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Find dy/dx of each of the functions expressed in parametric form in Exercises from 44 to 48.

Given,
x = t + 1/t, y = t – 1/t
Differentiating both the parametric functions w.r.t θ


Given,


x = 3cosq – 2cos3q, y = 3sinq – 2sin3q.
Given, x = 3cosq – 2cos3q, y = 3sinq – 2sin3q.
Differentiating both the parametric functions w.r.t. q


Given,
sin x = 2t/(1 + t2), tan y = 2t/ (1 – t2)



On differentiating both the given parametric functions w.r.t. t, we have


If x = ecos2t and y = esin2t, prove that dy/ dx = – y log x/ x log y.
Given,
x = ecos2t and y = esin2t
So, cos 2t = log x and sin 2t = log y
Now, differentiating both the parameter functions w.r.t t, we have


If x = asin2t (1 + cos2t) and y = b cos2t (1–cos2t), show that
Given,
x = asin2t (1 + cos2t) and y = b cos2t (1–cos2t)
Differentiating both the parametric equations w.r.t t, we have

