LIFE SCIENCE PART C (JUNE 2019) PYQ - CSIR NET Practice Test

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LIFE SCIENCE PART C (JUNE 2019) 2019

Equal volumes of pH 4.0 and pH 10.0 solutions are mixed. What will be the approximate pH of the final solution?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The inborn error of amino acid metabolism, alkaptonuria, is due to the lack of one of the following enzymes:

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LIFE SCIENCE PART C (JUNE 2019) 2019

The structure of protein with 100 residues was determined by X-ray analysis at atomic resolution and NMR spectroscopy. The following observations are possible.
A) The dihedral angles determined from the X-ray structure and NMR will be identical.
B) The dihedral angles determined from the X-ray structure will be more accurate.
C) b-turns can be determined only by NMR.
D) b-sheets can be more accurately determined from the X-ray structure.
Indicates the combination with ALL correct answers

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LIFE SCIENCE PART C (JUNE 2019) 2019

The different arms in the tRNA structure are shown in Column A. The specific signatures associated with the different arms as shown in Column B.
Choose the correct matches from the following:

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LIFE SCIENCE PART C (JUNE 2019) 2019

Some coenzymes that serve as transient carriers of specific chemical groups are shown belowChoose the combination with all correct matches.

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LIFE SCIENCE PART C (JUNE 2019) 2019

Thermodynamics of protein folding is depicted as a free energy funnel below:
Given below are regions in the diagram (Column X) and their representation (Column Y)
Choose the option that shows all correct matches

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LIFE SCIENCE PART C (JUNE 2019) 2019

Table below shows the list of organelles (Column A); and the signals (Column B) that target proteins to the organelle
Choose the option that shows all correct matches

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following statements are made about chromatin remodeling in human cells:A) Local chromatin conformation may play more important role than the local DNA sequence of the promoter.B) Histones in nucleosome can undergo many different covalent modifications, which in turn, alter the chromatin architecture locally.C) Chromatin remodeling is a developmentally regulated passive process which does not require ATP.D) Several histone variants exist, which replace the standard histones in specific types of chromatin.Select the option that has the combination of all correct answers.

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LIFE SCIENCE PART C (JUNE 2019) 2019

In an experiment, the student has infected mammalian host cell with cytoplasmic RNA virus. The virus growth was monitored by measuring the intracellular viral RNA at different time intervals. It was observed that viral RNA titre progressively went down with time, particularly 12 hours post infection. Following are few possibilities which an explain this observation.A) The virus infection triggered Upregulation of miRNAs that might have downregulated the host factor critical for viral RNA replication.B) The virus might encode miRNAs that regulate (inhibits) its own replication.C) One of the viral proteins inhibits replication of the viral RNA to restrict rapid proliferation.D) Viral RNA goes to nucleus with time and thus not detectable in the cytoplasm 12 hour post infection.Which one of the following options has all correct statements?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Irrespective of the chromosomal configuration, a single X-chromosome remains active in all diploid human somatic cell lines. Which one of the following mechanisms best accounts for the above phenomenon?

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LIFE SCIENCE PART C (JUNE 2019) 2019

In eukaryotic cells, replication initiation from a replication origin occurs only once per cell cycle and S-phase CDKs play a vital role in the regulation of DNA replication. In budding yeast a protein complex known as the origin recognition complex (ORC) is associated with DNA replication origin during G1; however, origins fire only once at the beginning of S-phase. DNA replication does not start in G1 because:A) MCM helicases are inactive in G1B) Spindle checkpoint is active in G1C) DNA polymerase is not recruited in G1.D) ORC and initiation factors Cde6 and Cdt1 do not recruit MCM helicase to the site of replication initiation in G1.Which of the above statements are correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Measurements of the rate of actin treadmilling in vivo show that it can be several times higher than can be achieved with pure actin in vitro. The treadmilling in vitro can be enhanced by providing:
A) profilin that binds G-actin on the site opposite the nucleotide-binding cleft.
B) Cofilin binds specifically to the ADP containing F-actin and destabilizes the actin filament.
C) buffer with ATP and low levels of cations.
D) buffer with ADP and low levels of cations.
Which of the above statements are correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

In a strain of E. coli, a fusion between the lac and trp operon took place and the new locus structure is shown below. The strain lacks the wild-type trp operon.
Given below are some of the potential
Scenarios:
A) Tryptophan will be synthesized in a medium containing lactose and tryptophan.
B) Tryptophan synthesis will be repressed in a medium containing glucose.
C) Tryptophan synthesis will take place only in the absence of sufficient tryptophan in the medium.
Choose the option that correctly describes the behaviors of the fusion operon.

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following statements have been made about the removal of supercoiling produced by DNA unwinding at the replication fork:
A) Accumulation of supercoils is the result of DNA helicase activity during the unwinding of DNA
B) Problem of DNA supercoiling is valid only for circular chromosomes of bacteria and not for the linear chromosomes
C) Supercoiling of DNA is removed by topoisomerases by breaking either one or both strands of DNA on the replicated DNA in front of replication fork.
D) Both topoisomerase I and topoisomerase II can remove positive supercoiling during replication
Which one of the following options has all correct statements?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Phosphorylation of the a-subunit of elF2 at Ser 51 position in Saccharomyces cerevisiae leads to sequestration of elF2B, a guanosine exchange factor. This phenomenon is

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LIFE SCIENCE PART C (JUNE 2019) 2019

E. coli mutants isolated from a genetic screen showed the following classes of mutations (A) Points mutations in lack (B) Deletions immediately downstream of the transcription start site of the lacZYZ mRNA (C) Duplication of part or whole of lacY (D) Duplication of part of the whole of Lac A Choose the option which is likely to result in constitutive expression of the lac operon?

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LIFE SCIENCE PART C (JUNE 2019) 2019

For Escherichia coli chromosomal DNA replication, which one of the following statements is true?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following observations were made about variations among genomes of cukaryotic organisms:A) Single nucleotide polymorphisms are the numerically most abundant type of genetic variants.B) Both, interspersed and tandem repeated sequences can show polymorphic variation.C) Mitotic recombination between mispaired repeats causes change in copy number and generates minisatellite diversity in populationD) Smaller variable segments in the genome can be identified by paired end mapping techniqueSelect the option with all correct statements.

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LIFE SCIENCE PART C (JUNE 2019) 2019

There are number of specific T cell surface molecules involved in various functions of adaptive immune response, Column X represents a list of T cell surface molecules and Column Y with the possible functional characteristics:Which of the following option has all correct matches?

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LIFE SCIENCE PART C (JUNE 2019) 2019

In an experiment, it was observed that a protein was upregulated in the cancer tissues (compared to control tissues) that showed a correlation with disease progression. Following are a few possibilities which can explain the above observation.
A) A mutation could be located in the 3’UTR of the corresponding mRNA at a miRNA binding site.
B) A mutation changes the conformation of the protein, resulting in its better stability.
C) A mutation in the corresponding mRNA promotes ribosome read-through of the termination codon resulting in increased synthesis of the protein.
D) A mutation in the corresponding mRNA increased the stability of the RNA due to a change in secondary structure.
Which one of the following combinations represents the most likely explanations?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The extracellular matrix contains a number of non-collagen proteins that typically have multiple domains, each with specific binding sites for other matrix molecules and cell surface receptors. These proteins, therefore, contribute to both organizing the matrix and helping cells attach to it. The most well-characterized matrix protein of this kind is fibronectin. Which one of the following characteristics is NOT TRUE for fibronectin?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following are the list of some cellular receptors (Column X) and with possible functional characteristics (Column Y):Which one of the following is the correct match?

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LIFE SCIENCE PART C (JUNE 2019) 2019

In a laboratory experiment it was observed that both ‘Virus A’ and ‘Virus B’ could infect a mammalian host cell, when infected individually. Interestingly, if the cells were first infected with ‘Virus A’ (with large MOI), Virus B failed to infect the same cell. If the Virus B (with large MOI) is added first followed by Virus A, both the virus can infect the cells. However, infection with ‘Virus A’ was found to be in lesser extent. Considering X and Y are the receptors/co-receptors which may be involved for the virus entry, following are few possibilities that can explain the observation.A) ‘Virus A’ uses ‘X’ as receptor and Y as coreceptor.B) ‘Virus B’ uses exclusively ‘Y’ as receptor for entryC) Both ‘Virus A’ and ‘Virus B’ need X as receptor.Choose the option with all correct statements.

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LIFE SCIENCE PART C (JUNE 2019) 2019

While testing the effect of several potent anti-cancer compounds on cycling human oral cancer cells, a student observed that a major percentage of cells showed dose- dependent cell death after 12 hours of drug treatment. However, the remaining cells repopulated the culture dish once the compounds were removed and the cells cultured in complete medium. The student made the following assumptions:A) Not all cells were equally affected by the compounds as they were not synchronized before treatment.B) The compound selectively killed cells which were in Go phase.C) The cancer stem cells were impervious to the effects of the compounds and therefore repopulated the culture.D) The cancer cells differentiated into a mesenchymal phenotype and grew in fresh culture medium containing inhibitors of epithelial-to-mesenchymal transition (EMT).Which one of the following combination of assumptions would best justify the results?

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LIFE SCIENCE PART C (JUNE 2019) 2019

When 8-cell embryo of tunicates is separated into 4 blastomere pairs and allowed to grow independently in culture medium, then each blastomere pair can form most of the cell types; however, cells for nervous system are not developed. The following statements are formed from the above observations:A) Nervous system development demonstrated autonomous specificationB) The other tissue types are formed due to conditional specificationC) All the tissue types, except nervous tissues that developed, demonstrated autonomous specification.D) Nervous system development demonstrated conditional specification.The correct combination of statements that explains the above result is:

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LIFE SCIENCE PART C (JUNE 2019) 2019

During wing development in chick, if Apical Ectodermal Ridge (AER) is removed, the limb development ceases, on the other hand placing leg mesenchyme directly beneath the wing AER, distal hindlimb structures develop at the end of the wing, and if limb mesenchyme is replaced by non-limb mesenchyme beneath AER, the AER regresses. This may demonstrate that:A) the limb mesenchyme cells induce and sustain AER.B) the mesenchyme cells specify the type: wing or limb.C) the AER is responsible for sustained outgrowth and development of the limbD) the AER does not specify the type: wing or limb.Which combination of above statements is demonstrated by the experiment?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The following statements regarding the generation of dorsal/ventral axis in Drosophila was made:A) Gurken protein moves along with the oocyte nucleus and signals follicle cells to adopt the ventral fate.B) Maternal deficiencies of either the gurken or torpedo gene cause ventralization of the embryo.C) Gurken is active only in the oocyte and Torpedo is active only in the somatic follicle cells.D) The Pipe protein is made in the dorsal follicle cells.E) The highest concentration of Dorsal is in the dorsal cell nuclei, which becomes the mesoderm.Which one of the following combinations of the above statements is true?

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LIFE SCIENCE PART C (JUNE 2019) 2019

A specialized area of teratogenesis involves the mis regulation of the endocrine system. Which one of the following statements regarding endocrine disruptors is true?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Given below are statements related to different aspects of plant growth and development.
A) Leaf longevity is increased in ethylene-insensitive mutants etr-I-1 and ein2 of Arabidopsis.
B) Programmed cell death (PCD) is responsible for the formation of prickles, thorns and spines in plants.
C) Senescence and PCD occur only in the development of vegetative tissues and does not occur in reproductive tissues.
D) Redifferentiation of organelles is an integral component during initial stages of senescence in plants.
Which one of the following represents the combination of all correct statements?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The following demonstrates proposed functions of different genes which determine the decision to become either trophoblast or inner cell mass (ICM) blastomere during early mammalian development:Based on the above figure, which oneof the following assumptions is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Jasmonate is known to inhibit root growth while auxin facilitates root growth. Upon infection with pathogenic bacteria that produce coronatine, we may expect the following in plants:
A) Upregulation of COI-I gene and inhibition of root growth.
B) Upregulation of Aux-I gene and inhibition of root growth.
C) Inhibition of Aux1-I gene and promotion of root growth.
D) Inhibition of COI-I gene and promotion of root growth.
Which one of the following is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following are certain statements with regard to plant respiration:
A) Metabolism of glucose into pyruvate through glycolysis generates NADH and not NADPH.
B) Metabolism of glucose through oxidative pentose phosphate cycle does not produce NADPH.
C) Cyanide forms a complex with haem iron of cytochrome oxidase leading to prevention of change in valency, which in turn stops electron transport in the respiratory chain.
D) Alternative oxidase is insensitive to cyanide and has higher Km than that of cytochrome oxidase.
Which one of the following combinations is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Blue light receptor cry 1 binds to COP1 and SPA1 complex by interacting with C-terminal region of cry 1 (CCT) in light dependent manner and regulates photomorphogenesis via transcription factor HY5. Read the following statements:
A) cry 1 binds to COP1 and SPA1 complex leading to degradation of HY5
B) cry 1 binds to COP1 and SPA1 complex and prevents degradation of HY5
C) CCT is overexpressed and the plants are kept in dark.
D) CCT is overexpressed and the plants are kept in light.
Which of the following combination of above statements will result in photomorphogenesis?

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LIFE SCIENCE PART C (JUNE 2019) 2019

After absorbing light, chlorophyll molecules in green plants exist in singlet and triplet states. Following are certain statements on singlet and triplet states of chlorophyll molecules:
A) Singlet state is short lived compared to triplet state.
B) Singlet state is long lived compared to triplet state.
C) Singlet state contains electrons with anti-parallel spins white triplet state has electrons with parallel spins.
D) Singlet state contains electrons with parallel spins while triplet state has electrons with anti-parallel spins.
Which one of the following combinations is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Only members of the plant kingdom and many bacteria have capability of biological nitrogen reduction. In this regard, following statements are given:
A) Nitrogen is normally taken by the plant in their fully oxidized form but needs to be reduced before incorporation in organic molecules.
B) Conversion of oxidized nitrogen into reduced nitrogen needs energy in the form of NAD(P).
C) The metal associated with the enzyme nitrate reductase is Magnesium.
D) Nitrate reduction takes place in the cytoplasm, whereas nitrite reduction takes place in chloroplast matrix.
Which one of the following combinations of the above statements is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

During interaction with the host, phytopathogens are known to deliver effector proteins directly into the host cells. The following statements were made regarding the role of these effector proteins.A) May promote pathogen virulence.
B) May elicit a virulence response.
C) May suppress defence response.
D) May promote plant growth.
Which one of the following combinations of the above statements is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The CO2 dissociation curves of oxygenated and deoxygenated blood are given along with dissolved CO2 below:
Following are the statements deduced from the curves above and/or based on the knowledge about CO2 transport, which may or may not be correct:
A) The deoxygenated haemoglobin has greater affinity for CO2 than oxygenated haemoglobin.
B) The deoxygenated haemoglobin does not bind with free H ions released during the formation of HCO3 from CO2.
C) The haemoglobin saturation with O2 has no effect on the CO2 dissociation curve.
D) O2 and CO2 bind to haemoglobin at different sites.
Which one of the following options represents a combination of all correct statements?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Given below are the different intervals/ durations of electrocardiogram of a human subject (column A) and the events in heart during the process (column B).Which one of the following options is a correct match of entries in columns A and B?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The pathway of synthesis of aldosterone in zona glomerulosa along with the intracellular locations is shown below:The enzymes below are required for different steps of synthesis of aldosterone:Which one of the following options represents correct matches for A, B and C?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Given below is a figure of pro-opiomelanocortin (POMC) polypeptide and its cleavage products (marked as A, B, C, D) which have different hormonal activities. The names of the cleaved products obtained from POMC are shown in the table below the diagram.
Which one of the following options represents A, B, C and D correctly?

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LIFE SCIENCE PART C (JUNE 2019) 2019

