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NCERT · Class 6 · Maths

Chapter 3: Playing with Numbers

Practice each question, then open the answer or worked solution.

Exercise 3.5

Textbook page 61 · 12 questions
Q1Multiple choice

Which of the following statements is true?

(e) If two numbers are co-primes, at least one of them must be prime.

(f) All numbers which are divisible by 4 must also be divisible by 8.

(g) All numbers which are divisible by 8 must also be divisible by 4.

(h) If a number exactly divides two numbers separately, it must exactly divide their sum.

(i) If a number exactly divides the sum of two numbers, it must exactly divide the two numbers separately.

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Correct option: A
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Worked solution

(a) False, 6 is divisible by 3 but is not divisible by 9

(b) True, as 9 = 3 × 3. Hence, if a number is divisible by 9, it will also be divisible by 3

(c) False. Since 30 is divisible by both 3 and 6 but is not divisible by 18

(d) True, as 9 × 10 = 90. Hence, if a number is divisible by both 9 and 10 then it is divisible by 90

(e) False. Since 15 and 32 are co-primes and also composite numbers

(f) False, as 12 is divisible by 4 but is not divisible by 8

(g) True, as 2 × 4 = 8. Hence, if a number is divisible by 8, it will also be divisible by 2 and 4

(h) True, as 2 divides 4 and 8, and it also divides 12 (4 + 8 = 12)

(i) False, since 2 divides 12 but it does not divide 7 and 5

Q2Written answer

Here are two different factor trees for 60. Write the missing numbers.

(a)

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 - 1

(b)
NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 - 2

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Worked solution

(a) Since 6 = 2 × 3 and 10 = 5 × 2

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 - 3

(b) Since 60 = 30 × 2

30 = 10 × 3

10 = 5 × 2

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 - 4

Q3Written answer

Which factors are not included in the prime factorisation of a composite number?

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Worked solution

1 and the number itself are not included in the prime factorisation of a composite number.

Q4Written answer

Write the greatest 4-digit number and express it in terms of its prime factors.

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Worked solution

The greatest four-digit number is 9999

Therefore 9999 = 3 × 3 × 11 × 101
NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 - 5

Q5Written answer

Write the smallest 5-digit number and express it in the form of its prime factors.

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Worked solution

The smallest five-digit number = 10000

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 - 6

10000 = 2 × 2 × 2 × 2 × 5 × 5 × 5 × 5

Q6Written answer

Find all the prime factors of 1729 and arrange them in ascending order. Now state the relation, if any, between two consecutive prime factors.

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Worked solution

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 - 7

1729 = 7 × 13 × 19

13 – 7 = 6

19 – 13 = 6

Hence, the difference between two consecutive prime factors is 6.

Q7Written answer

The product of three consecutive numbers is always divisible by 6. Verify this statement with the help of some examples.

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Worked solution

(i) 2 × 3 × 4 = 24 which is divisible by 6

(ii) 5 × 6 × 7 = 210 which is divisible by 6

Q8Written answer

The sum of two consecutive odd numbers is divisible by 4. Verify this statement with the help of some examples.

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Worked solution

(i) 5 + 3 = 8 which is divisible by 4

(ii) 7 + 9 = 16 which is divisible by 4

(iii) 13 + 15 = 28 which is divisible by 4

Q9Multiple choice

In which of the following expressions has prime factorisation been done?

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Correct option: A
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Worked solution

(a) 24 = 2 × 3 × 4

Since 4 is composite. Hence, prime factorisation has not been done

(b) 56 = 7 × 2 × 2 × 2

Since all the factors are prime. Hence, prime factorisation has been done

(c) 70 = 2 × 5 × 7

Since all the factors are prime. Hence, prime factorisation has been done

(d) 54 = 2 × 3 × 9

Since 9 is composite. Hence prime factorisation has not been done

Q10Written answer

Determine if 25110 is divisible by 45. [Hint: 5 and 9 are co-prime numbers. Test the divisibility of the number by 5 and 9].

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Worked solution

45 = 5 × 9

1, 5 are factors of 5

1, 3, 9 are factors of 9

Hence, 5 and 9 are co-prime numbers

The last digit of 25110 is 0. Hence, it is divisible by 5

Sum of digits 25110

2 + 5 + 1 + 1 + 0

= 9

Since the sum of digits of 25110 is divisible by 9. Hence, 25110 is divisible by 9

Since the number is divisible by both 5 and 9

Therefore 25110 is divisible by 45