My Cart
Your Cart 0

    Your cart is empty.

  • Total (Amount) ₹0.00
NCERT Exemplar · Class 6 · Maths

Chapter 4: Fractions and Decimals

Practice each question, then open the answer or worked solution.

Read chapter PDFDownload PDF

Textbook exercises

129 questions
Q1Written answer

The fraction which is not equal to $\dfrac{4}{5}$ is

(A) $\dfrac{{40}}{{50}}$

(B) $\dfrac{{12}}{{15}}$

(C) $\dfrac{{16}}{{20}}$

(D) $\dfrac{9}{{15}}$

Show solutionHide solution
Worked solution

Ans: Option D is right

Check option $A \Rightarrow \dfrac{{40 \div 10}}{{50 \div 10}} = \dfrac{4}{5}$

Check option ${\text{B}} \Rightarrow \dfrac{{12}}{{15}} = \dfrac{4}{5}$

Check option ${\text{C}} \Rightarrow \dfrac{{16}}{{20}} = \dfrac{4}{5}$

Check option ${\text{D}} \Rightarrow \dfrac{9}{{15}} = \dfrac{3}{5}$


Q2Written answer

The two consecutive integers between which the fraction $\dfrac{5}{7}$ lies are

(A) ${\mathbf{5}}$ and ${\mathbf{6}}$

(B) ${\mathbf{0}}$ and ${\mathbf{1}}$

(C) ${\mathbf{5}}$ and $7$

(D) ${\mathbf{6}}$ and ${\mathbf{7}}$

Show solutionHide solution
Worked solution

Ans: Option B is right

Fundamental from fraction, if the value of a numerator of each fraction implies less than this value of denominator, ever lies between and $0$ and $1$.

Hence, $\dfrac{5}{7}$ are lies between $0$ and $1$.


Q3Written answer

When $\dfrac{1}{4}$ is written with denominator as ${\mathbf{12}}$, its numerator is

(A) ${\mathbf{3}}$

(B) ${\mathbf{8}}$

(C) ${\mathbf{24}}$

(D) ${\mathbf{12}}$

Show solutionHide solution
Worked solution

Ans: Option A is right

Since, $\Rightarrow \dfrac{1}{4} \times \dfrac{3}{3} = \dfrac{3}{{12}}$


Q4Written answer

Which of the following is not in the lowest form?

(A) $\dfrac{7}{5}$

(B) $\dfrac{{15}}{{20}}$

(C) $\dfrac{{13}}{{33}}$

(D) $\dfrac{{27}}{{28}}$

Show solutionHide solution
Worked solution

Ans: Option B is right

In case of $\dfrac{5}{7}$, the common factor of $7$ and $5$ is $1$.

Hence, already given in the simplest form.

In case of $\dfrac{{15}}{{20}}$, the common factor of $15$ and $20$ is $4.$

In case of $\dfrac{{13}}{{33}}$, the common factor of $13$ and $33$ is $1$.

Hence, already given in the simplest form.

In case of $\dfrac{{27}}{{28}}$, the common factor of $27$ and $28$ is $1$.

Hence, already given in the simplest form.

Hence, $\dfrac{{15}}{{20}}$ not given in the simplest form.


Q5Written answer

If $\dfrac{5}{8} = \dfrac{{20}}{p}$, then value of $p$ is

(A) ${\mathbf{23}}$

(B) ${\mathbf{2}}$

(C) ${\mathbf{32}}$

(D) ${\mathbf{16}}$

Show solutionHide solution
Worked solution

Ans: Option ${\text{C}}$ is right

$\dfrac{5}{8} = \dfrac{{20}}{{\text{p}}}$

$\Rightarrow 5 \times {\text{p}} = 20 \times 8$

$\Rightarrow {\text{p}} = \dfrac{{20 \times 8}}{5}$

$\Rightarrow {\text{p}} = 4 \times 8 = 32$

Hence, Value of ${\text{p}}$ is 32


Q6Written answer

Which of the following is not equal to the others?

(A) $\dfrac{6}{8}$

(B) $\dfrac{{12}}{{16}}$

(C) $\dfrac{{15}}{{25}}$

(D) $\dfrac{{18}}{{24}}$

Show solutionHide solution
Worked solution

Ans: Option ${\text{C}}$ is right

Check option ${\text{A}} \Rightarrow \dfrac{6}{8} = \dfrac{3}{4}$

Check option ${\text{B}} \Rightarrow \dfrac{{12 \div 4}}{{16 \div 4}} = \dfrac{3}{4}$

Check option ${\text{C}} \Rightarrow \dfrac{{15 \div 5}}{{25 \div 5}} = \dfrac{3}{5}$

Check option D $\Rightarrow \dfrac{{18 \div 6}}{{24 \div 6}} = \dfrac{3}{4}$

Thus, Option ${\text{C}}$ is not equal to the other option.


Q7Written answer

Which of the following fractions is the greatest?

(A) $\dfrac{5}{7}$

(B) $\dfrac{5}{6}$

(C) $\dfrac{5}{9}$

(D) $\dfrac{5}{8}$

Show solutionHide solution
Worked solution

Ans: Option B is right

In the above option given that, among the entire fraction with same numerator, the one with smaller denominator will be greatest.

Thus, required fraction is $\dfrac{5}{6}$.


Q8Written answer

Which of the following fractions is the smallest?

(A) $\dfrac{7}{8}$

(B) $\dfrac{9}{8}$

(C) $\dfrac{3}{8}$

(D) $\dfrac{5}{8}$

Show solutionHide solution
Worked solution

Ans: Option C is right

In the above option given that, among the entire fraction with same denominator, the one with smaller numerator will be smallest.

Thus, required fraction is $\dfrac{3}{8}$.


Q9Written answer

Sum of $\dfrac{4}{{17}}$ and $\dfrac{{15}}{{17}}$ is

(A) $\dfrac{{19}}{{17}}$

(B) $\dfrac{{11}}{{17}}$

(C) $\dfrac{{19}}{{34}}$

(D) $\dfrac{2}{{17}}$

Show solutionHide solution
Worked solution

Ans: Option A is right 

$\dfrac{4}{{17}}$ and $\dfrac{{15}}{{17}}$

Take the LCM of denominators

$\Rightarrow \dfrac{4}{{17}} + \dfrac{{15}}{{17}} = \dfrac{{4 + 15}}{{17}}$

$= \dfrac{{19}}{{17}}$

Thus, required fraction is $\dfrac{{19}}{{17}}$.


Q10Written answer

On subtracting $\dfrac{5}{9}$ from $\dfrac{{19}}{9}$, the result is

(A) $\dfrac{{24}}{9}$

(B) $\dfrac{{14}}{9}$

(C) $\dfrac{{14}}{{18}}$

(D) $\dfrac{{14}}{0}$

Show solutionHide solution
Worked solution

Ans: Option B is right 

$\dfrac{5}{9}$ from $\dfrac{{19}}{9}$

Take the LCM of denominators


   $\Rightarrow \dfrac{{19}}{9} - \dfrac{5}{9} = \dfrac{{19 - 5}}{9}$

   $= \dfrac{{14}}{9}$ 

Thus, required fraction is $\dfrac{{14}}{9}$.