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Practice each question, then open the answer or worked solution.
The place value of a digit at the tenths place is 10 times the same digit at the one's place.
Ans: The given statement is False
The place value of a digit at the tenths place is $\dfrac{1}{{10}}$ times the same digit at the one's place.
$\dfrac{x}{{10}} = 10x$, it is not possible.
The place value of a digit at the hundredths place is $\dfrac{1}{{10}}$ times the same digit at the tenths place.
Ans: The given statement is True
The decimal $3.725$is equal to $3.72$ correct to two decimal places.
Ans: The given statement is False
Since, $5$are at thousandths place.
$3.725$is written as $3.73,$correct two decimal place.
In the decimal form, fraction $\dfrac{{25}}{8} = 3.125$.
Ans: The statement is True
$\dfrac{{25}}{8} = \dfrac{{25 \times 125}}{{8 \times 125}}$
$= \dfrac{{3125}}{{1000}} = 3.125$
The decimal $23.2 = 23\dfrac{2}{5}$.
Ans: The given statement is False
$23.2 = \dfrac{{232}}{{10}}$
$= \dfrac{{232 \div 2}}{{10 \div 2}} = \dfrac{{116}}{5}$
By Long division method the quotient and reminder is $23{\kern 1pt} {\kern 1pt} \,{\text{and}}{\kern 1pt} \,1$.
The correct statement
The decimal $23.2 = 23\dfrac{1}{5}$.
The fraction represented by the shaded portion in the adjoining figure is $\dfrac{3}{8}$.
Ans: The given explanation is true.
The figure shows that, number of total part is$8$ and out of these$3$parts is shaded.
The required fraction is $\dfrac{3}{8}$
The fraction represented by the un-shaded portion in the adjoining figure is $\dfrac{5}{9}$.
Ans: The given statement for the figure is false.
The figure shows that, number of total part is $9$ and out of these $4$ parts is un-shaded.
The required fraction is $\dfrac{4}{9}$.
$\dfrac{{25}}{{19}} + \dfrac{6}{{19}} = \dfrac{{31}}{{38}}$
Ans: The addition of the fraction is False
Denominator is same for the fractions so by adding the numerator
$\Rightarrow \dfrac{{25}}{{19}} + \dfrac{6}{{19}} = \dfrac{{25 + 6}}{{19}} = \dfrac{{31}}{{19}}$
$\Rightarrow \dfrac{{31}}{{19}} \ne \dfrac{{31}}{{38}}$
$\dfrac{8}{{18}} - \dfrac{8}{{15}} = \dfrac{8}{3}$
Ans: The subtract of the fraction is False
Cross multiply the both fraction with each other.
$\Rightarrow \dfrac{8}{{18}} - \dfrac{8}{{15}} = \dfrac{{8 \times 15 - 8 \times 18}}{{18 \times 15}}$
$= \dfrac{{120 - 144}}{{270}} = \dfrac{{ - 24}}{{270}}$
$= - \dfrac{4}{{45}}$
$\Rightarrow - \dfrac{4}{{45}} \ne \dfrac{8}{3}$
$\dfrac{7}{{12}} + \dfrac{{11}}{{12}} = \dfrac{3}{2}$
Ans: The addition of the fraction is True
$\Rightarrow \dfrac{7}{{12}} + \dfrac{{11}}{{12}} = \dfrac{{7 + 11}}{{12}}$
$= \dfrac{{18 \div 6}}{{12 \div 6}} = \dfrac{3}{2}$