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NCERT Exemplar · Class 11 · Maths

Chapter 14: Mathematical Reasoning

Practice each question, then open the answer or worked solution.

Exercise · Page 261

Textbook page 261 · 17 questions
Q11Written answer

Identify the Quantifiers in the following statements.

(i) There exists a triangle which is not equilateral.

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Worked solution

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “There exists a triangle which is not equilateral”

Quantifier is “There exist”

Hence, There exist is quantifier.

(ii) For all real numbers x and y, xy = y x.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “For all real numbers x and y, xy = yx.”

Quantifier is “For all”

Hence, ‘For all’ is quantifier.

(iii) There exists a real number which is not a rational number.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “There exists a real number which is not a rational number.”

Quantifier is “There exist”

Hence, ‘There exist’ is quantifier.

(iv) For every natural number x, x + 1 is also a natural number.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “For every natural number x, x + 1 is also a natural number.”

Quantifier is “For every”

Hence, ‘For every’ is quantifier.

(v) For all real numbers x with x > 3, x 2 is greater than 9.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “For all real numbers x with x > 3, x2 is greater than 9.”

Quantifier is “For all”

Hence, ‘For all’ is quantifier.

(vi) There exists a triangle which is not an isosceles triangle.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “There exists a triangle which is not an isosceles triangle.”

Quantifier is “There exist”

Hence, ‘There exist’ is quantifier.

(vii) For all negative integers x, x 3 is also a negative integers.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “For all negative integers x, x3 is also a negative integers.”

Quantifier is “For all”

Hence, ‘For all’ is quantifier.

(viii) There exists a statement in above statements which is not true.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “There exists a statement in above statements which is not true.”

Quantifier is “There exist”

Hence, ‘There exist’ is quantifier.

(ix) There exists a even prime number other than 2.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “There exists a even prime number other than 2.”

Quantifier is “There exist”

Hence, ‘There exist’ is quantifier.

(x) There exists a real number x such that x 2 + 1 = 0.

Quantifiers means a phrase like ‘there exist’, ’for all’ and ‘for every’ etc. and these are used to make the prepositional statement.

In the given statement “There exists a real number x such that x2 + 1 = 0.”

Quantifier is “There exist”

Hence, ‘There exist’ is quantifier.

Q12Written answer

Prove by direct method that for any integer ‘n’, n3 – n is always even.

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Worked solution

Given n3-n

Let us assume, n is even

Let n = 2k, where k is natural number

n3 – n = (2k)3– (2k)

n3 – n = 2k (4k2-1)

Let k (4k2 – 1) = m

n3 – n = 2m

Therefore, (n3-n) is even.

Now, let us assume n is odd

Let n = (2k + 1), where k is natural number

n3 – n = (2k + 1)3 – (2k + 1)

n3 – n = (2k + 1) [(2k + 1)2 – 1]

n3 – n = (2k + 1) [(4k2 + 4k + 1 – 1)]

n3 – n = (2k + 1) [(4k2 + 4k)]

n3 – n = 4k (2k + 1) (k + 1)

n2 – n = 2.2k (2k + 1) (k + 1)

Let λ = 2k (2k + 1) (k + 1)

n3 – n = 2λ

Therefore, n3-n is even.

Hence, n3-n is always even

Q13Written answer

Check the validity of the following statement.

(i) p: 125 is divisible by 5 and 7.

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Worked solution

p: 125 is divisible by 5 and 7

Let, q: 125 is divisible by 5.

r: 125 is divisible 7.

Here, q is true and r is false.

Therefore, q ᴧ r is False

Hence, p is not valid.

(ii) q: 131 is a multiple of 3 or 11.

Given q : 131 is a multiple of 3 or 11

Let, P: 131 is a multiple of 3.

Q: 131 is a multiple of 11.

Here, P is false and Q is False

Therefore, P ⋁ Q is False

Hence, q is not valid

Q14Written answer

Prove the following statement by contradiction method.

p: The sum of an irrational number and a rational number is irrational

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Worked solution

Let p is false, as the sum of an irrational number and a rational number is irrational.

Let √λ is irrational and n is rational number

√λ + n = r

√λ = r – n

But, we know that √λ is irrational whereas (r-n) is rational which is contradiction.

Here, Our Assumption is False

Hence, P is true.

Q15Written answer

Prove by direct method that for any real numbers x, y if x = y, then x2 = y2.

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Worked solution

Given for any real number x, y if x=y

Now we have to find x2 = y2

Let us assume

p: x=y where x and y are real number

On squaring both sides we get

x2 = y2 : q (Assumption)

Therefore,

p = q

Hence, Proved

Q16Written answer

Using contrapositive method prove that if n2 is an even integer, then n is also an even integers.

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Worked solution

Let us assume

p: n2 is an even integer.

~p: n is not an even integer

q: n is also an even integer

~q=n is not an even integer.

Since, in the contrapositive, a conditional statement is logically equivalent to its contrapositive.

Therefore,

~q → ~p = If n is not an even integer then n2 is not an even integer.

Hence, ~q is true → ~p is true.

Objective type questions:

Choose the correct answer out of the four options given against each of the Exercises 17 to 36 (M.C.Q.).

Q17Multiple choice

Which of the following is a statement.

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Correct option: C
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Worked solution

(C) 6 is a natural number.

Explanation:

A statement is an assertive (declarative) sentence if it is either true or false but not both.

Here, 6 is a natural number is true

18. Which of the following is not a statement

(A) Smoking is injurious to health.

(B) 2 + 2 = 4

(C) 2 is the only even prime number.

(D) Come here.

(D) Come here.

Explanation:

To given order like Come here, Go there are not statements.