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NCERT Exemplar · Class 6 · Maths

Chapter 7: Algebra

Practice each question, then open the answer or worked solution.

Questions

48 questions
Q11Written answer

In algebra, letters may stand for

(A) known quantities (B) unknown quantities

(C) fixed numbers (D) none of these

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Worked solution

Solution:-

(B) Unknown quantities

Q12Written answer

“Variable” means that it

(A) can take different values (B) has a fixed value

(C) can take only 2 values (D) can take only three values

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Worked solution

Solution:-

(A) Can take different values

The word ‘variable’ means something that can vary, i.e., change. The value of a variable is not fixed. We use a variable to represent a number and denote it by any letter such as l, m, n, p, x, y, z etc.

Q13Written answer

10 – x means

(A) 10 is subtracted x times (B) x is subtracted 10 times

(C) x is subtracted from 10 (D) 10 is subtracted from x

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Worked solution

Solution:-

(C) x is subtracted from 10

Q14Written answer

Savitri has a sum of Rs x. She spent Rs 1000 on groceries, Rs 500 on clothes and Rs 400 on education, and received Rs 200 as a gift. How much money (in Rs) is left with her?

(A) x – 1700 (B) x – 1900 (C) x + 200 (D) x – 2100

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Worked solution

Solution:-

(A) x – 1700

From the question it is given that,

Savitri has a sum of Rs x

She spent money on groceries = ₹ 1000

She spent money on clothes = ₹ 500

She spent money on education = ₹ 400

She received gift = ₹ 200

Total money spent by Savitri = 1000 + 500 + 400 = ₹ 1900

Then,

Total money left with her after deducting = ₹ (x – 1900)

Therefore, money left with her after adding gift money = (x – 1900) + 200

= x – 1700

Q15Written answer

The perimeter of the triangle shown in Fig. 7.1 is

NCERT Exemplar Class 6 Maths Solutions Chapter 7 Algebra Image 1

(A) 2x + y (B) x + 2y (C) x + y (D) 2x – y

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Worked solution

Solution:-

(A) 2x + y

Given triangle is an isosceles triangle,

So, perimeter of an isosceles triangle = 2 × x + y

= 2x + y

Q16Written answer

The area of a square having each side x is

(A) x × x (B) 4x (C) x + x (D) 4 + x

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Worked solution

Solution:-

(A) x × x

We know that, area of square = side × side

Given, square having a side x.

So, area of a square = x × x

= x2

Q17Written answer

The expression obtained when x is multiplied by 2 and then subtracted from 3 is

(A) 2x – 3 (B) 2x + 3 (C) 3 – 2x (D) 3x – 2

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Worked solution

Solution:-

(C) 3 – 2x

From the question it is given that,

X is multiplied by 2 = x × 2 = 2x

Then, x is multiplied by 2 and then subtracted from 3 = 3 – 2x

Q18Written answer

q/2 = 3 has a solution

(A) 6 (B) 8 (C) 3 (D) 2

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Solution:-

(A) 6

Consider the given equation q/2 = 3

By cross multiplication we get, q = 6

Q19Written answer

x – 4 = – 2 has a solution

(A) 6 (B) 2 (C) – 6 (D) – 2

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Solution:-

(B) 2

Consider the given equation x – 4 = -2

Transform – 4 from left hand side to right hand side it becomes 4.

x = – 2 + 4

x = 2

Q20Written answer

4/2 = 2 denotes a

(A) numerical equation (B) algebraic expression

(C) equation with a variable (D) false statement

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Worked solution

Solution:-

(A) numerical equation

4/2 = 2

By cross multiplication we get,

4 = 4