Capacitor - Electromagnetism - Physics Previous Year Questions

Two capacitors \(C_1\) and \(C_2\) are charged to 120 V and 200 V, respectively. When they are connected in parallel, it is found that potential on each one of them is zero. Therefore,

If R and C denote resistance and capacitance of a material, then the dimension of CR will be :

In the network shown in figure, the equivalent capacitance between points P and Q is

In the figure, first the capacitors are fully charged by closing the key \(\mathrm{K}\). Then after opening the Key a dielectric material with dielectric constant 2 is filled in the space between the plates of both the capacitor. At this state the ratio of the Charge on the capacitor \(C_1\) to that of \(C_2\) is:

Figure below shows a network of resistors, cells, and a capacitor at steady state.

What is the current through the resistance 4 \(\Omega\) ?

The figure shows a network of five capacitors connected to a 20 V battery. Calculate the charge acquired by each 10 \(\mu\)F capacitor.

A parallel plate capacitor having a dielectric constant 5 and dielectric strength \(10^6 \mathrm{~V} \mathrm{~m}^{-1}\) is to be designed with voltage rating of \(2 \mathrm{~kV}\). The field should never exceed \(10 \%\) of its dielectric strength. To have the capacitance of \(60 \mathrm{~pF}\) the minimum area of the plates should be

A parallel plate capacitor is filled by a dielectric whose relative permittivity varies with the applied voltage (U) as \(\epsilon=2 U\). A similar capacitor with no dielectric is charged to \(U_0=78 \mathrm{~V}\). It is then connected to the uncharged capacitor with the dielectric. Find the final voltage on the capacitors.

A network of capacitors is as shown below. If the voltage supply is 100 V , find the energy stored in the $6 \mu \mathrm{~F}$ capacitor.

$C_1=3 \mu F, C_2=6 \mu F, C_3=3 \mu F$ and $C_4=4 \mu F$

A dielectric of dielectric constant \(K\) is introduced such that half of its area of a capacitor of capacitance \(C\) is occupied by it. The new capacity is

If \(C\) be the capacitance and \(V\) be the electric potential, then the dimensional formula of \(\mathrm{CV}^2\) is

A capacitor of capacity \(2 ~\mu \mathrm{F}\) is charged upto a potential \(14 \mathrm{~V}\) and then connected in parallel to an uncharged capacitor of capacity \(5 ~\mu \mathrm{F}\). The final potential difference across each capacitor will be

In the figure below, the capacitance of each capacitor is \(3 \mu \mathrm{F}\). The effective capacitance between \(A\) and \(B\) is

What is the charge on $15 \mu F$ in the circuit given?

A capacitor of capacitance $8 \mu \mathrm{~F}$ is fully charged by connecting it to a source of 200 V . It is then disconnected from the supply and connected to an uncharged capacitor of capacitance $4 \mu \mathrm{~F}$. The electrostatic energy lost in this sharing is: