Consider the reactions given below. On the basis of these reactions find out which of the algebric relations given in options (i) to (iv) is correct?
\[\begin{array}{*{35}{l}} \left( \mathbf{a} \right)\mathbf{ C }\left( \mathbf{g} \right)\mathbf{ + 4 H }\left( \mathbf{g} \right)\mathbf{ }\to \mathbf{ C}{{\mathbf{H}}_{\mathbf{4}}}\mathbf{ }\left( \mathbf{g} \right)\mathbf{;}{{\mathbf{\Delta }}_{\mathbf{r }}}\mathbf{H = x kJ mo}{{\mathbf{l}}^{\mathbf{1}}} \\ \left( \mathbf{b} \right)\mathbf{ C}{{\mathbf{ }}_{\left( \mathbf{graphite,s} \right)}}\mathbf{ + 2}{{\mathbf{H}}_{\mathbf{2}}}\mathbf{ }\left( \mathbf{g} \right)\to \mathbf{ C}{{\mathbf{H}}_{\mathbf{4}}}\mathbf{ }\left( \mathbf{g} \right)\mathbf{; }{{\mathbf{\Delta }}_{\mathbf{r }}}\mathbf{H = y kJ mo}{{\mathbf{l}}^{\mathbf{1}}} \\\end{array}\]
(i) x = y
(ii) x = 2y
(iii) x > y
(iv) x < y
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Ans: Same bonds are formed in reaction (a) and (b) but bonds between the reactant molecules are broken only in reaction (b). Hence option(iii) is the correct answer.