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NCERT Exemplar · Class 11 · Maths

Chapter 7: Permutations and Combinations

Practice each question, then open the answer or worked solution.

Exercise · Page 122

Textbook page 122 · 32 questions
Q31Written answer

A five-digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions. The total number of ways this can be done is
A. 216
B. 600
C. 240
D. 3125
[Hint:5 digit numbers can be formed using digits 0, 1, 2, 4, 5 or by using digits 1, 2, 3, 4, 5 since sum of digits in these cases is divisible by 3.]

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Worked solution

A. 216

Explanation:

5-digit numbers that can be formed using digits 0, 1, 2, 4, 5

4 4 3 2 1

4×4×3×2×1=96

5-digit numbers can be formed using digits 1, 2, 3, 4, 5 = 5!

Total number of ways = 5! +96

=216

Hence, Option (A) 216 is the correct answer.

Q32Written answer

Everybody in a room shakes hands with everybody else. The total number of hand shakes is 66. The total number of persons in the room is
A. 11

B. 12
C. 13
D. 14

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Worked solution

B. 12

Explanation:

We know that,

nCr
NCERT Exemplar Solutions For Class 11 Maths Chapter 7-31

Let total time of handshakes=nC2 = 66

NCERT Exemplar Solutions For Class 11 Maths Chapter 7-32

⇒ n2-n=132

⇒ (n-12) (n+11) = 0

n=12 or n = – 11

Therefore, n = 12

Hence, Option (B) 12 is the correct answer.