During prolonged illumination, rhodopsin is desensitized which leads to the termination of visual response. The associated proteins (column A) and their effects (column B) are given below:
Which one of the matched combinations is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Estrus cycle in rats is controlled by pituitary and gonadal hormones. While treating a set of rats with vitamin D3 a student accidentally injected the rats with an inhibitor of 17a-hydroxypregnenolone and checked vaginal smear for 10 consecutive days.
Which one of the following observations is correct?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Centromere positions can be mapped in linear tetrads in some fungi. A cross was made between two strains a b and a’ b’ and 100 linear tetrads were analysed. The genes a and b are located on two arms of the chromosome. The tetrads were divided into 5 classes as shown below.
Based on the above observation, the following conclusions were drawn:
A) Class 1 is a result of a cross over between ‘a’ and the centromere
B) Class 2 is a result of a double crossover involving 3 strands between ‘a’ and the centromere
C) Class 5 is a result of a double crossover between ‘a’ – centromere, and ‘b’ – centromere, involving three strands
D) Class 4 is a result of a double crossover, involving all the 4 strands
Which one of the following options represents all correct statements?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The yellow mice with straight hair were crossed and the following progeny was obtained:
1/2 yellow, straight hair
1/6 yellow, fuzzy hair
1/4 gray, straight hair
1/12 gray, fuzzy hair
In order to provide genetic explanation for the results and assign genotypes to the parents and progeny of this cross, the following statements were given:
A) The 6:2:3:1 ratio obtained here indicates recessive epistasis
B) This cross concern two independent characteristics – body colour and type of hair
C) The deviation of dihybrid ratio from 9:3:3:1 to 6:2:3:1 may be due to one of the genes being a recessive lethal
D) The lethal allele is associated with straight hair
The most appropriate combination of statements to provide genetic explanation for this result is:

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LIFE SCIENCE PART C (JUNE 2019) 2019

A family was examined for a given trait which is represented in the pedigree shown below. Further, the degree of expression of the trait is highly variable among members of the family; some are only slightly affected while others developed severe symptoms at an early age.
The following statements are made toexplain the pattern of inheritance shown in the pedigree:
A) X-linked dominant mutation
B) X-linked recessive mutation
C) Mitochondrial inheritance
D) Variable expression can be due to heteroplasty
The best possible explanation for this inheritance is:

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LIFE SCIENCE PART C (JUNE 2019) 2019

The location of six deletions (shown as solid line underneath the chromosome) has been mapped to the Drosophila chromosome as shown in the diagram given below:
Recessive mutations a, b, c, d, e, f and g are known to be located in the region of deletions, but the order of mutations on the chromosome is not known. When flies homozygous for the recessive mutations are crossed with flies homozygous for the deletion, the following results were obtained, where the letter ‘m’ represents a mutant phenotype and ‘+’ represents the wild type.
The relative order of the seven mutant genes on chromosome is:

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LIFE SCIENCE PART C (JUNE 2019) 2019

In the following pedigree, individuals with shaded circle or shaded square show presence of a recessive autosomal trait.
The calculated risk of occurrence of this trait for III-I is

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LIFE SCIENCE PART C (JUNE 2019) 2019

During the course of vertebrate evolution, the jaw bones got modified into three ear ossicles in mammals. Which one of the following is a correct match of ear ossicle and its ancestral jaw bone?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Given below are names of the animals in column X and the accessory respiratory organs in teleost fishes (column Y).
The correct match of the animals with the accessory respiratory organs they have are:

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LIFE SCIENCE PART C (JUNE 2019) 2019

The terms expressing some of the developmental events or specific body structures are given in column X and the names of animals that are associated with them in column Y:
The correct match of the terms in column X with the name of animals in column Y is:

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LIFE SCIENCE PART C (JUNE 2019) 2019

The table lists characteristic anatomical features and names of plants.
Choose the option that correctly matches plant with their characteristic features.

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LIFE SCIENCE PART C (JUNE 2019) 2019

The table given below provides a list of female gametophyte features and plant genera.
Which one of the following options correctly matches the plant genera to female gametophyte features?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following are some generalizations related to wood anatomy of higher plants:A) The axial system of conifer woods consists mainly or entirely of tracheids.B) The rays of conifers typically contain only parenchyma cells.C) The rays of angiosperms typically contain both sclerenchyma cells and tracheids.D) Angiosperm wood may be either diffuse porous or ring porous.Which one of the following options represents all correct statements?

