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Practice each question, then open the answer or worked solution.
$0.7499$lies between
(A) $0.7$and $0.74$
(B)$0.75$ and $0.79$
(C) ${\mathbf{0}}.{\mathbf{749}}{\text{ }}{\mathbf{and}}{\text{ }}{\mathbf{0}}.{\mathbf{75}}$
(D) ${\mathbf{0}}.{\mathbf{74992}}{\text{ }}{\mathbf{and}}{\text{ }}{\mathbf{0}}.{\mathbf{75}}$
Ans: Option ${\text{C}}$ is right
$0.7499$ is successor of $0.749$and predecessor of $0.75$
Thus, $0.749$lies between $0.749$and $0.75$
${\mathbf{0}}.{\mathbf{023}}$lies between
(A) $0.2 and 0.3$
(B)${\mathbf{0}}.{\mathbf{02}}{\text{ }}{\mathbf{and}}{\text{ }}{\mathbf{0}}.{\mathbf{03}}$
(C)${\mathbf{0}}.{\mathbf{03}}{\text{ }}{\mathbf{and}}{\text{ }}{\mathbf{0}}.{\mathbf{029}}$
(D)${\mathbf{0}}.{\mathbf{026}}{\text{ }}{\mathbf{and}}{\text{ }}{\mathbf{0}}.{\mathbf{024}}$
Ans: Option B is right
Thus, $0.023$lies between $0.02$and $0.03$
$\dfrac{{11}}{7}$ can be expressed in the form
(A) $7\dfrac{1}{4}$
(B) $4\dfrac{1}{7}$
(C) $1\dfrac{4}{7}$
(D) $11\dfrac{1}{7}$
Ans: Option ${\text{C}}$ is right
The mix fraction of $\dfrac{{11}}{7}$ is $1\dfrac{4}{7}$
The mixed fraction $5\dfrac{4}{7}$ can be expressed as
(A) $\dfrac{{33}}{7}$
(B) $\dfrac{{39}}{7}$
(C) $\dfrac{{33}}{4}$
(D) $\dfrac{{39}}{4}$
Ans: Option B is right
$\because 5\dfrac{4}{7} = \dfrac{{(7 \times 5) + 4}}{7}$
$= \dfrac{{35 + 4}}{7}$
$= \dfrac{{39}}{5}$
$0.07 + 0.008$ is equal to
(A) ${\mathbf{0}}.{\mathbf{15}}$
(B)${\mathbf{0}}.{\mathbf{015}}$
(C)${\mathbf{0}}.{\mathbf{078}}$
(D)${\mathbf{0}}.{\mathbf{78}}$
Ans: Option ${\text{C}}$ is right
Sum of $0.07 + 0.008$ is ${\mathbf{0}}.{\mathbf{078}}$
Which of the following decimals is the greatest?
(A) ${\mathbf{0}}.{\mathbf{182}}$
(B)${\mathbf{0}}.{\mathbf{0925}}$
(C)${\mathbf{0}}.{\mathbf{29}}$
(D)${\mathbf{0}}.{\mathbf{038}}$
Ans: Option ${\text{C}}$ is right
Convert the above option into like decimal as $0.1820,0.0925,0.2900$and $0.0380.$
Thus, comparing the value of like decimal value, $0.2900$ is the greatest among the given option.
Which of the following decimals is the smallest?
(A) ${\mathbf{0}}.{\mathbf{27}}$
(B)${\mathbf{1}}.{\mathbf{5}}$
(C)${\mathbf{0}}.{\mathbf{082}}$
(D)${\mathbf{0}}.{\mathbf{103}}$
Ans: Option ${\text{C}}$ is right
Convert the above option into like decimal as $0.270,1.500,0.082{\text{ and }}0.103.$
Thus, comparing the value of like decimal value, $0.082$is the smallest among the given option.
$13.572$correct to the tenths place is
(A) ${\mathbf{10}}$
(B)${\mathbf{13}}.{\mathbf{57}}$
(C)${\mathbf{14}}.{\mathbf{5}}$
(D)${\mathbf{13}}.{\mathbf{6}}$
Ans: Option D is right
Round off the number $13.572$is $13.6$
$15.8 - 6.73$ is equal to
(A) ${\mathbf{8}}.{\mathbf{07}}$
(B)${\mathbf{9}}.{\mathbf{07}}$
(C)${\mathbf{9}}.{\mathbf{13}}$
(D)${\mathbf{9}}.{\mathbf{25}}$
Ans: Option B is right
Subtraction of $15.8 - 6.73$is ${\mathbf{9}}.{\mathbf{07}}$
The decimal $0.238$ is equal to the fraction
(A) $\dfrac{{119}}{{500}}$
(B) $\dfrac{{238}}{{25}}$
(C) ${\kern 1pt} \,{\kern 1pt} \dfrac{{199}}{{25}}$
(D) $\dfrac{{119}}{{50}}$
Ans: Option A is right
Thus, $0.238$
fraction for $0.238$
$\Rightarrow \dfrac{{238}}{{1000}} = \dfrac{{238 \div 2}}{{1000 \div 2}}$
$= \dfrac{{119}}{{500}}$
Thus, required option $\dfrac{{119}}{{500}}.$
In Questions 21 to 44, fill in the blanks to make the Statements True