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NCERT Exemplar · Class 6 · Maths

Chapter 4: Fractions and Decimals

Practice each question, then open the answer or worked solution.

Textbook exercises

129 questions
Q71Written answer

$6.25 \ldots \dfrac{{25}}{4}$

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Worked solution

Ans: Since, convert $1.3$into fraction from, we get $\dfrac{{625}}{{100}}$

$\Rightarrow \dfrac{{625}}{{100}} = \dfrac{{625 \div 25}}{{100 \div 25}} = \dfrac{{25}}{4}$

$\dfrac{{25}}{4} \ldots .\dfrac{{25}}{4}$

$\dfrac{{25}}{4} = \dfrac{{25}}{4}$

Therefore, $6.25 = \dfrac{{25}}{4}$


Q72Written answer

Write the fraction represented by the shaded portion of the adjoining figure:


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Worked solution

Ans: In the given figure, total parts in the figure is divided into $8$ parts and 7 parts are shaded. 

Total parts $= 8$

Total shaded parts $= 7$

Therefore,

fraction of unshaded portion $= \dfrac{{{\text{ Total shaded parts }}}}{{{\text{ Total parts }}}}$

$= \dfrac{7}{8}$

The required fraction is $\dfrac{7}{8}$.


Q73Written answer

Write the fraction represented by the un-shaded portion of the adjoining figure:


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Worked solution

Ans: In the given figure, total parts in which figure has been divided into 15 and out of which 4 parts are unshaded.

Total parts $= 15$

Total unshaded parts $= 4$

Therefore,

fraction of unshaded portion $= \dfrac{{{\text{ Total unshaded parts }}}}{{{\text{ Total parts }}}} = \dfrac{4}{{15}}$

The required fraction is $\dfrac{4}{{15}}$.


Q74Written answer

Ali divided one fruit cake equally among six persons. What part of the cake he gave to each person?

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Worked solution

Ans: Given data 

Number of cake $= 1$

Total no. of persons $= 6$

Since,

Ali has to divide one fruit cake among 6 people,

${\text{Each person will get}} = \dfrac{{{\text{ No}}{\text{. of cake }}}}{{{\text{ Total no}}{\text{. of person }}}}$

$= \dfrac{1}{6}{\text{ part}}$


Q75Written answer

Arrange ${\mathbf{12}}.{\mathbf{142}},{\text{ }}{\mathbf{12}}.{\mathbf{124}},{\text{ }}{\mathbf{12}}.{\mathbf{104}},{\text{ }}{\mathbf{12}}.{\mathbf{401}}{\text{ }}{\mathbf{and}}{\text{ }}{\mathbf{12}}.{\mathbf{214}}$in ascending order.

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Worked solution

Ans: Given number$12.142,12.124,12.104,12.401{\kern 1pt} \,{\text{and }}12.214$ in like decimal.

So, compare the place value of the digit and arrange them, $12.104 < 12.124 < 12.142 < 12.214 < 12.401$


Q76Written answer

Write the largest four-digit decimal number less than1 using the digits $1,5,3$ and ${\mathbf{8}}$ once.

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Worked solution

Ans: Given whole numbers are$1,5,3,{\text{ and }}8$.

Arrange them in descending order to make them large, after arranging the number will be $8531.$

To make it a decimal number we will keep the whole number  8531 in the decimal point.

The required number is 0.8531, which is the largest four  -  digit decimal number less than 1.


Q77Written answer

Using the digits ${\mathbf{2}},{\mathbf{4}},{\mathbf{5}}$ and ${\mathbf{3}}$ once, write the smallest four-digit decimal number. 

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Worked solution

Ans: For converting $2,4,5,$and $3$ into smallest four digit decimal number, arrange them in ascending order and then making the numbers decimal, we have to keep the whole numbers in decimal point.

After arranging whole numbers in ascending form it will be $2345.$

To make the number decimal we will keep the numbers in decimal point.

So, the required number is$0.2345$, which is the smallest four digit decimal number.


Q78Written answer

Express $\dfrac{{11}}{{20}}$ as a decimal.

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Worked solution

Ans: $\dfrac{{11}}{{20}}$ is an improper fraction.

To get the denominator as whole number we will multiply denominator by$5$,

$\dfrac{{11}}{{20}} = \dfrac{{11 \times 5}}{{20 \times 5}} = \dfrac{{55}}{{100}} = 0.55$

$0.55$ is in decimal form


Q79Written answer

Express $6\dfrac{2}{3}$ as an improper fraction.

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Worked solution

Ans: We will convert the mixed fraction $6\dfrac{2}{3}$ into improper fraction. 

We have,

$6\dfrac{2}{3} = \dfrac{{(6 \times 3) + 2}}{3} = \dfrac{{18 + 2}}{3} = \dfrac{{20}}{3}$

Now we got $\dfrac{{20}}{3}$.

$\dfrac{{20}}{3}$ is an improper fraction.


Q80Written answer

Express $3\dfrac{2}{5}$ as a decimal.

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Worked solution

Ans: We will convert the mixed fraction $3\dfrac{2}{5}$ into an improper fraction. 

We have, $3\dfrac{2}{5} = \dfrac{{(3 \times 5) + 2}}{5} = \dfrac{{15 + 2}}{5} = \dfrac{{17}}{5}$

Now,

$\dfrac{{17}}{5} = \dfrac{{17 \times 2}}{{5 \times 2}} = \dfrac{{34}}{{10}} = 3.4$