If a number is divisible both by 2 and 3, then it is divisible by 12.
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Solution:-
False.
Let us consider the number 6, it is actually divisible by 2 and 3, But 6 is not divisible by 12.
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If a number is divisible both by 2 and 3, then it is divisible by 12.
Solution:-
False.
Let us consider the number 6, it is actually divisible by 2 and 3, But 6 is not divisible by 12.
A number with three or more digits is divisible by 6, if the number formed by its last two digits (i.e., ones and tens) is divisible by 6.
Solution:-
False.
A number with 4 or more digits is divisible by 8, if the number formed by the last three digits is divisible by 8.
Solution:-
True.
As per the rule of divisibility test, a number with 4 or more digits is divisible by 8, if the number formed by the last three digits is divisible by 8.
If the sum of the digits of a number is divisible by 3, then the number itself is divisible by 9.
Solution:-
False.
As per the rule of divisibility test, the sum of the digits of a number is divisible by 9, then the number itself is divisible by 9.
All numbers which are divisible by 4 may not be divisible by 8.
Solution:-
True.
Consider the number 20, it is divisible by 4 but not divisible by 8.
The Highest Common Factor of two or more numbers is greater than their Lowest Common Multiple.
Solution:-
False.
The Highest Common Factor of two or more numbers is lower than their Lowest Common Multiple.
LCM of two or more numbers is divisible by their HCF.
Solution:-
True.
As per the rule, LCM of two or more numbers is divisible by their HCF.
LCM of two numbers is 28 and their HCF is 8.
Solution:-
False.
From the question it is given that, LCM of two numbers is 28 and their HCF is 8.
But, 28 is not exactly divided by 8.
LCM of two or more numbers may be one of the numbers.
Solution:-
True.
Consider the two numbers 2 and 4.
Then, LCM of 2 and 4 is 4.
HCF of two or more numbers may be one of the numbers.
Solution:-
True.