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LIFE SCIENCE PART C (JUNE 2019) 2019

A field ecologist gathers the following data (abundance values) in order to study the diversity of species in four plant communities.
Based on the above observations, the ecologist draws following conclusions:
A) Plant communities C1 and C4 show strong similarity with each other
B) Plant communities C1 and C4, as well as communities C2 and C3, show strong similarity with each other
C) Plant community C1 is most diverse
D) Plant community C4 is most diverse
Which of the following statements is correct regarding the above conclusions?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The table given below lists types of plant communities and types of growth forms.Which of the following is the best match for the plant communities with most dominant growth form generally present in that community?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following are some of the generalizations regarding energy flow in an ecosystem:A) Assimilation efficiency of carnivores is higher than herbivores.B) Consumption efficiency of aquatic herbivores is higher than terrestrial herbivores.C) Vertebrates have higher production efficiencies than invertebrates.D) Trophic-level transfer efficiency is higher in terrestrial food chains than in marine.Based on the above, select the correct option.

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LIFE SCIENCE PART C (JUNE 2019) 2019

In an experiment to show that biogeochemical cycles interact, nitrogen fixing vines (Galactica sp.) were grown in plots under normal levels of CO2 (Control) and under artificially elevated atmospheric CO2 (Experimental). Effect of elevated CO2 levels on nitrogen fixation was measured over a period of 7 years (Plot A) and the concentrations of iron and molybdenum in the leaves of these plants were quantified at the end of the study (Plot B).Which one of the following inferences CANNOT be made from the above experiment?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Match the following invasive plants to the likely habitats in which they are expected to occur:

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LIFE SCIENCE PART C (JUNE 2019) 2019

Incorporating additional ecological factors into the Lotka-Voltera predator-prey model can change the predator isocline. Given below are three state-space graphs (A-C) representing modification of predator isoclines due to the ecological factors listed below (i- iii)(i). Victim abundance acting as predator carrying capacity(ii). Availability of alternate prey (victim) population(iii) Predator carrying capacity determined by factors other than victim abundanceWhich one of the following options represents all correct matches of the state-space graphs with their ecological factor?

60

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LIFE SCIENCE PART C (JUNE 2019) 2019

Birds in a population show two foraging phenotypes, A and B. Birds of phenotype A search, attack and capture prey while birds of phenotype B steal prey from birds of phenotype A. A and B are maintained in the population through negative frequency-dependent selection. The graph below shows the fitness of A (broken line) and B (solid line) at different relative frequencies of A (frequency of B = 1, frequency of A).Which of the following statements does the graph support?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Antelopes are proposed to form groups to reduce the risk of predation. A researcher measured the predation of individuals in groups of different sizes. She found that per capita mortality risk decreased with increasing group size for males (solid line) but remained unchanged for females (dashed line). Furthermore, males in all groups experienced greater per capita morality risk than females.Identify the graph below that best depicts the above findings:

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LIFE SCIENCE PART C (JUNE 2019) 2019

The prominent mammal species found in four different protected areas are listed below:Area A: Tiger, Wild dog, Leopard, ElephantArea B: Common langur, Barking deer, Wild dog, ElephantArea C: Tiger, Indian rhinoceros, Pygny hog, Wild pigArea D: Blackbuck, Indian gazelle, Hyena, Indian WolfThe area with the greatest phylogenetic diversity is

63

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LIFE SCIENCE PART C (JUNE 2019) 2019

The Hardy-Weinberg principle states that allele frequencies in a population will remain constant over generations if certain assumptions are met.A) Random matingB) Mate choiceC) Small population sizeD) Large population sizeE) Lack of mutationsF) Directional selectionWhich of the above factors will cause changes in allele frequencies over generation?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Given below are few traits and related functions:Match the above given traits to their most likely functions.

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following is a diagrammatic representation of human evolutionary tree.In the above diagram A, B, C and D respectively represent:

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LIFE SCIENCE PART C (JUNE 2019) 2019

Based upon phenotypic observation, it was concluded that an unknown gene responsible for an agronomically important trait is present in a particular plant. In order to identify the gene, a researcher proposes to use the following strategies:A) PCR amplification of the gene.B) Map based cloning of the gene.C) Subtractive DNA hybridization.D) Genome sequencingE) Develop molecular markers linked to the traitWhich one of the following options is most suitable for identifying the unknown gene?

