 × 2 × 3 × 7

HCF = 2 × 2 × 3 = 12

Therefore the HCF of 36, 84 is 12

(f) 34, 102

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 11

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 12

34 = 2 × 17

102 = 2 × 3 × 17

HCF = 2 × 17 = 34

Therefore the HCF of 34, 102 is 34

(g) 70, 105, 175

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 13

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 14

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 15

70 = 2 × 5 × 7

105 = 3 × 5 × 7

175 = 5 × 5 × 7

HCF = 5 × 7 = 35

Therefore the HCF of 70, 105, 175 is 35

(h) 91, 112, 49

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 16

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 17

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 18

91 = 7 × 13

112 = 2 × 2 × 2 × 2 × 7

49 = 7 × 7

HCF = 7

Therefore the HCF of 91, 112, 49 is 7

(i) 18, 54, 81

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 -19

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 20

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 21

18 = 2 × 3 × 3

54 = 2 × 3 × 3 × 3

81 = 3 × 3 × 3 × 3

HCF = 3 × 3 = 9

Therefore the HCF of 18, 54, 81 is 9

(j) 12, 45, 75

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 22

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 23

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 24

12 = 2 × 2 × 3

45 = 3 × 3 × 5

75 = 3 × 5 × 5

HCF = 3

Therefore the HCF of 12, 45, and 75 is 3

 

Q2Written answer

What is the HCF of two consecutive

(a) numbers?

(b) even numbers?

(c) odd numbers?

Show solutionHide solution
Worked solution

(a) The HCF of two consecutive numbers is 1

Example: The HCF of 2 and 3 is 1

(b) The HCF of two consecutive even numbers is 2

Example: The HCF of 2 and 4 is 2

(c) The HCF of two consecutive odd numbers is 1

Example: The HCF of 3 and 5 is 1

Q3Written answer

HCF of co-prime numbers 4 and 15 was found as follows by factorisation:

4 = 2 × 2 and 15 = 3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

Show solutionHide solution
Worked solution

No. The answer is not correct. The correct answer is 1.