Simple Harmonic Motion - Mechanics - Physics Previous Year Questions

A particle executes a linear SHM with an amplitude of 4 cm. At the mean position the velocity of the particle is 10 cm/s. What is the displacement of the particle when its speed becomes 5 cm/s?

Two spring of force constant \(k_1\) and \(k_2\) are configured as the figure given below

The angular frequency of this configuration is

The function \(y = \log \omega t\) can represent

A particle is performing simple harmonic motion. Equation of its motion is \(x = 5\sin \left( {4t - {\pi \over 6}} \right),x\) being the displacement from mean position. Velocity (in ms\(^{-1}\)) of the particle at the instant when its displacement is 3, will be

A circular disc of mass \(20 \mathrm{~kg}\), having radius \(10 \mathrm{~cm}\) is suspended by a wire attached to its centre. The wire is twisted by rotating the disc and released. The time period of torsional oscillations is found to be \(1 \mathrm{~s}\). The torsional spring constant of the wire is

A body is executing SHM. When its displacements from the mean position are \(4 \mathrm{~cm}\) and \(5 \mathrm{~cm}\) it has velocity \(10 \mathrm{~cms}^{-1}\) and \(8 \mathrm{~cms}^{-1}\) respectively. Its periodic time \(\mathrm{t}\) is

A particle executes a simple harmonic motion of amplitude \(\mathrm{A}\). The distance from the mean position at which its kinetic energy is equal to its potential energy is

The phase difference between displacement and velocity of a particle in simple harmonic motion is

An object of mass 10 g executes SHM along the $x$-axis with frequency of $\left(\frac{10}{\pi}\right) \mathrm{Hz}$. At the point $x=2 \mathrm{~cm}$ the object has KE 1.2 J and PE 0.4 J . The amplitude of oscillation is

Force constant of interatomic bond, in a certain element, is $7.1 \mathrm{Nm}^{-1}$. If the atom oscillates in SHM in a certain direction, what is its frequency?

Given: Mole weight of the given element is 108 g and Avagadro's number $=6.023 \times 10^{23} \mathrm{~g} \mathrm{~mol}^{-1}$