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LIFE SCIENCE PART C (JUNE 2019) 2019

A To transgenic plant contains two unlinked copies of the T-DNA of which, one is functional and the other issilenced. Segregation of the transgenic to non-transgenic phenotype would occur in a ____(i)____ratio in progeny obtained by backcrossing and in a ____(ii)_____ratio in F1 progeny obtained by self-pollination.Fill in the blanks with the correct combination of (i) and (ii) from the options given below:

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LIFE SCIENCE PART C (JUNE 2019) 2019

Column X lists two diseases and column Y list name of proteins which are commonly used in routine clinical diagnosis of these disease.Find out the correct combination:

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LIFE SCIENCE PART C (JUNE 2019) 2019

Given below are the steps to assess the population size of grasshoppers in a given area:A) ‘n’ individuals are collected randomly from the study area in a defined period of time.B) The captured individuals are counted, marked and released at the site of collection. Next day, individuals are captured from the same site for same length of time. Number of marked (nm) and unmarked (nu) individuals are separated and counted.C) This capture-release and recapture is continued till one gets 100% marked individuals.D) The size of the population (N) is estimated as follows:E) The size of population (N) is estimated as follow:The most appropriate combination of steps for estimating population size using mark-recapture method is:

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LIFE SCIENCE PART C (JUNE 2019) 2019

A neurophysiologist was interested in using the path clamp technique. Following statements are related to this technique:A) Intracellular movement of ion channels.B) Post-translation modification of the ion channel protein.C) Ligand that controls the opening or closing of ion channels.D) Change in current flow in a single ion channel.Which one of the following combinations will be achievable using the patch clamp technique?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The blood plasma proteins (albumin and globulins) from a healthy person were separated by electrophoresis as shown above. The diagnosis of acute inflammation can be done used on one of the following observations:

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LIFE SCIENCE PART C (JUNE 2019) 2019

Following statements were given regarding factors influencing variation in expression levels of transgene in transgenic plants:A) Difference in restriction enzyme sites within the T-DNA.B) Difference in copy number of the transgene.C) Variations in site of integration of the T-DNA within the plant genome.D) Presence of multiple promoters within the T-DNA region.Which one of the following options represents a combination of statements that would NOT lead to variations in transgene expression levels in transgenic plants generated using the same T-DNA/ binary vector?

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LIFE SCIENCE PART C (JUNE 2019) 2019

The above figure shows the fluorescence emission spectra of three different proteins; Protein (X), Protein (Y) and Protein (Z) excited at 280 nm.Which one of the following statements gives the correct interpretation?

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LIFE SCIENCE PART C (JUNE 2019) 2019

Specimens for light microscopy are commonly fixed with a solution containing chemicals that crosslink/denature cellular constituents. Commonly used fixatives such as formaldehyde and methanol could act in various ways as described below:
A) Formaldehyde crosslinks amino groups on adjacent molecules and stabilizes protein-protein and protein-nucleic acid interactions.
B) Methanol acts as a denaturing fixative and acts by reducing the solubility of protein molecules by disrupting hydrophobic interactions.
C) Formaldehyde crosslinks lipid tails in biological membranes.
D) Methanol acts on nucleic acids, crosslinks nucleic acids with proteins and thus stabilizes protein-nucleic acid interactions.
Which one of the following combinations represents all correct statements?

75

PYP

LIFE SCIENCE PART C (JUNE 2019) 2019

Run off transcription assays were performed to establish the specificity of three novel sigma factors for their promoters. Results of the experiments are shown below:Following inferences were made from these results:A) sA initiates transcription from P2 and sB from P1.B) sC can initiate transcription from both promoters.C) sB prevents initiation of transcription from P2.D) sA initiates transcription from P1.Choose the option that correctly interprets the results.

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LIFE SCIENCE PART C (JUNE 2019) 2019

Paper pattern & analysis

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Practise paper questions

NTA

State PSC

School Board Exams

UPSC

GATE

ESE & PSUs

State Entrance

Science & Research Entrance

JAM

CTET & TET

Engineering

Design Entrance

Judicial Services

CAT & MBA

Medical

Jawahar Navodaya (JNV)

SSC & Railway

Law Entrance

PRT, TGT & PGT

CSIR & UGC

PO, CLERK & SO

CLAT UG

NDA & CDS

LIFE SCIENCE PART C (JUNE 2019) 2019

Difficulty distribution

Question type distribution

Syllabus