Difficulty distribution
How the classified questions are distributed by difficulty.
Your cart is empty.
Practice Chemical Equilibrium - Physical Chemistry - Chemistry previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
Every graph below is calculated only from this selection.
Year-wise coverage for Chemical Equilibrium. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| COMEDK 2025 AFTERNOON SHIFT | 2025 | 1 | View paper |
| COMEDK 2025 EVENING SHIFT | 2025 | 2 | View paper |
| COMEDK 2024 AFTERNOON SHIFT | 2024 | 1 | View paper |
| COMEDK 2024 EVENING SHIFT | 2024 | 1 | View paper |
| COMEDK 2023 EVENING SHIFT | 2023 | 1 | View paper |
| COMEDK 2023 Morning Shift | 2023 | 1 | View paper |
| COMEDK 2022 | 2022 | 2 | View paper |
| COMEDK 2021 | 2021 | 3 | View paper |
| COMEDK 2020 | 2020 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
\(2S{O_2}(g) + {O_2}(g)\buildrel {{V_2}{O_5}} \over \[\rightleftharpoons\) is an example for\]
In the chemical reaction,
N\(_2\) + 3H\(_2\) \(\rightleftharpoons\) 2NH\(_3\) at equilibrium point.
For the equilibrium,
2NOCl(g) \(\rightleftharpoons\) 2NO(g) + Cl\(_2\)(g),
the value of the equilibrium constant, \(K_C\) is 3.75 \(\times\) 10\(^{-6}\) at 1069 K. The value of \(K_p\) for the reaction at this temperature will be
In the equilibrium, \(AB\rightleftharpoons A+B\), if the equilibrium concentration of A is double, then equilibrium concentration of B will be
For the reaction, H\(_2\)(g) + I\(_2\)(g) \(\rightleftharpoons\) 2HI(g) the position of equilibrium can be shifted to the right by
The equilibrium constant, \(K_C\) for \(3C_2H_2(g) \rightleftharpoons C_6H_6(g)\) is 4 L\(^2\)mol\(^{-2}\). If the equilibrium concentration of benzene is 0.5 mol\(^{-1}\) than what is the value of concentration of ethylene?
The equilibrium constants for the reactions \(a, b\), and \(c\) are as given:
a) \(\mathrm{N}_2+3 \mathrm{H}_2=2 \mathrm{NH}_3: \mathbf{K}_1\)
b) \(\mathrm{N}_2+\mathrm{O}_2=2 \mathrm{NO}: \mathrm{K}_2\)
c) \(2 \mathrm{H}_2+\mathrm{O}_2=2 \mathrm{H}_2 \mathrm{O}: \mathbf{K}_3\)
What would be the Equilibrium constant for the reaction:
$$4 \mathrm{NH}_3+5 \mathrm{O}_2=4 \mathrm{NO}+6 \mathrm{H}_2 \mathrm{O} ; \mathbf{K}_{\mathbf{x}}$$
\(\mathrm{S}_8\) on heating at a temperature above \(1000 \mathrm{~K}\), changes to \(\mathrm{S}_2\). When 1 mole of \(\mathrm{S}_8\) is heated above \(1000 \mathrm{~K}\), the pressure falls by \(32 \%\) at equilibrium. The equilibrium constant for the conversion is:
At \(700 \mathrm{~K}\), the Equilibrium constant value for the formation of \(\mathrm{HI}\) from \(\mathrm{H}_2\) and \(\mathrm{I}_2\) is 49.0 . 0.7 mole of \(\mathrm{HI}(\mathrm{g})\) is present at equilibrium. What will be the concentrations of \(\mathrm{H}_2\) and \(\mathrm{I}_2\) gases if we initially started with \(\mathrm{HI}(\mathrm{g})\) and allowed the reaction to reach equilibrium at the same temperature?
Consider the reaction
$$\mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s})+3 \mathrm{CO}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{Fe}(\mathrm{l})+3 \mathrm{CQ}_2(\mathrm{~g})$$
In accordance with Le-Chatlier's principle, which of the following will not disturbs the equilibrium?
For a reaction,
$$A+B \rightleftharpoons 2 C$$
1.0 mole of $A, 1.5$ mole of $B$ and 0.5 mole of $C$ were taken in a 1 L vessel. At equilibrium, the concentration of $C$ was $1.0 \mathrm{~mol} \mathrm{~L}^{-1}$. The equilibrium constant for the reaction is $x / 15$. The value of ' $x$ ' is:
Consider the following equilibrium,
$$\begin{aligned} & 2 \mathrm{No}(g) \rightleftharpoons \mathrm{N}_2+\mathrm{O}_2 ; \mathrm{K}_{\mathrm{G}}=2.4 \times 10^{20} \\ & \mathrm{No}(\mathrm{g})+\frac{1}{2} \mathrm{Br}_2(\mathrm{~g}) \rightleftharpoons \mathrm{NoBr}(\mathrm{g}) ; \mathrm{K}_{\mathrm{C}_2}=1.4 \end{aligned}$$
Calculate \(K_C\) for the reaction,
$$\frac{1}{2} \mathrm{~N}_2(g)+\frac{1}{2} \mathrm{O}_2(g)+\frac{1}{2} \mathrm{Br}_2(g) \rightleftharpoons \mathrm{NOBr}(g)$$