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NCERT Exemplar · Class 11 · Chemistry

Chapter 6: Thermodynamics

Practice each question, then open the answer or worked solution.

Multiple Choice Questions (Type-I)

14 questions
Q11Written answer

Consider the reactions given below. On the basis of these reactions find out which of the algebric relations given in options (i) to (iv) is correct?

\[\begin{array}{*{35}{l}}   \left( \mathbf{a} \right)\mathbf{ C }\left( \mathbf{g} \right)\mathbf{ + 4 H }\left( \mathbf{g} \right)\mathbf{ }\to \mathbf{ C}{{\mathbf{H}}_{\mathbf{4}}}\mathbf{ }\left( \mathbf{g} \right)\mathbf{;}{{\mathbf{\Delta }}_{\mathbf{r }}}\mathbf{H = x kJ mo}{{\mathbf{l}}^{\mathbf{1}}}  \\   \left( \mathbf{b} \right)\mathbf{ C}{{\mathbf{ }}_{\left( \mathbf{graphite,s} \right)}}\mathbf{ + 2}{{\mathbf{H}}_{\mathbf{2}}}\mathbf{ }\left( \mathbf{g} \right)\to \mathbf{ C}{{\mathbf{H}}_{\mathbf{4}}}\mathbf{ }\left( \mathbf{g} \right)\mathbf{; }{{\mathbf{\Delta }}_{\mathbf{r }}}\mathbf{H = y kJ mo}{{\mathbf{l}}^{\mathbf{1}}}  \\\end{array}\] 

(i) x = y 

(ii) x = 2y

(iii) x > y

(iv) x < y

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Worked solution

Ans: Same bonds are formed in reaction (a) and (b) but bonds between the reactant molecules are broken only in reaction (b). Hence option(iii) is the correct answer.


Q12Written answer

The enthalpies of elements in their standard states are taken as zero. The enthalpy of formation of a compound- 

(i) is always negative

(ii) is always positive 

(iii) may be positive or negative 

(iv) is never negative

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Worked solution

Ans: The enthalpies of elements in their standard states are taken as zero. The enthalpy of formation of a compound as the reaction could be exothermic or endothermic. Hence, option(iii) is the correct answer.


Q13Written answer

Enthalpy of sublimation of a substance is equal to

(i) enthalpy of fusion + enthalpy of vaporisation 

(ii) enthalpy of fusion

(iii) enthalpy of vaporisation 

(iv) twice the enthalpy of vaporisation

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Worked solution

Ans: Enthalpy of sublimation can be shown as

 Solid \[\to \] Liquid \[\to \]Vapour

Hence, Enthalpy of sublimation of a substance is equal to enthalpy of fusion + enthalpy of vaporisation. Therefore, option(i) is the correct answer. 


Q14Written answer

Which of the following is not correct?

(i) ∆G is zero for a reversible reaction

(ii) ∆G is positive for a spontaneous reaction

(iii) ∆G is negative for a spontaneous reaction

(iv) ∆G is positive for a non-spontaneous reaction 

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Worked solution

Ans: \[\text{ }\!\!\Delta\!\!\text{ G}\] positive for a spontaneous reaction. Hence, option(ii) is the correct answer.