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NCERT Exemplar · Class 10 · Maths

Chapter 4: Quadratic Equations

Practice each question, then open the answer or worked solution.

Exercise 4.4

4 questions
Q1Written answer

Find a natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.

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Worked solution

Let the natural number = ‘x’.

According to the question,

We get the equation,

x² – 84 = 3(x+8)

x² – 84 = 3x + 24

x² – 3x – 84 – 24 = 0

x² – 3x – 108 = 0

x² – 12x + 9x – 108 = 0

x(x – 12) + 9(x – 12) = 0

(x + 9) (x – 12)

⇒ x = -9 and x = 12

Since, natural numbers cannot be negative.

The number is 12.

Q2Written answer

A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.

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Worked solution

Let the natural number = x

When the number increased by 12 = x + 12

Reciprocal of the number = 1/x

According to the question, we have,

x + 12 = 160 times of reciprocal of x

x + 12 = 160/ x

x( x + 12 ) = 160

x2 + 12x – 160 = 0

x2 + 20x – 8x – 160 = 0

x( x + 20) – 8( x + 20)= 0

(x + 20) (x – 8) = 0

x + 20 = 0 or x – 8 = 0

x = – 20 or x = 8

Since, natural numbers cannot be negative.

The required number = x = 8

Q3Written answer

A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/h more. Find the original speed of the train.

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Worked solution

Let original speed of train = x km/h

We know,

Time = distance/speed

According to the question, we have,

Time taken by train = 360/x hour

And, Time taken by train its speed increase 5 km/h = 360/( x + 5)

It is given that,

Time taken by train in first – time taken by train in 2nd case = 48 min = 48/60 hour

360/x – 360/(x +5) = 48/60 = 4/5

360(1/x – 1/(x +5)) = 4/5

360 ×5/4 (5/(x² +5x)) =1

450 × 5 = x² + 5x

x² +5x -2250 = 0

x = (-5± √ (25+9000))/2

= (-5 ±√ (9025) )/2

= (-5 ± 95)/2

= -50, 45

But x ≠ -50 because speed cannot be negative

So, x = 45 km/h

Hence, original speed of train = 45 km/h

Q4Written answer

If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now?

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Worked solution

Let Zeba’s age = x

According to the question,

(x-5)²=11+5x

x²+25-10x=11+5x

x²-15x+14=0

x²-14x-x+14=0

x(x-14)-1(x-14)=0

x=1 or x=14

We have to neglect 1 as 5 years younger than 1 cannot happen.

Therefore, Zeba’s present age = 14 years.

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