Solve the following equations.
(a) 2y + (5/2) = (37/2)
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By transposing (5/2) from LHS to RHS, it becomes -5/2
Then,
= 2y = (37/2) – (5/2)
= 2y = (37-5)/2
= 2y = 32/2
Now,
Divide both sides by 2.
= 2y/2 = (32/2)/2
= y = (32/2) × (1/2)
= y = 32/4
= y = 8
(b) 5t + 28 = 10
By transposing 28 from LHS to RHS, it becomes -28
Then,
= 5t = 10 – 28
= 5t = – 18
Now,
Divide both sides by 5.
= 5t/5= -18/5
= t = -18/5
(c) (a/5) + 3 = 2
By transposing 3 from LHS to RHS, it becomes -3
Then,
= a/5 = 2 – 3
= a/5 = – 1
Now,
Multiply both sides by 5.
= (a/5) × 5= -1 × 5
= a = -5
(d) (q/4) + 7 = 5
By transposing 7 from LHS to RHS, it becomes -7
Then,
= q/4 = 5 – 7
= q/4 = – 2
Now,
Multiply both sides by 4.
= (q/4) × 4= -2 × 4
= a = -8
(e) (5/2) x = -5
First, we have to multiply both sides by 2.
= (5x/2) × 2 = – 5 × 2
= 5x = – 10
Now,
We have to divide both sides by 5.
Then, we get
= 5x/5 = -10/5
= x = -2
(f) (5/2) x = 25/4
First, we have to multiply both sides by 2.
= (5x/2) × 2 = (25/4) × 2
= 5x = (25/2)
Now,
We have to divide both sides by 5.
Then, we get
= 5x/5 = (25/2)/5
= x = (25/2) × (1/5)
= x = (5/2)
(g) 7m + (19/2) = 13
By transposing (19/2) from LHS to RHS, it becomes -19/2
Then,
= 7m = 13 – (19/2)
= 7m = (26 – 19)/2
= 7m = 7/2
Now,
Divide both sides by 7.
= 7m/7 = (7/2)/7
= m = (7/2) × (1/7)
= m = ½
(h) 6z + 10 = – 2
By transposing 10 from LHS to RHS, it becomes – 10
Then,
= 6z = -2 – 10
= 6z = – 12
Now,
Divide both sides by 6.
= 6z/6 = -12/6
= m = – 2
(i) (3/2) l = 2/3
First, we have to multiply both sides by 2.
= (3l/2) × 2 = (2/3) × 2
= 3l = (4/3)
Now,
We have to divide both sides by 3.
Then, we get
= 3l/3 = (4/3)/3
= l = (4/3) × (1/3)
= x = (4/9)
(j) (2b/3) – 5 = 3
By transposing -5 from LHS to RHS, it becomes 5
Then,
= 2b/3 = 3 + 5
= 2b/3 = 8
Now,
Multiply both sides by 3.
= (2b/3) × 3= 8 × 3
= 2b = 24
And,
Divide both sides by 2.
= 2b/2 = 24/2
= b = 12