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NCERT · Class 9 · Science

Chapter 11: Sound

Practice each question, then open the answer or worked solution.

Section 12.2.3

Textbook page 166 · 7 questions
Q1Written answer

Which wave property determines (a) loudness, (b) pitch?

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Worked solution

(a) Amplitude – The loudness of the sound and its amplitude is directly related to each other. The larger the amplitude, the louder the sound.

(b) Frequency – The pitch of the sound and its frequency is directly related to each other. If the pitch is high, then the frequency of sound is also high.

Q2Written answer

Guess which sound has a higher pitch: guitar or car horn?

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Worked solution

The pitch of a sound is directly proportional to its frequency. Therefore, the guitar has a higher pitch when compared to a car horn.

Q3Written answer

What are the wavelength, frequency, time period and amplitude of a sound wave?

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Worked solution

(a) Wavelength – Wavelength can be defined as the distance between two consecutive rarefactions or two consecutive compressions. The SI unit of wavelength is metre (m).

(b) Frequency – Frequency is defined as the number of oscillations per second. The SI unit of frequency is hertz (Hz).

(c) Amplitude – Amplitude can be defined as the maximum height reached by the trough or crest of a sound wave.

(d) Time period – The time period is defined as the time required to produce one complete cycle of a sound wave.

Q4Written answer

How are the wavelength and frequency of a sound wave related to its speed?

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Worked solution

Wavelength, speed, and frequency are related in the following way:

Speed = Wavelength x Frequency

v = λ ν

Q5Written answer

Calculate the wavelength of a sound wave whose frequency is 220 Hz and speed is 440 m/s in a given medium.

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Worked solution

Given that,

Frequency of sound wave = 220 Hz

Speed of sound wave = 440 m/s

Calculate wavelength.

We know that

Speed = Wavelength × Frequency

v = λ ν

440 = Wavelength × 220

Wavelength = 440/220

Wavelength = 2

Therefore, the wavelength of the sound wave = 2 metres

Q6Written answer

A person is listening to a tone of 500 Hz, sitting at a distance of 450 m from the source of the sound. What is the time interval between successive compressions from the source?

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Worked solution

The time interval between successive compressions from the source is equal to the time period, and the time period is reciprocal to the frequency. Therefore, it can be calculated as follows:

T= 1/F

T= 1/500

T = 0.002 s

Q7Written answer

Distinguish between loudness and intensity of sound.

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Worked solution

The amount of sound energy passing through an area every second is called the intensity of a sound wave. Loudness is defined by its amplitude.